The transamination of a-ketoglutarate leads to the formation of this amino acid A. Aspartate B. Glutamate C. Asparagine D. Glutamine E. Valine

Answers

Answer 1

Answer:

Answer:

B. Glutamate

Explanation:

Transamination is a chemical reaction which involves the transfer of an amino group to a ketoacid to form new amino acids.

In biochemistry, transamination is accomplished by the enzymes known as transaminases / aminotransferases.

The example of transanimation is the conversion of α-ketoglutarate to glumate amino acid. α-ketoglutarate in body acts as a predominant acceptor of amino-group and produces glutamate on transanimation as a new amino acid.

It accepts the amino group transferred from the amino acid.

Aminoacid + α-ketoglutarate ↔ α-keto acid + Glutamate

Related Questions

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Molecular compounds result from covalent bonding which are called _______.This is for high school physical science
What is the mass of 0.73 moles of AgNO3?
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Calculate the molar solubility of Cd(OH)2 when buffered at a pH = 12.30. The Ksp for Cd(OH)2 is 2.5 x 10-14. Calculate the molar solubility of Cd(OH)2 when buffered at a pH = 12.30. The Ksp for Cd(OH)2 is a.2.5 x 10-14 M. b. 8.5 x 10-6 M c. 6.3 x 10-11 M d. 1.3 x 10-12 M e. 5.0 x 10-2 M f. 1.8 x 10-5 M

A solution contains 0.10 M Pb2+ and 0.10 M Cu2.. Which cation will precipitate first when a solution of NazS is slowly added to the mixture? Refer to the information sheet for solubility constants. P A) Pb2+ B) Cu2+ C) impossible to tell D) both cations

Answers

Answer:

b) Cu2+

Explanation:

information sheet for solubility constants:

Ksp PbS = 3.4 E-28

Ksp CuS = 6.0 E-37

PbS ↔ Pb2+ + S2-

∴ Ksp = 3.4 E-28 = [ Pb2+ ] * [ S2- ]

∴ [ Pb2+ ] = 0.10 M

⇒ [ S2- ] = 3.4 E-28 / 0.10 = 3.4 E-27 M

CuS ↔ Cu2+ + S2-

∴ Ksp = 6.0 E-37 = [ Cu2+ ] * [ S2- ]

∴ [ Cu2+ ] = 0.10 M

⇒ [ S2- ] = 6.0 E-37 / 0.10 = 6.0 E-36 M

we have:

(1) [ S2- ] PbS >> [ S2- ] CuS

(2) Ksp PbS >> Ksp CuS

from (1) and (2) it can determined, that separation can be carried out and also the cation that precipitates first is the Cu2+

Metal vapor deposition is a process used to deposit a very thin layer of metal on a target substrate. A researcher puts a glass slide in the metal vapor deposition chamber and coats the slide with copper. After deposition, the glass slide had increased in mass by 2.26 milligrams. Approximately how many copper atoms were deposited on the glass slide

Answers

Answer:

2.14x10¹⁹ atoms of Cu were deposited

Explanation:

The increased in mass of the glass slide is due the deposition of copper.

That means the mass of copper deposited is 2.26mg = 2.26x10⁻³g Cu

To know the copper atoms we need to convert this mass to moles of Cu using molar mass of copper (63.546g/mol), and these moles are converted to atoms using Avogadro's number (6.022x10²³ atoms = 1 mole)

Moles Cu:

2.26x10⁻³g Cu * (1 mol / 63.546g) = 3.556x10⁻⁵ moles Cu

Atoms Cu:

3.556x10⁻⁵ moles Cu * (6.022x10²³ atoms / 1 mole) =

2.14x10¹⁹ atoms of Cu were deposited

The element oxygen has valence electrons

Answers

Answer:

it’s electron configuration is 1s^2 2s^2 2p^4. To determine valence electrons, add the outermost s and p orbitals. In an oxygen atom, 8 electrons are present. Electron present in the first shell (n=1) 2n^2=2 (1)^2=2 (1)=2.

A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature changes from 5° C to 30° C? (Neglect the expansion of the beaker, evaporation of alcohol and absorption of water vapor by alcohol.) The volume coefficient of expansion γγ for alcohol = 1.12 x 10-4 K-1

Answers

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

$v_0=500$
$\alpha =1.12* 10^(-4)$
$\Delta \epsilon = 25$

Now,

Increase in volume will be:

⇒ $\Delta V = \alpha* v_0* \Delta \epsilon$

By putting the given values, we get

$=1.12* 10^(-4)* 500* 25$

$=1.12* 10^(-4)* 12500$

$=1.4 \ mL$

A substance that cannot be chemically broken down into simpler substances is a an electron. b a heterogeneous mixture. c an element. d a homogeneous mixture. e a compound.

Answers

Answer:

c. an element.

Explanation:

An element -

It refers to the substance , which has same type of atoms , with exactly same number of protons , is referred to as an element .

In term of chemical species , elements are the smallest one , and can not be bifurcated down to any further small substance by the means of any chemical reaction .

Hence , from the given information of the question ,

The correct term is an element .

Answer:

C. an element.

Explanation:

5.0 liters of a gas are at an initial pressure of 5.0 atmospheres. If the temperature and amount of a gas are kept constant, what is the new volume of the gas when pressure is increased to 7.0 atmospheres?

Answers

Final answer:

Using Boyle's Law of gases which states that the pressure and volume of a gas have an inverse relationship when temperature is kept constant, we find that when the pressure of the gas increases from 5.0 to 7.0 atmospheres, the volume of the gas decreases to approximately 3.57 liters.

Explanation:

The question pertains to the application of Boyle's Law, a fundamental concept in the field of physics dealing with gases. Boyle's Law states that the pressure and volume of a gas have an inverse relationship when the temperature is held constant. This means if the pressure of a gas increases, the volume decreases, and vice versa.

In this case, you have 5.0 liters of a gas under an initial pressure of 5.0 atmospheres. The pressure is then increased to 7.0 atmospheres, and you are asked to determine the new volume of the gas. To solve this problem, we use the formula for Boyle's Law, which is P1V1 = P2V2. We know P1 (initial pressure) is 5.0 atmospheres and V1 (initial volume) is 5.0 liters. P2 (final pressure) is increased to 7.0 atmospheres and V2 (final volume) is what we are trying to find.

So, we plug the numbers into the equation and get: 5.0 atmospheres * 5.0 liters = 7.0 atmospheres * V2. Solving for V2, we find V2 to be approximately 3.57 liters. Therefore, when the pressure of the gas is increased from 5.0 atmospheres to 7.0 atmospheres, the volume decreases to around 3.57 liters, while the temperature remains constant.

Learn more about Boyle's Law here:

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