Answer:
a) The fly is 2.24 m from the origin.
b) In polar coordinates, the position of the fly is (2.24 m, 26.7°).
Explanation:
Hi there!
The position vector of the fly is r = (2.00, 1.00)m. The distance from that point to the origin is the magnitude of the vector "r" (see figure).
a) Notice in the attached figure that the distance from the origin to the point where the fly is located is the hypotenuse of the triangle formed by r, the x-component of r (2.00 m) and the y-component ( 1.00 m). Then:
r² = (2.00 m)² + (1.00 m)²
r² = 5.00 m²
r = 2.24 m
The fly is 2.24 m from the origin.
b) To find the angle θ (see figure) we can use trigonometry:
cos θ = adjacent / hypotenuse
cos θ = 2.00 m / √5 m
θ = 26.7°
The same will be obtained if we use sin θ:
sin θ = opposite / hypotenuse
sin θ = 1.00 m / √5 m
θ = 26.7°
In polar coordinates, the position of the fly is (2.24 m, 26.7°).
The distance for both Parts A and B are given in the question.
A balloon drifts 140m toward the west in 45s.
The wind suddenly changes and the balloon flies 90m toward the east in the next 25s.
To find the total distance, we can just add.
140 + 90 = 230m
Best of Luck!
Answer:
Length
Time
Mass
Temperature
Energy
Direct Current (DC)
Frequency
Volume
Speed
Amount of substance
Luminous Intensity
Density
Concentration
Refractive Index
Work
Pressure
Power
Charge
Electric Potential
Entropy
b.) they only fish during the warmest times of the day
c. they must know the right time of year for Gathering certain foods
d.) they still catch walleye with the steering method
The Ojibwe people pay close attention to the seasons in order to know right
time of year for gathering certain foods.
The Ojibwe mostly hunt for fishes through the use of various techniques
such as:
They hunt for fishes at night because they are usually docile during that time
which enables them to catch them easily as against during the day when
they are much active.
Read more about Ojibwe people here brainly.com/question/24963033
Answer:C. They must know the right time of year for gathering certain foods
Explanation:
I got it correct
a. Find the electric potential energy of the original capacitor when it is charged. (in Joules)
b. Calculate the electric potential energy of the upgraded capacitor when it is charged. ( In Joules)
Answer:
a
b
Explanation:
From the question we are told that
The capacitance is
The voltage is
The first dielectric constant is
The second dielectric constant is
Generally the electric potential energy is mathematically represented as
=>
=>
Generally the capacitance when the capacitor's filling was changed is
=>
Generally the electric potential energy when the capacitor's filling was changed is
=>
=>
Answer:
3.06 seconds time passes before the watermelon has the same velocity
watermelon going at speed 59.9 m/s
watermelon traveling when it hits the ground at speed is 79.19 m/s
Explanation:
given data
height = 320 m
speed = 30 m/s
to find out
How much time passes before the watermelon has the same velocity and How fast is the watermelon going and How fast is the watermelon traveling
solution
we will use here equation of motion that is
v = u + at ....................1
here v is velocity 30 m/s and u is initial speed i.e zero and a is acceleration i.e 9.8 m/s²
put the value and find time t
30 = 0 + 9.8 (t)
t = 3.06 s
so 3.06 seconds time passes before the watermelon has the same velocity
and
we know superman cover distance is = velocity × time
so distance = 30 × t
and distance formula for watermelon is
distance = ut + 0.5×a×t² .............2
here u is initial speed i.e 0 and a is acceleration i.e 9.8 m/s² and h is 30 × t
30 × t = 0 + 0.5×9.8×t²
t = 6.12 s
so by equation 1
v = u + at
v = 0 + 9.8 ( 6.12)
v = 59.9 m/s
so watermelon going at speed 59.9 m/s
and
watermelon traveling speed formula is by equation of motion
v² - u² = 2as ......................3
here v is speed and u is initial speed i.e 0 and a is acceleration i.e 9.8 m/s² and s is distance i.e 320 m
v² - 0 = 2(9.8) 320
v = 79.19 m/s
so watermelon traveling when it hits the ground at speed is 79.19 m/s