Sheba is texting and driving. She does not see the baby chinchilasitting in the road! If she was traveling at 35 m/s, and at best her
car can accelerate at -3.5 m/p/s, how far would it take her to stop?

Answers

Answer 1
Answer:

Answer:

dfmwekognjioq 4eijqgi24gno3p2qtijoq2 gjo23ijgto32tneqew gqewkgnoweqgmnlqwe gwjoegkqwji4toqn34goti34

Explanation:


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State the following forms of electromagnetic radiation in increasing order of wavelength.Radiowaves, gamma rays, x-rays, infrared radiation, visible light​
A ship is traveling at 154 m/s and accelerates at a rate of 1.80 m/s^2 for 1 minute. What will its speed be after that minute? Calculate the answer in both meters per second and kilometers per hour.
Lightning can sometimes occur on hot and humid summer evenings when there are no thunderstorms.(A) True(B) False
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Find the net downward force on the tank's flat bottom, of area 1.60 m2 , exerted by the water and air inside the tank and the air outside the tank. Assume that the density of water is 1.00 g/cm3

Answers

Answer:

The net downward force on the tank is 1.85*10^(5)\ N

Explanation:

Given that,

Area = 1.60 m²

Suppose the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 150 K Pa , and the depth of the water will be 14.4 m . The pressure of the air in the building outside the tank will be 88.0 K Pa.

We need to calculate the net downward force on the tank

Using formula of formula

F=(P+\rho* g* h-P_(out))A

Where, P = pressure

g = gravity at mars

h = height

A = area

Put the value into the formula

F=(150*10^3+1.00*10^3*3.71*14.4-88.0*10^(3))*1.60

F=1.85*10^(5)\ N

Hence, The net downward force on the tank is 1.85*10^(5)\ N

Final answer:

The net downward force on the tank's flat bottom can be found by calculating the pressure at the bottom of the container.

Explanation:

Since the density is constant, the weight can be calculated using the density:

w = mg = pVg = pAhg.

The pressure at the bottom of the container is therefore equal to atmospheric pressure added to the weight of the fluid divided by the area.

Learn more about pressure calculation here:

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Seven seconds after a brilliant flash of lightning, thunder shakes the house. How far was the lightning strike from the house? Seven seconds after a brilliant flash of lightning, thunder shakes the house. How far was the lightning strike from the house? Much farther away than two kilometers Much closer than one kilometer About two kilometers away About one kilometer away It is impossible to predict.

Answers

Answer:

About two kilometers away

\rm distance=2.401\ km

Explanation:

Given:

The time gap between the light and sound to travel to the house, t=7\ s

Since the clouds are formed in the troposphere region of the atmosphere which extends from 8 kilometers to 12 kilometers above the earth-surface and the velocity of light is 300000 kilometers per second so it is visible almost instantly, hence we neglect the time taken by the light to travel to the house from the clouds.

∴Distance between the lightning-strike and the house:

\rm distance=v* t

we have the speed of sound as: v=343\ m.s^(-1)

So,

\rm distance=343* 7

\rm distance=2401\ m

\rm distance=2.401\ km

Information that is easily converted into numbers and is stored as a on and off signals is _____ information.

Answers

"Binary" information

find the area of a right triangle with sides 15.0 cm, 20.0 cm, and 25.0 cm. express your answer with the correct number of significant figures

Answers

The area of this triangle can be calculated using herons formula since th three sides are given. It is expressed as:

A=sqrt( s(s-a)(s-b)(s-c))

where s is equal to a+b+c / 2

s=15 +20 +25 /2=30
A=sqrt( 30(30-15)(30-20)(30-25))
A= 150 cm^3

A train travels due south at 20 m/s. It reverses its direction and travels due north at 20 m/s. What is the change in velocity of the train? 50 m/s, due south e50 m/s, due north 120 m/s, due south zero ms 40 m/s, due north

Answers

Answer:

40 m/s due north

Explanation:

Consider that the south direction a negative Y axis and north direction as  + Y axis

v1 = 20 m/s South = 20 (-j) m/s

v2 = 20 m/s North = 20 j m/s

Change in velocity = v2 - v1 = 20 j - 20 (-j) = 40 j m/s

So, change in velocity is 40 m/s due north.

If a pressure gauge measure an increase in 3×10^(5)Pa on an area of 0.7 m^2, calculate the increase in the force applied to the area?​

Answers

Answer:210000N

Explanation:

Pressure=3x10^5pa

area=0.7m^2

Force = pressure x area

Force=3x10^5x0.7

Force=210000N