Answer:
C. three
Explanation:
A lithium atom must lose one valence electron to achieve a full valence shell, resulting in a positively charged lithium cation (Lit) with a noble gas configuration similar to helium.
To achieve a full valence shell, a lithium atom must lose one electron. Lithium has an atomic number of 3, which means it has three electrons: two in the first shell and one in the second shell. Since the first shell (1s) is already full with two electrons, lithium has a single electron in the 2s subshell of the second shell. This single electron is the valence electron.
According to the Lewis diagram, lithium (Li) has only one valence electron in its second shell. By transferring this lone electron to another atom, lithium's electron configuration will resemble that of helium (He), with two electrons in its first shell, thus achieving a stable noble gas configuration. This transfer results in the formation of a lithium cation, denoted as Lit, with a charge of 1+.
It is important to note that when lithium becomes a cation, it does not necessarily mean it has a complete valence shell in terms of helium or neon. Instead, it has achieved stability by having a full inner shell, which mimics the noble gas configuration of helium.
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© Dorling Kindersley / Universal Images Group / Image Quest 2016
What does the red line indicate?
A. A cold front is moving to the north and east.
B. A cold front is moving to the south and west.
C. A warm front is moving to the north and east.
D. A warm front is moving to the south and west.
Answer: It's D. A warm front is moving to the south and west.
Explanation: I got it right on the test
the specific heat of the resulting Nacl solutions is 4.06j/gc
calculate the heat of neutralisation of hcl and naoh in kj/mol nacl products
Answer:
62.12kJ/mol
Explanation:
The neutralization reaction of HCl and NaOH is:
HCl + NaOH → NaCl + H₂O + HEAT
You can find the released heat of the reaction and heat of neutralization (Released heat per mole of reaction) using the formula:
Q = C×m×ΔT
Where Q is heat, C specific heat of the solution (4.06J/gºC), m its mass and ΔT change in temperature (27.5ºC-20.0ºC = 7.5ºC).
The mass of the solution can be finded with the volume of the solution (50.0mL of HCl solution + 50.0mL of NaOH solution = 100.0mL) and its density (1.02g/mL), thus:
100.0mL × (1.02g / mL) = 102g of solution.
Replacing, heat produced in the reaction was:
Q = C×m×ΔT
Q = 4.06J/gºC×102g×7.5ºC
Q = 3106J = 3.106kJ of heat are released.
There are 50.0mL ×1M = 50.0mmoles = 0.0500 moles of HCl and NaOH that are reacting releasing 3.106kJ of heat. That means heat of neutralization is:
3.106kJ / 0.0500mol of reaction =
Answer:
An Exothermic Reaction , gives off more heat, and a little energy to its surroundings.
this can helps us figure out that the answer is , C, More heat is given off into its products.
Explanation:
Answer:
1.7 × 10⁴ J
Explanation:
Step 1: Calculate the heat required to raise the temperature of ice from -15 °C to 0°C
We will use the following expression.
Q₁ = c(ice) × m × ΔT
Q₁ = 2.03 J/g.°C × 25 g × [0°C - (-15°C)] = 7.6 × 10² J
Step 2: Calculate the heat required to melt 25 g of ice
We will use the following expression.
Q₂ = C(fusion) × m
Q₂ = 80. cal/g × 25 g × 4.184 J/1 cal = 8.4 × 10³ J
Step 3: Calculate the heat required to raise the temperature of water from 0°C to 75 °C
We will use the following expression.
Q₃ = c(water) × m × ΔT
Q₃ = 4.184 J/g.°C × 25 g × (75°C - 0°C) = 7.8 × 10³ J
Step 4: Calculate the total heat required
Q = Q₁ + Q₂ + Q₃
Q = 7.6 × 10² J + 8.4 × 10³ J + 7.8 × 10³ J = 1.7 × 10⁴ J
Scientific data related to the ecosystem and the effect of environmental changes.
Political action by governments and other organizations such as environmental
protection groups.
Economic issues such as cost of wood products, fuel for heat, price of electricity, and
income levels of local people.
Answer:
ALL of these are factors in conservation.
Explanation:
Fe2+, cr4+, cl-, O2-
Answer:
{eq}Fe^{2+} {/eq} and {eq}I^- {/eq} forms {eq}FeI_2 {/eq}
{eq}Fe^{2+} {/eq} and {eq}S^{2-} {/eq} forms {eq}FeS {/eq}
{eq}Cr^{4+} {/eq} and...
Explanation:
Empirical formula:
The empirical formula gives the simple ratio of the different types of atoms in a compound. It is different from the molecular formula, which gives the exact number of each type of atom in a compound.
In basic chemistry, an empirical formula represents the simplest ratio of atoms in a compound. For example, the empirical formula for a compound formed by Fe2+ (Iron II) and O2- (Oxide) would be FeO. In this question, a compound composed of all these ions (Fe2+, Cr4+, Cl-, O2-) is unusual and there's insufficient information to determine a reasonable structure.
The question is asking for an empirical formula, which is a formula that gives the simplest whole number ratio of atoms of each element in a compound. The formula you're asked to provide involves the ions Fe2+ (Iron II), Cr4+ (Chromium IV), Cl- (Chloride), and O2- (Oxide).
Creating an empirical formula is a matter of balancing out the charges in order to get a neutral compound. For instance, if you wanted to combine Fe2+ and O2-, the empirical formula would be FeO because one Fe2+ ion would balance out one O2- ion to make an electrically neutral compound.
It's important to remember that the charge value of the ion helps you determine the necessary ratio to achieve neutrality. In essence, we need the amount of positive charge to equal the amount of negative charge in the empirical formula.
For a compound involving all these ions, unfortunately, it's not common or reasonable to have a compound with four different ions. Iron, chromium, and oxygen are transition metals that could form complex ions, but we do not have enough information in this question to determine the structure.
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