What else is produced during the replacement reaction of silver nitrate and potassium sulfate? 2AgNO3 + K2SO4 Ag2SO4 + ________

Answer:

The Correct answer is C

Explanation:

The sequence of three bases which codes for a specified amino acid.

Answer:

Which best describes a codon? 1. a cell structure that gives the master instructions for an organism 2. a segment of DNA that is the basis of heredity in organisms 3. the sequence of three bases that codes for a specific amino acid 4. the basic unit of structure and function of all living things

Answer: correct option is the option B= 2.6 × 10^-5 mol.sec^-1

Explanation:

Check attached file/picture for the plot of graph of reaction velocity against substrate concentration.

Initial velocity can be defined as the velocity at the beginning of an enzyme-catalyzed reaction. It is usually denoted as V°.

In the equation of reaction below;

A + B----------> [AB] ------------>Product

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Where the forward reaction is k1 that is the rection producing the intermediate [AB].

And, the backward reaction is k-1 that is the arrow pointing back to the Reactants.

K2 is the arrow from the intermediate [AB] to the products.

Note that k1 and k-1

represent rapid non-covalent dissociation of substrate from enzyme active site. Also, K2 is the rate constant for the formation of the products.

In order to calculate the initial velocity,V° we need to use the Michaelis- Menteen equation.

V° = Vmax ×(S)/ Km + (S)-------------------------------------------------------------(1).

From the question the parameters given are;

Vmax = 6.5 x 10–5 mol•sec–1 , [S] = 3.0 x 10–3 M, and KM = 4.5 x 10–3 M.

Therefore, slotting in the above parameters into the equation (1) above, we have;

V° = 6.5 x 10–5 mol•sec–1 × 3.0 x 10–3 M / 4.5 x 10–3 M + 3.0 x 10–3 M.

Initial velocity,V° = 2.6 x 10-5 moles per sec..

Answer: 0.522cm3

Explanation:

Mass = 11.2g

Density = 21.45 g/cm3

Volume =?

Volume = Mass /Density

Volume = 11.2 / 21.45

Volume = 0.522cm3

Explanation:

Law of conservation of mass states that mass can neither be created nor it can be destroyed but it can be transformed into one form to another.

Similarly, law of conservation of energy states that energy can neither be created nor it can be destroyed as it can only be transformed from one form to another.

In modern view of matter and energy, is the law of mass conservation still relevant to chemical reactions as follows.

For example,

Atomic mass of Na = 23

Atomic mass of Cl = 35

Hence, mass of total number of reactants is calculated as follows.

             [(2 \times 23) + (35 \times 2)] g/mol = 116 g/mol

Mass of total number of products is calculated as follows.

             [2 \times (23 + 35)] = 116 g/mol

Thus, it is proved that in our modern view of matter and energy, is the law of mass conservation still relevant to chemical reactions.

Answer:

Moles of hydrogen formed = 3.5 moles

Explanation:

Given that:-

Moles of aluminium= 4.0 mol

Moles of hydrogen bromide = 7.0 mol

According to the reaction:-

2 moles of aluminum react with 6 moles of hydrogen bromide

1 mole of aluminum react with 6/2 moles of hydrogen bromide

4 moles of aluminum react with (6/2)*4 moles of hydrogen bromide

Moles of hydrogen bromide = 12 moles

Available moles of hydrogen bromide = 7.0 moles

Limiting reagent is the one which is present in small amount. Thus, hydrogen bromide is limiting reagent. (7.0 < 12)

The formation of the product is governed by the limiting reagent. So,

6 moles of hydrogen bromide on reaction forms 3 moles of hydrogen

1 moles of hydrogen bromide on reaction forms 3/6 moles of hydrogen

7 moles of hydrogen bromide on reaction forms (3/6)*7 moles of hydrogen

Moles of hydrogen formed = 3.5 moles

Answer:

3.5 mol H2, HBr (limiting reactant)

Explanation:

4.0 mol Al × 3 mol H2/ 2 mol Al = 6.0 mol H2

7.0 mol HB ×3 mol H2/ 6mol HBr = 3.5 mol H2

Since 7.0mol of HBr will produce less H2 than 4.0mol of Al, HBr will be the limiting reactant, and the reaction will produce 3.5mol of H2.

Final answer:

To neutralize the KOH solution, we need 61.4 mL of 1.33 mol L−1 H2SO4(aq).

Explanation:

To find the volume of the H2SO4 solution needed to neutralize the KOH solution, we can use the equation:

Mole of H2SO4 = Molarity of KOH x Volume of KOH

First, calculate the moles of KOH:
Moles of KOH = Molarity of KOH x Volume of KOH = 0.830 mol/L x (49.3 mL / 1000 mL) = 0.04089 mol

Since H2SO4 is a diprotic acid and KOH is a strong base, the reaction will be:
H2SO4 + 2 KOH -> K2SO4 + 2 H2O

Therefore, the ratio between the moles of H2SO4 and KOH is 1:2. This means that twice the moles of KOH will be needed to neutralize the H2SO4. Calculate the moles of H2SO4 needed:
Moles of H2SO4 needed = 2 x Moles of KOH

= 2 x 0.04089 mol

= 0.08178 mol

Finally, calculate the volume of the H2SO4 solution needed:
Volume of H2SO4 = Moles of H2SO4 / Molarity of H2SO4 = 0.08178 mol / 1.33 mol/L

= 0.0614 L

= 61.4 mL

Learn more about Neutralization here:

brainly.com/question/32025930

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