Answer is 0.0024
Explanation
divide the length value by 1000.
Answer:
when u learn something new it goes to ur short term memory
Answer:
1) The volume of helium in the ballon when is fully inflated is 492.8070 m³
2) The magnitude of the force of gravity (with no people) is 869.3119 N
Explanation:
Given:
ρair = density of air = 1.28 kg/m³
ρhelium = density of helium = 0.18 kg/m³
R = radius of balloon = 4.9 m
mtotal = 121 kg
Vtotal = 0.073 m³
mp = average mass per person = 73 kg
Vp = 0.077 m³
g = gravity = 9.8 m/s²
Questions:
1) What is the volume of helium in the balloon when fully inflated, Vhelium = ?
2) What is the magnitude of the force of gravity on the entire system (but with no people), Fg = ?
1) The volume of helium in the ballon when is fully inflated
2) First, you need to calculate the mass of helium
The magnitude of the force of gravity (with no people)
Work = Force times Distance
Work = 200 x 30
Work = 6000
The work done by a force of 200N on a body that moved 30m is 6000J or 6000 Joules.
Answer:
U/U₀ = 2
(factor of 2 i.e U = 2U₀)
Therefore, the energy stored in the capacitor is doubled when the plate separation is doubled while the capacitor has been disconnected
Explanation:
Energy stored in a capacitor can be expressed as;
U = 0.5CV^2 = Q^2/2C
And
C = ε₀ A/d
Where
C = capacitance
V = potential difference
Q = charge
A = Area of plates
d = distance between plates
So
U = Q^2/2C = dQ^2/2ε₀ A
The initial energy of the capacitor at d = d₀ is
U₀ = Q^2/2C = d₀Q^2/2ε₀ A ....1
When the plate separation is increased after the capacitor has been disconnected, the charge Q of the capacitor remain constant.
The final energy stored in the capacitor at d = 2d₀ is
U = 2d₀Q^2/2ε₀ A ...2
The factor U/U₀ can be derived by substituting equation 1 and 2
U/U₀ = (2d₀Q^2/2ε₀ A)/( d₀Q^2/2ε₀ A )
Simplifying we have;
U/U₀ = 2
U = 2U₀
Therefore, the energy stored in the capacitor is doubled when the plate separation is doubled while the capacitor has been disconnected.
Answer:
10ms
Explanation:
The bird must travel the length of the train (150m), with a combined speed of 15m/s this means it will take 10s to cross an accumulated 150ms.
Answer:
The time taken by the parrot to cross the train is = 10 m/s
Explanation:
given:
A train of 150 m length is going toward north direction at a speed of 10 m/s
and a parrot is flying towards south direction parallel to the railway track with a speed of 5 m/s
find;
The time taken by the parrot to cross the train
using the distance over speed relation formula t = d / v
where:
v = velocity
d = distance
t = time
v = 10 m/s + 5 m/s = 15 m/s (combine velocity)
d = 150 m
t = ?
plugin values into the formula
t = 150
15
t = 10 m/s
therefore,
The time taken by the parrot to cross the train is = 10 m/s