Identify two ions that have the following ground-state electron configurations Part B
[Ar]3d^5
Check all that apply.
A- Fe2+
B- Fe3+
C- Mn2+
D- V+
E- Sc2+

Answers

Answer 1
Answer:

Answer: Fe^(2+):24:[Ar]3d^5

Mn^(2+):23:[Ar]3d^5

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.  The electrons are filled according to Afbau's rule in order of increasing energies.

The electronic configuration for given elements is as follows:

Fe:26:[Ar]3d^64s^2

Fe^(2+):24:[Ar]3d^5

Fe^(3+):23:[Ar]3d^4

Mn:25:[Ar]3d^54s^2

Mn^(2+):23:[Ar]3d^5

V:23:[Ar]3d^34s^2

V^+:22:[Ar]3d^34s^1

Sc:21:[Ar]3d^14s^2

Sc^(2+):19:[Ar]3d^1

Answer 2
Answer:

Final answer:

The ions Fe2+ and Mn2+ have the ground-state electron configuration [Ar]3d^5.

Explanation:

The ground-state electron configuration [Ar]3d^5 indicates a level of electrons in 3d subshell after the Argon core electron configuration. Now, iron (Fe) has a base atomic configuration of [Ar]3d^6 4s2. When it loses 2 electrons (to form Fe2+), it tends to lose from both the 3d and the 4s sublevels, giving [Ar]3d^5 (which is our required configuration).

However, it's also important to consider Manganese (Mn), which has a base configuration of [Ar]3d^5 4s2. It usually loses 2 electrons from the 4s sublevel first when it forms Mn2+ which results in a configuration [Ar]3d^5.

So, the two ions with the electron configuration [Ar]3d^5 are Fe2+ and Mn2+.

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Answers

Answer:

              Structure is attached.

Explanation:

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What is the mass of silver that can be prepared from 1.50 g of copper metal? Cu(s)+2AgNO3(aq)→Cu(NO3)2(aq)+2Ag(s)

Answers

The mass of silver that can be prepared from 1.50 g of copper metal is 5.10 g.

To find the mass of silver that can be prepared from 1.50 g of copper metal, we need to use stoichiometry and the balanced chemical equation.

From the equation, we can see that 1 mole of copper reacts with 2 moles of silver to produce 1 mole of copper(II) nitrate and 2 moles of silver.

We can use the molar masses of copper and silver to convert grams to moles, and then use the mole ratio to find the moles of silver. Finally, we can convert moles of silver back to grams using the molar mass of silver.

Step 1: Convert grams of copper to moles of copper. (1.50 g Cu) / (63.55 g/mol Cu) = 0.0236 mol Cu

Step 2: Use the mole ratio of silver to copper from the chemical equation. (0.0236 mol Cu) × (2 mol Ag / 1 mol Cu) = 0.0473 mol Ag

Step 3: Convert moles of silver to grams of silver. (0.0473 mol Ag) × (107.87 g/mol Ag) = 5.10 g Ag

Molar mass:

Ag = 107.86 g/mol
Cu = 63.54 g/mol

Mole ratio:

Cu(s)+2 AgNO₃(aq)→Cu(NO₃)₂(aq)+2 Ag(s)

63.54 g Cu ------------- 2 x 107.86 g Ag
1.50 g Cu -------------- ??

Mass Ag = 1.50 x 2 x 107.86 / 63.54

Mass Ag = 32358 / 63.54

= 509.25 g of Ag

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Calculate the mass percent of oxygen in KMnO4.

Answers

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Are the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl4) the same in both compounds?

Answers

Taking into account the definition of ionic and covalent bond, the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl₄) are different in both compounds.

Ionic bond

An ionic bond is a type of chemical bond that occurs when one atom gives up an electron to the other, in order for both to achieve electronic stability.

This union normally occurs between metal and nonmetal elements with different electronegativity, which means that the elements have different capacity to attract electrons.

In other words, an ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

Covalent bond

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas.

Bonds of NaCl and CCl₄

In the case of NaCl, Na is a metal while Cl is a nonmetal. So NaCl is an ionic bond.

On the other hand, in the case of CCl₄ both C and Cl are two non-metallic elements. So CCl₄ is a covalent bond.

In summary, the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl₄) are different in both compounds.

Learn more about

ionic bond:

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covalent bond:

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Answer:

No, NaCl is formed by an ionic bond, and CCl4 would be formed by covalent bonds.

Explanation:

NaCl is an ionic bond because of their opposite charges while carbon and chlorine are sharing their electrons making it a covalent bond.