CHEMISTRY COLLEGE

What is the value for the kinetic energyfor a n = 2 Bohr orbit electron in Joules?

Answers

Answer 1

Answer:

Answer:

K.E. = 5.4362 × 10⁻¹⁹ J

Explanation:

The expression for Bohr velocity is:

$v=(Ze^2)/(2 \epsilon_0* n* h)$

Applying values for hydrogen atom,

Z = 1

Mass of the electron ( $m_e$ ) is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

$\epsilon_0$ = 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

$v=\frac {2.185* 10^6}{n}\ m/s$

Given, n = 2

So,

$v=\frac {2.185* 10^6}{2}\ m/s$

$v=1.0925* 10^6\ m/s$

Kinetic energy is:

$K.E.=\frac {1}{2}* mv^2$

So,

$K.E.=\frac {1}{2}* 9.1093* 10^(-31)* ({1.0925* 10^6})^2$

K.E. = 5.4362 × 10⁻¹⁹ J

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Joan has four containers. The chart below shows the mass and volume of each of the containers. Two of the containers are filled with solids, one is filled with a liquid, and one is filled with a gas.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, it should be noted that if the containers are compared with an equal average volume, the containers having solids will have larger masses than that containing liquid which will also have a larger mass than that containing gas. This is because solids have there molecules touching each other in compact manner which makes the molecule exert a certain combined force/mass. The molecules of liquid are also close to one another but are not compact like the solids and are hence exerting a lesser force/mass than solids. Gases have free molecules that are far apart and thus are usually the lightest when they occupy the same volume as liquids and solids.

Is my answer right? How many millilitres of 1.33 mol L−1 H2SO4(aq) are required to completely neutralize 49.3 mL of 0.830 mol L−1 KOH(aq) ?

I got 15.4 once and now I got 61.4? Are they correct? if so, which one?

Answers

Final answer:

To neutralize the KOH solution, we need 61.4 mL of 1.33 mol L−1 H2SO4(aq).

Explanation:

To find the volume of the H2SO4 solution needed to neutralize the KOH solution, we can use the equation:

Mole of H2SO4 = Molarity of KOH x Volume of KOH

First, calculate the moles of KOH:
Moles of KOH = Molarity of KOH x Volume of KOH = 0.830 mol/L x (49.3 mL / 1000 mL) = 0.04089 mol

Since H2SO4 is a diprotic acid and KOH is a strong base, the reaction will be:
H2SO4 + 2 KOH -> K2SO4 + 2 H2O

Therefore, the ratio between the moles of H2SO4 and KOH is 1:2. This means that twice the moles of KOH will be needed to neutralize the H2SO4. Calculate the moles of H2SO4 needed:
Moles of H2SO4 needed = 2 x Moles of KOH

= 2 x 0.04089 mol

= 0.08178 mol

Finally, calculate the volume of the H2SO4 solution needed:
Volume of H2SO4 = Moles of H2SO4 / Molarity of H2SO4 = 0.08178 mol / 1.33 mol/L

= 0.0614 L

= 61.4 mL

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What is the net ionic equation for the reaction that occurs when aqueous solutions of naoh and hno3 are mixed?

Answers

Answer:-

H+ + OH- --> H2O

Explanation:-

The chemical equation is NaOH + HNO3 --> NaNO3 + H2O

Now for the ionic compounds

HNO3 --> H+ + NO3 -

NaOH--> Na+ + OH-

NaNO3 --> Na+ + NO3-

Water being covalent will remain as H2O,

Hence

HNO3 + NaOH--> NaNO3 + H2O

H+ + NO3 - + Na+ + OH- --> Na+ + No3 - + H2O.

Crossing out common terms

H+ + OH- --> H2O

Determine the rate of a reaction that follows the rate law:rate = k[A]”[B]", where:
k= 1.5
[A] = 1 M
[B] = 3 M
m = 2
n = 1

Answers

The rate of the reaction is 4.5 mol L⁻¹s⁻¹.

What is meant by rate of a reaction ?

Rate of a reaction is defined as the change in concentration of any one of the reactants or products of the reaction, in unit time.

Here,

The concentration of A, [A] = 1 M

The concentration of B, [B] = 3 M

The partial order with respect to A, m = 2

The partial order with respect to B, n = 1

The rate constant of the reaction, k = 1.5

The rate of the reaction,

r = k[A]^m [B}^n

r = 1.5 x 1² x 3

r = 4.5 mol L⁻¹s⁻¹

Hence,

The rate of the reaction is 4.5 mol L⁻¹s⁻¹.

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Answer:

k= 1.5

[A] = 1 M

[B] = 3 M

m = 2

n = 1

Explanation:

rate = k[A]”[B]"

In a 66.0-g aqueous solution of methanol, CH4O, the mole fraction of methanol is 0.290. What is the mass of each component? g

Answers

Answer:

23.84g CH30H

32.81g H2O

Explanation:

We will be using the definition of mole fraction to determine the relationship between the number of moles of methanol,

CH3OH , and the number of moles of water.

But mole fraction gives the ratio between the number of moles of a component i of a solution to the total number of moles present in that solution.

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

Final answer:

In a 66.0g aqueous solution of methanol with a mole fraction of 0.290, the mass of the methanol is approximately 19.14g and the mass of the water is approximately 46.86g.

Explanation:

In this aqueous solution of methanol (CH4O), we know that its mass is 66.0g and the mole fraction of methanol is 0.290. The mole fraction is defined as the ratio of the number of moles of a component to the total number of moles of all components in the solution.

In order to find the mass of each component, namely the methanol and the water, we first need to establish that if the mole fraction of methanol is 0.290, the mole fraction of water must be 0.710 (because the total of all mole fractions in a solution is always equal to 1).

We then can set up the following proportion: mass of methanol/mass of water = mole fraction of methanol/mole fraction of water. After solving this equation, the mass of methanol will be approximately 19.14g and the mass of the water will be approximately 46.86g.

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Which letter indicates the asthenosphere

Answers

Answer:

Explanation:

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In a 74.0-g aqueous solution of methanol, CH4O, the mole fraction of methanol is 0.140. What is the mass of each component?