Answers
Answer:
first of all since the value of mass of the object and force F(horizontal) or the relation between them is not mentioned , so there can be multiple effects and let us study them in cases.
Let us consider that mass of the object is m and the coefficient of friction is the coefficient of static friction of the surface{since friction can be static as well as dynamic} whose value(μ) as is given in the question is 0.2. Since the surface and the force applied are both horizontal so there will be no vertical component of the force applied which means that the normal force is N=weight of the object=mg where g is the acceleration due to gravity(9.8 m/s^2 on average on surface of earth).
Case 1:
When F<=μN. This means that when the value of F is less than or equal to μN then the static friction is equal to F. So the body remains stationary.
Case 2:
When F>μN. This means that when the value of F is greater than μN then the static friction is less than F. So the body starts moving and if the force applied F is constant then the body will start accelerating because coefficient of kinetic friction is less than that of static friction.
Explanation:
When an object rests on a horizontal floor. the coefficient of static friction is 0.4 and the acceleration of gravity is 9.8m/s, then the maximum force of friction would be 1.962M and the minimum force of friction would be zero when no external force is applied, where M represents the mass of the object
What is friction?
Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.
When an object is beginning to move as a result of an external force, limiting friction is involved. This frictional force balances the external force until the object is in a condition where it remains stationary.
maximum Frictional force= μN
where μ is the coefficient of static friction
N is the normal reaction force having a value of mg
Thus, The maximum force of friction would be 1.962M, and the minimum force would be zero
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Related Questions
In college softball, the distance from the pitcher's mound to the batter is 43 feet. If the ball leaves the bat at 110 mph , how much time elapses between the hit and the ball reaching the pitcher?
Assume the following values: d1 = 0.880 m , d2 = 1.11 m , d3 = 0.560 m , d4 = 2.08 m , F1 = 510 N , F2 = 306 N , F3 = 501 N , F4 = 407 N , and MA = 1504 N⋅m . Express the Cartesian components of the resultant force and the couple moment in newtons and newton-meters to three significant figures separated by commas.
In general terms, the efficiency of a system can be thought of as the output per unit input. Which of the expressions is a good mathematical representation of efficiency e of any heat engine? Where, Qh: the absolute value (magnitude) of the heat absorbed from the hot reservoir during one cycle or during some time specified in the problem Qc: the absolute value (magnitude) of the heat delivered to the cold reservoir during one cycle or during some time specified in the problem W: the amount of work done by the engine during one cycle or during some time specified in the problem A) e=QhW B) e=QcQh C) e=QcW D) e=WQh E) e=WQc
A ball having a mass of 500 grams is dropped from a height of 9.00 meters what is its kinetic energy when it hits the ground
Answers
Answer
The Columb's law is the same as Gravitational law
Explanation
As we see the formula of both Coulomb and Gravitational Law,
(1)
(2)
The masses (M) in formula (1) experiencing the force of gravitational pull with each other which varies with changing the distance. In the formula (2), the charges also are felling the forces on each other which varies with distance. The charges and masses are just like the objects which are experiencing the forces which have a common factor as distance. The gravitational force is also called the mutual forces.
Answers
Answer:
The gravity at Equator is 9.780 m/s2 and the gravity at poles is 9.832 m/s2. The gravity at poles are bigger than at equator, principally because the Earth is not totally round. The gravity is inversely proportional to the square of the radius, that is the reason for the difference of gravity (The radius at Poles are smaller than at Equator).
If Earths would have a net charge Q. The Electric field of Earth would be inversely proportional to the square of the radius of Earth (Electric field definition for a charge), the same case as for gravity. So there would be a difference between the electric field at poles and equator, too.
Answers
The reflected beam experienced a phase change of about 180°.
What is reflection in the glass surface?
According to Snell's law, the light that incident on the glass surface will be reflected and transmitted at an angle equals to the angle of incidence.
By the observation of refractive index of the glass for the normal incidence only 4% of the light is transmitted or reflected.
The light passing through glass is not only reflected on the front surface, but also on the back. For several times the light will gets reflected back and forth. So, the total reflectance through a glass window can be calculated as
2·R / (1+R).
Thus, A light wave travelling in air is reflected by a glass barrier will undergo a phase change of 180°, while light travelling in glass will not undergo a phase change if it is reflected by a boundary with air.
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Answer:
180 degree phase change
Explanation:
( a= ? m/s2 )
Calculate the proton's speed after 1.40 {\rm \mu s} in the field, assuming it starts from rest.
