The fundamental force that is responsible for beta decay is the: A) weak force. B) strong force. C) dark energy force. D) gravitational force E) electromagnetic force.

Answers

Answer 1

Answer:

Answer:

A. Weak forces

Explanation:

The fundamental forces responsible for beta decay is the weak force. Weak forces are among the four fundamental forces of universe the electromagnetic, gravitational and strong forces. The weak forces are responsible for the decaying. The fundamental work of weak forces is covert neutron into proton and electron into neutrino. weak forces operate at very low distances as low as fermi meter.

Answer 2

Answer:

Answer:

The answer is

dark energy force.

hope this helps u stay safe

Explanation:

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You're carrying a 3.6-m-long, 21 kg pole to a construction site when you decide to stop for a rest. You place one end of the pole on a fence post and hold the other end of the pole 35 cm from its tip. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. Part A Part complete How much force must you exert to keep the pole motionless in a horizontal position? Express your answer in newtons. F = 114 N Previous Answers

The tension of a string is found to be 4050 N and the mass of 1 m of the string is 0.5 kg. What could be the velocity of a wave traveling in that string?

Answers

Answer:

90 m/s

Explanation:

The formula for velocity of wave in a string is given as,

v' = √(T/m') ................ Equation 1

Where v' = velocity of the string, T = Tension on the string, m' = mass per unit length of the string.

Given: T = 4050 N, and

m' = m/l where m = mass of the string, l = length of the spring.

m = 0.5 kg, l = 1 m

m' = 0.5/1 = 0.5 kg/m

Substitute into equation 1

v' = √(4050/0.5)

v' = √(8100)

v' = 90 m/s.

Hence the velocity of the wave in the string = 90 m/s

An interstellar space probe is launched from Earth. After a brief period of acceleration it moves with a constant velocity, 70.0% of the speed of light. Its nuclear-powered batteries supply the energy to keep its data transmitter active continuously. The batteries have a lifetime of 15.9 years as measured in a rest frame. (a) How long do the batteries on the space probe last as measured by mission control on Earth? yr
(b) How far is the probe from Earth when its batteries fail, as measured by mission control?
ly
(c) How far is the probe from Earth, as measured by its built-in trip odometer; when its batteries fail?
ly

Answers

Answer:

22.26 years

, 15.585 light years , 11.13 light years

Explanation:

$t' = t/(√(1-(v/(c*v)/c))$

= $15.9/√((1-0.7*0.7))$

= 22.26 years

0.7*c*22.26 years

=15.585 light years

0.7*c*15.9

=11.13 light years

An object is floating in equilibrium on the surface of a liquid. The object is then removed and placed in another container, filled with a less dense liquid. What would you observe?

Answers

Answer:

The fraction of its volume inside liquid is increased .

Explanation:

According to principle pf floatation , an object floats on the surface of water

when the weight of liquid displaced by it becomes equal to weight of the object . weight of the liquid depends upon the density of the liquid .

In the second case , when the body is dipped into liquid of lesser density , in order to balance the weight of body , more volume of liquid will be displaced so that weight of displaced liquid becomes equal to object's weight . So the body floats with greater depth inside liquid . The fraction of its volume inside liquid is increased .

1. On a force vs. mass graph, what would be the slope of the line?2. On a Free Body Diagram, if the forces are all balanced, what do you know about the
object? Can it be moving?

Answers

1. By Newton's second law,

F = ma

so the slope of the line would represent the mass of the object.

2. If all the forces are balanced, then the object is in equilibrium with zero net force, which in turn means the object is not accelerating. So the object is either motionless or moving at a constant speed.

Final answer:

The slope on a Force vs. Mass graph represents acceleration. In a Free Body Diagram, if all the forces are balanced, the object could be either at rest or moving at a constant velocity.

Explanation:

1. On a Force vs. Mass graph, the slope of the line represents acceleration, according to Newton's second law of motion, which is force equals mass times acceleration (F=ma). The slope of the line is calculated as the change in force divided by the change in mass, which results in acceleration.

