Answers
Answer:
V= 57.5 V
Explanation:
- If the resistors are in the linear zone of operation, the potential difference across them, must obey Ohm's law:
- For the 6.0 Ω resistor, if the potential difference across it is 15 V, we can find the current flowing through it as follows:
- In a series circuit, the current is the same at any point of it, so the current through the battery is I = 2.5 A
- The equivalent resistance of a series circuit is just the sum of the resistances, so, in this case, we can write the following equation:
- Applying Ohm's Law to the equivalent resistance, we can find the potential difference through it, that must be equal to the potential difference across the battery, as follows:
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A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the railing with his outstretched arms. During the stopping process, his center of mass moves 30 cm toward the railing. (a) What is the change in the kinetic energy of his center of mass during this process? (b) What average force must he exert on the railing?
Electrons with energy of 25 eV have a wavelength of ~0.25 nm. If we send these electrons through the same two slits (d = 0.16 mm) we use to produce a visible light interference pattern what is the spacing (in micrometer) between maxima on a screen 3.3 m away?
Two identical small charged spheres are a certain distance apart, and each one initially experiences an electrostatic force of magnitude F due to the other. With time, charge gradually leaks off of both spheres. Calculate the magnitude of the electrostatic force, when each of the spheres has lost half of its initial charge. (Your answer will be a function of F, since no values are giving)
A quarterback claims that he can throw the football a horizontal distance of 167 m. Furthermore, he claims that he can do this by launching the ball at the relatively low angle of 33.1 ° above the horizontal. To evaluate this claim, determine the speed with which this quarterback must throw the ball. Assume that the ball is launched and caught at the same vertical level and that air resistance can be ignored. For comparison a baseball pitcher who can accurately throw a fastball at 45 m/s (100 mph) would be considered exceptional.
Answers
Answer:
kilogram
Explanation:
Answer:
SI base units of mass=KG
Answers
Answer:
People can hear sounds at frequencies from about 20 Hz to 20,000 Hz,
20 Hz up to 20,000 Hz
Brain pls
Answers
Answer:
Explanation:
On both sides of the film , the mediums have lower refractive index.
for interfering pattern from above , for constructive interference of reflected wave from both sides of the film , the condition is
2μt = ( 2n +1 ) λ / 2
μ is refractive index of film ,t is thickness of film λ is wavelength of light
n is order of fringe
for minimum thickness
n = 0
2μt = λ / 2
t = λ / 4μ
= 670 / 1.75 x 4
= 95.71 nm .
Answers
Answer:
x(t) = 20t + 12.75e⁻¹•⁶ᵗ + 487.5
t = 24.375 s
Explanation:
The force balance on the object is given as
Net force = W - Drag force
ma = W - 10v
a = (dv/dt)
ma = m(dv/dt) = 200 - 10v
W = mg
200 = m×32
m = 6.25 kg
m(dv/dt) = 200 - 10v
6.25(dv/dt) = 200 - 10v
(dv/dt) = 32 - 1.6v
v' + 1.6v = 32
Solving this differential equation using the integrating factor method
(ve¹•⁶ᵗ) = ∫ (32e¹•⁶ᵗ) dt
ve¹•⁶ᵗ = (20e¹•⁶ᵗ) + c (where c = constant of integration)
v = (20 + ce⁻¹•⁶ᵗ)
At t = 0, v = 0
0 = 20 + c
c = -20
v = (20 - 20e⁻¹•⁶ᵗ)
v = (dx/dt)
(dx/dt) = 20 - 20e⁻¹•⁶ᵗ
dx = (20 - 20e⁻¹•⁶ᵗ) dt
x(t) = 20t + 12.5e⁻¹•⁶ᵗ + c (c is still the constant of integration)
At t = 0, x = - 500
- 500 = 0 + 12.5 + c
c = 512.5
x(t) = 20t + 12.75e⁻¹•⁶ᵗ - 487.5
when the object hits the ground, x = 0
0 = 20t + 12.75e⁻¹•⁶ᵗ - 487.5
20t + 12.75e⁻¹•⁶ᵗ = 487.5
Solving by trial and error,
t = 24.375 s
Hope this Helps!!!
the internal energy of the cube increases by 47000 cal its temperature
increases by:
A
B
C
D
E
5 °C
10 °C
20 °C
100 °C
200 °C
Answers
The change in temperature of this cube of aluminum is equal to: B. 10°C
Given the following data:
- Edge length, L = 20 cm.
- Density of Aluminum = 2.7 g/cm
- Specific heat capacity (C) of aluminum = 0.217 Cal/g°С
- Internal energy = 47000 calories.
To find the change in temperature of this cube of aluminum:
First of all, we would determine the volume of this cube of aluminum.
Next, we calculate the mass of this cube of aluminum:
Mass = 21,600 grams.
Now, we can find the change in temperature of this cube of aluminum:
Mathematically, the quantity of heat energy is given by the formula;
Where:
- Q represents the quantity of heat energy.
- m represents the mass of an object.
- c is the specific heat capacity.
- ∅ is the change in temperature.
Substituting the parameters into the formula, we have;
Change in temperature = 10°C
Read more: brainly.com/question/18877825
Answer:
10 °C
Explanation:
From the question given above, the following data were obtained:
Egde length (L) of aluminum = 20 cm
Density of Aluminum = 2.7 g/cm³
Specific heat capacity (C) of aluminum = 0.217 cal/ g°С
Heat (Q) energy = 47000 cal
Change in Temperature (ΔT) =?
Next, we shall determine the volume of the aluminum. This can be obtained as follow:
Egde length (L) of aluminum = 20 cm
Volume (V) of aluminum =?
V = L³
V = 20³
V = 8000 cm³
Thus, the volume of the aluminum is 8000 cm³
Next, we shall determine the mass of the aluminum. This can be obtained as follow:
Density of Aluminum = 2.7 g/cm³
Volume of Aluminum = 8000 cm³
Mass of aluminum =.?
Density = mass/volume
2.7 = mass /8000
Cross multiply
Mass of aluminum = 2.7 × 8000
Mass of Aluminum = 21600 g
Finally, we shall determine the change in temperature of the aluminum as follow:
Specific heat capacity (C) of aluminum = 0.217 Cal/g°С
Heat (Q) energy = 47000 Cal
Mass (M) of Aluminum = 21600 g
Change in Temperature (ΔT) =?
Q = MCΔT
47000 = 21600 × 0.217 × ΔT
47000 = 4687.2 × ΔT
Divide both side by 4687.2
ΔT = 47000 / 4687.2
ΔT = 10 °C
Therefore, the increase in the temperature of the aluminum is 10 °C.
Answers
Answer:210000N
Explanation:
Pressure=3x10^5pa
area=0.7m^2
Force = pressure x area
Force=3x10^5x0.7
Force=210000N