Answer:
It's impossible for an ideal heat engine to have non-zero power.
Explanation:
Option A is incomplete and so it's possible.
Option B is possible
Option D is related to the first lae and has nothing to do with the second law.
Hence, the correct option is C.
The ideal engine follows a reversible cycle albeit an infinitely slow one. If the work is being done at this infinitely slow rate, the power of such an engine is zero.
We can also stat the second law of thermodynamics in this manner;
It is impossible to construct a cyclical heat engine whose sole effect is the continuous transfer of heat energy from a colder object to a hotter one.
This statement is known as second form or Clausius statement of the second law.
Thus, it is possible to construct a machine in which a heat flow from a colder to a hotter object is accompanied by another process, such as work input.
According to the second law of thermodynamics, it is impossible for heat energy to flow from a colder body to a hotter body, for an ideal heat engine to have an efficiency of 99%, and for a physical process to yield more energy than what is put in.
According to the second law of thermodynamics, it is impossible for heat energy to flow from a colder body to a hotter body. This is because heat naturally flows from a region of higher temperature to a region of lower temperature. This principle is what allows us to effectively use heat for various purposes, such as in heat engines.
An ideal heat engine is a theoretical construct used to study the efficiency of engines. The second law of thermodynamics states that no heat engine can have an efficiency of 100%, so it is impossible for an ideal heat engine to have an efficiency of 99%. This is due to the losses in heat transfer and other thermodynamic processes.
The second law of thermodynamics also implies that in any physical process, the total energy cannot increase. It is impossible for a physical process to yield more energy than what is put in. This principle is central to understanding energy conservation and the limitations of energy conversion.
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Answer:
6.2 seconds
Explanation:
Using Newton's second law, ∑F=ma, we know the net force acting on the object is Force applied-Force of friction. The net force is 203 N. Newton's second law requires the mass of an object, not the weight force, so we will have to calculate the mass. We know that m*g=weight force, in this case, solve for the mass and you will get 210 kg. Now that we have the value of the net force and the mass, we can solve for acceleration. =0.967 m/s^2. Now, since we have the acceleration, initial velocity(0 m/s), and the final velocity (6m/s) we will use these to solve for time using the kinematic equation Vf=Vi + at. Plug in the values we know and solve for time and you will get 6.2 seconds
b) +9.8 m/s^2 throughout
c) -9.8 m/s^2 throughout
d) zero throughout
e) +9.8 m/s^2, then momentarily zero, then -9.8 m/s^2
The block's kinetic energy is closest to 1500 Joules.
The energy is always conserved.
So that, the total kinetic energy will be sum of initial potential energy and kinetic energy during falling.
Given that, mass(m)=10kg, v=10m/s, h=10m,g=10m/s^2
K.E=(1/2)mv^2 + mgh
K.E=(1/2)*10*100 + (10*10*10)
K.E=500 + 1000=1500Joule
The block's kinetic energy is closest to 1500 Joules.
Learn more about the kinetic energy here:
Answer:
Kinetic energy = 1500 J
Explanation:
The computation of the block's kinetic energy is shown below:
As we know that
Conservation of energy is
PE_i + KE_i = PE_f + KE_f
where,
Initial Potential energy = PE_i = m gh = 10kg× 10m/s^2 × 10m = 1000 J
Initial Kinetic energy = KE_i = (0.5) m V^2 = (0.5) (10 kg) (10 m/s)^2 = 500 J
Final potential energy = PE_f = mgh = 0
As h = 0 which is at reference line
So
PE_i + KE_i = PE_f + KE_f
Now put these valeus to the above formulas
1000 J + 500 J = 0 + KE_f
After solving this
Kinetic energy = 1500 J
Measure the circumference of the tire before and after riding.
B.
Measure the total distance traveled on his bike and divide this by how long it took him.
C.
Measure the wear on his treads before and after riding a certain number of laps.
D.
Time how long it takes him to ride 5 laps around his cul-de-sac.
Answer:
C.
Measure the wear on his treads before and after riding a certain number of laps.
Answer:
Measure the wear on his treads before and after riding a certain number of laps.
Explanation:
By riding in a circular motion the inside of the tire will be in contact with the road more than the outside of the tire. Thus, to see if the constant circular motion had any effect on his tires David should measure the tread depth on both the inside and the outside of the tires before the experiment and measure the inside and the outside of the tires (at the same location on the tires) after the experiment. Then he can compare the tread loss on the inside of the tire to the tread loss on the outside of the tire.
Answer:
After passing through the glass plate, the red light disperses and meets at point.
The convex lens has two refracting surfaces, and convex kens is called as converging lens. So, at the exact center of the lens, one observes a Dark spot.
Thus, the correct option is a) one observes a dark spot.
Answer:
The answer is: A) a darkspot
Explanation:
When the red light passes through the glass plate, it is scattered. the convex lens (convergent lens) has two refractive surfaces, therefore, in the center of the lens, a characteristic dark spot would be observed.
Answer:
(c) 3P/5
Explanation:
The formula to calculate the power is:
where
W is the work done
T is the time required for the work to be done
In the second part of the problem, we have
Work done: 3W
Time interval: 5T
So the power required is