2. In a Free Body Diagram, if all the forces are balanced, it means the net force acting on the object is zero. This does not necessarily mean that the object is stationary. The object could be at rest, or it could be moving at a constant velocity. If an object is moving at a constant velocity, it is said to be in equilibrium because the forces are balanced.

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A softball player swings a bat, accelerating it from rest to 2.6 rev/srev/s in a time of 0.20 ss . Approximate the bat as a 0.90-kgkg uniform rod of length 0.95 mm, and compute the torque the player applies to one end of it.

Answers

Answer:

$\tau=22.13Nm$

Explanation:

information we have:

mass: $m=0.9kg$

lenght: $L=0.95m$

frequency: $f=2.6rev/s$

time: $t=0.2s$

and from the information we have we can calculate the angular velocity $\omega$ . which is defined as

$\omega=2\pi f$

$\omega=2\pi (2.6rev/s)\n\omega=16.336 rev/s$

----------------------------

Now, to calculate the torque

We use the formula

$\tau=I \alpha$

where $I$ is the moment of inertia and $\alpha$ is the angular acceleration

moment of inertia of a uniform rod about the end of it:

$I=(1)/(3)mL^2$

substituting known values:

$I=(1)/(3) (0.9kg)(0.95m)^2\nI=0.271kg/m^2$

for the torque we also need the acceleration $\alpha$ which is defined as:

$\alpha=(\omega)/(t)$

susbtituting known values:

$\alpha=(16.336rev/s)/(0.2s) \n\alpha=81.68rev/s^2$

and finally we substitute $I$ and $\alpha$ into the torque equation $\tau=I \alpha$ : $\tau=(0.271kg/m^2)(81.68rev(s^2)\n\tau=22.13Nm$

Final answer:

To calculate the torque, we need to use the formula: Torque = Moment of Inertia * Angular Acceleration. By approximating the bat as a uniform rod and using its length and mass, we can find the moment of inertia. Then, using the given angular velocity, we can calculate the angular acceleration. Finally, we can determine the torque by multiplying the moment of inertia by the angular acceleration.

Explanation:

To compute the torque the player applies to one end of the bat, we need to use the formula:

Torque = Moment of Inertia * Angular Acceleration

Given that the bat is approximated as a uniform rod and we know its length and mass, we can calculate the moment of inertia. Then, using the given angular velocity, we can compute the angular acceleration. Finally, we can find the torque by multiplying the moment of inertia by the angular acceleration.

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If the balloon takes 0.19 s to cross the 1.6-m-high window, from what height above the top of the window was it dropped?

Answers

Answer:

$heigth=2.86m$

Explanation:

Given data

time=0.19 s

distance=1.6 m

To find

height

Solution

First we need to find average velocity

$V_(avg)=(distance)/(time)\nV_(avg)=(1.6m)/(0.19s)\nV_(avg)=8.42m/s$

Also we know that average velocity

$V_(avg)=(V_(i)+V_(f))/2\n$

Where

Vi is top of window speed

Vf is bottom of window speed

Also we now that

$V_(f)=V_(i)+gt\nV_(f)=V_(i)+(9.8)(0.19)\nV_(f)=V_(i)+1.862$

Substitute value of Vf in average velocity

$V_(avg)=(V_(i)+V_(f))/2\nwhere\nV_(f)=V_(i)+1.862\nand\nV_(avg)=8.42m/s\nSo\n8.42m/s=(V_(i)+V_(i)+1.862)/2\n2V_(i)+1.862=16.84\nV_(i)=(16.84-1.862)/2\nV_(i)=7.489m/s\n$

Vi is speed of balloon at top of the window

Now we need to find time

$V_(i)=gt\nt=V_(i)/g\nt=7.489/9.8\nt=0.764s$

So the distance can be found as

$distance=(1/2)gt^(2)\n distance=(1/2)(9.8)(0.764)^(2)\n distance=2.86m$

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