When two point charges are a distance d part, the electric force that each one feels from the other has magnitude F. In order to make this force twice as strong, the distance would have to be changed toA) √2d
B) d/√2
C) d/4
D) 2d
E) d/2

Answers

Answer 1
Answer:

Answer:b

Explanation:

Given

Force of attraction is F when charges are d distance apart.

Electrostatic force is given by

F=(kq_1q_2)/(d^2)---1

where k=constant

q_1 and q_2 are charges

d=distance between them

In order to double the force i.e. 2F

2F=(kq_1q_2)/(d'^2)----2

divide 1 and 2 we get

(F)/(2F)=(d'^2)/(d^2)

d'=(d)/(√(2))


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A solid cylinder of cortical bone has a length of 500mm, diameter of 2cm and a Young’s Modulus of 17.4GPa. Determine the spring constant ‘k’. Please explain.

Answers

Answer:

The spring constant k is1.115* 10^(9) N/m

Solution:

As per the question:

Length of the solid cylinder, L = 500 mm = 500* 10^(- 3) = 0.5 m

Diameter pf the cylinder, D = 2 cm = 0.02 m

As the radius is half the diameter,

Radius, R = 1 cm = 0.01 m

Young's Modulus, E = 17.4 GPa = 17.4* 10^(9) Pa

Now,

The relation between spring constant, k and Young's modulus:

kL = EA

where

A = Area

Area of solid cylinder, A = 2\piR(L + R)

0.5k = 17.4* 10^(9)* 2\piR(L + R)

k = (17.4* 10^(9)* 2\pi* 0.01(0.01 + 0.5))/(0.5)

k = 1.115* 10^(9) N/m

Young's modulus, E is the ratio of stress and strain

And

Stress = (Force or thrust)/(Area)

Strain = (length, L)/(elongated or change in length, \Delta L)

Also

Force on a spring is - kL

Therefore, we utilized these relations in calculating the spring constant.

An indestructible bullet 2.00cm long is fired straight through a board that is 10.0cm thick. The bullet strikes the board with a speed of 470 m/s and emerges with a speed of 270 m/s. (To simplify, assume that the bullet accelerates only while the front tip is in contact with the wood.) a). What is the average acceleration of the bullet through the board? ________m/s^2b). What is the total time that the bullet is in contact with the board? (Enter the total time for the bullet to completely emerge from the board.) _________s
c.) What thickness of board (calculated 0.1 cm) would it take to stop the bullet, assuming that the acceleration through all boards is the same? ________cm

Answers

Answer:

a)a=-7.4* 10^(-5)\ m/s^2

b)t=0.27* 10^(-3)\ s

c)s=14.92 cm

Explanation:

 Given that

u= 470 m/s

v = 270 m/s

s= 10 cm

a)

We know that

v^2=u^2+2as

270^2=470^2+2* a* 0.1

a=-7.4* 10^(-5)\ m/s^2

b)

v= u + a t

270=470-7.4* 10^(-5)* t

t=0.27* 10^(-3)\ s

c)

To stop the bullet it means that the final velocity will be zero.

v^2=u^2+2as

0^2=470^2-2* 7.4* 10^(-5) * s

s=14.92 cm

As you go up the y-axis, what happens to the number of sprouted bean seeds?A. Sprouted bean seeds decrease.

B. Sprouted bean seeds increase.

C. Sprouted bean seeds remain constant.

D. None of the above

Answers

As we go up the y-axis, the number of sproutedbean seeds increase (option B).

What is a graph?

Graph is a data chart intended to illustrate the relationship between a set (or sets) of numbers (quantities, measurements or indicative numbers) and a reference set.

In a graph, there are two axes as follows;

  • Y-axis or vertical axis
  • X-axis or horizontal axis

According to this question, a graph of number of sprouted bean seeds on the y-axis is plotted against temperature on the x-axis.

We can observe that as we go up the y-axis, the number of sprouted bean seeds increase.

Learn more about graphs at: brainly.com/question/2938738

#SPJ1

What would the position of arrows on a target need to be to illustrate measurements that are neither accurate nor precise

Answers

Answer:

The position of the arrows will not be on the target i.e. outside the bull's eye, neither will they be close to one another (widely scattered).

Explanation:

Accuracy refers to the closeness of a measurement to an actual or accepted value while precision refers to the closeness of measurements to one another.

Using archery as an illustration of precision and accuracy, measurements (arrows) that are neither accurate not precise are those arrows that will be far away or outside the bull's eye region (target) of the board and also far apart from one another.

In a nutshell, the arrows will be distant from the bull's eye or target (not accurate) and also distant from one another (not precise).

A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine provides anet thrust of 0.795 N perpendicular tothe tethering wire.(a) Find the torque the net thrust producesabout the center of the circle.
N·m

(b) Find the angular acceleration of the airplane when it is inlevel flight.
rad/s2

(c) Find the linear acceleration of the airplane tangent to itsflight path.
m/s2

Answers

(a) 24.6 Nm

The torque produced by the net thrust about the center of the circle is given by:

\tau = F r

where

F is the magnitude of the thrust

r is the radius of the wire

Here we have

F = 0.795 N

r = 30.9 m

Therefore, the torque produced is

\tau = (0.795 N)(30.9 m)=24.6 N m

(b) 0.035 rad/s^2

The equivalent of Newton's second law for a rotational motion is

\tau = I \alpha

where

\tau is the torque

I is the moment of inertia

\alpha is the angular acceleration

If we consider the airplane as a point mass with mass m = 0.741 kg, then its moment of inertia is

I=mr^2 = (0.741 kg)(30.9 m)^2=707.5 kg m^2

And so we can solve the previous equation to find the angular acceleration:

\alpha = (\tau)/(I)=(24.6 Nm)/(707.5 kg m^2)=0.035 rad/s^2

(c) 1.08 m/s^2

The linear acceleration (tangential acceleration) in a rotational motion is given by

a=\alpha r

where in this problem we have

\alpha = 0.035 rad/s^2 is the angular acceleration

r = 30.9 m is the radius

Substituting the values, we find

a=(0.035 rad/s^2)(30.9 m)=1.08 m/s^2

If i throw up an object up at 31 m/s, how long will it take to get to its highest point

Answers

Answer:

Explanation:

vf=vi+at

vf=31 m/s

vi=0 m/s

a=g=9.8 m/s2

t=?

vf-vi=at

vf-vi/a=t

t=vf-vi/a

t=31 m/s-0/9.8

t=3.16 s