( V= ? m/s )"
Answers
To solve this problem we will start from the definition of Force, as the product between the electric field and the proton charge. Once the force is found, it will be possible to apply Newton's second law, and find the proton acceleration, knowing its mass. Finally, through the linear motion kinematic equation we will find the speed of the proton.
PART A ) For the electrostatic force we have that is equal to
Here
q= Charge
E = Electric Force
PART B) Rearrange the expression F=ma for the acceleration
Here,
a = Acceleration
F = Force
m = Mass
Replacing,
PART C) Acceleration can be described as the speed change in an instant of time,
There is not then
Rearranging to find the velocity,
Final answer:
The magnitude of the electric force felt by the proton is 4.4 x 10^-16 N. The proton's acceleration is 2.64 x 10^11 m/s^2. The proton's speed after 1.40 μs in the field is 3.70 x 10^5 m/s.
Explanation:
The charge of a proton is 1.6 x 10-19 coulombs and the electric field strength is 2750 N/C. Therefore, the magnitude of the electric force felt by the proton is (1.6 x 10-19 C)(2750 N/C) = 4.4 x 10-16 N. The mass of a proton is approximately 1.67 x 10-27 kilograms. Therefore, the proton's acceleration is (4.4 x 10-16 N)/(1.67 x 10-27 kg) = 2.64 x 1011 m/s2. Since the proton starts from rest, its initial velocity (u) is 0. Therefore, the proton's speed after 1.40 μs is v = (2.64 x 1011 m/s2)(1.40 x 10-6 s) = 3.70 x 105 m/s.
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Answers
Answer:
10.4⁰ and 169.6⁰
Explanation:
The force experienced by the moving electron in the magnetic field is expressed as F = qvBsinθ where;
q is the charge on the electron
v is the velocity of the electron
B is the magnetic field strength
θ is the angle that the velocity of the electron make with the magnetic field.
Given parameters
F = 1.40*10⁻¹⁶ N
q = 1.6*10⁻¹⁹C
v = 3.94*10³m/s
B = 1.23T
Required
Angle that the velocity of the electron make with the magnetic field
Substituting the given parameters into the formula:
1.40*10⁻¹⁶ = 1.6*10⁻¹⁹ * 3.94*10³ * 1.23 * sinθ
1.40*10⁻¹⁶ = 7.75392 * 10⁻¹⁹⁺³sinθ
1.40*10⁻¹⁶ = 7.75392 * 10⁻¹⁶sinθ
sinθ = 1.40*10⁻¹⁶/7.75392 * 10⁻¹⁶
sinθ = 1.40/7.75392
sinθ = 0.1806
θ = sin⁻¹0.1806
θ₁ = 10.4⁰
Since sinθ is positive in the 1st and 2nd quadrant, θ₂ = 180-θ₁
θ₂ = 180-10.4
θ₂ = 169.6⁰
Hence, the angle that the velocity of the electron make with the magnetic field are 10.4⁰ and 169.6⁰
Answers
Answer:
2.72 m
Explanation:
wavelength of sound λ = velocity / frequency
= 340 / 1200
= .2833 m
Distance of point of first constructive interference
= λ D / d ( D is distance of the screen and d is distance between source of sound.
Here D = 12.5 m
d = 1.3 m
λ D / d= ( .2833 x 12.5) / 1.3
= 2.72 m
Distance of point of first constructive interference = 2.72 m
Final answer:
The wavelength of the produced sound is approximately 0.29 m. Constructive interference occurs when the path difference between the two waves is a multiple of this wavelength, allowing you to calculate the distance between the central maximum and first maximum loud position.
Explanation:
For part (a) of the question, we need to calculate the wavelength of the sound wave. The wave speed (v) is given by the multiplication of frequency (f) and wavelength (λ). The speed of sound in air is approximately 343 m/s and given that the frequency produced by the function generator is 1200 Hz, the wavelength can be calculated using the formula λ = v / f = 343 / 1200 ≈ 0.29 m.
For part (b) the distance between the central maximum (loud) position and the first maximum along this line requires understanding of sound wave interference and constructive interference. For constructive interference to occur, the path difference between the two waves needs to be a multiple of the wavelength. Thus, in the first constructive interference position (first maximum loud position), the path difference equals one wavelength (0.29m). Since the student is walking 12.5 m away and parallel to the line between the speakers (which is the hypotenuse of a right triangle stakeout, with one side being 0.65m), we can use Pythagorean theorem to find out the distance.
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