CHEMISTRY COLLEGE

100.0 g of liquid copper (molar mass 63.546 g/mol; melting point 1358 K; density 8.02 g/mL) is placed in a rigid container of volume 10.0 L at temperature 1508 K. The container is placed in an evacuated chamber and a small hole of area 3.23 mm2 is made in the upper container wall. After 2.00 hours, the mass of copper in the container has decreased by 1 0.0168 g. Assuming the mass loss is due to effusion, calculate the vapor pressure of liquid copper at 1508 K. Hint: because the liquid constantly evaporates, the pressure inside the container is constant

Answers

Answer 1

Answer:

8.912x10^-18

Explanation:

-dn/dt = pANa/2piMRT

100 g = initial copper

Number of moles = 100/63.546

= 1.5736

Mass of copper left = 100-10.0168

= 89.9832

Moles = 89.9832/63.546

= 1.4160

dn = 1.4160-1.5736

= -0.1576

dt = 2 hrs

A = 3.23mm² = 3.23x10^-6

M = 63.546

T = 0.0821

T = 1508k

Na = 6.023x10²³

When we insert all these into the formula above

We get

P = 8.912x10^-18atm

Related Questions

This is a pretty hard question. can someone help out?Correctly match the following vocabulary words with their definitions:1. _____. the phase change of a substance from the solid state directly to the gaseous state; for example, dry ice, moth balls, or solid air freshener2. _____. a form of energy transferred (by way of conduction, convection, or radiation) by virtue of a difference in temperature; heat is energy in transit; heat is energy flow, measured in energy units3. _____. matter with definite volume and definite shape4. _____. theory in physics based on the fact that particles of matter are in vigorous motion and that the temperature of a substance increases with an increase in either the average kinetic energy of the particles or the average potential energy of separation of the particles, or in both, when heat is added5. _____. a measure of how hot or cold something is; a measure of the average kinetic energy of the particles of a substance6. _____. matter with no definite volume or shape7. _____. the process by which a gas changes phase directly to a solid; for example, the formation of frost8. _____. a gaslike state of matter consisting of positively charged ions, free electrons, and neutral particles; found in stars, the sun, solar wind, lightning, and fire; unlike gases, plasmas are good conductors of electrical currents9. _____. net absorption of energy10. _____. the transfer of heat through matter by way of the collision of molecules11. _____. heat; energy transferred due to temperature differential that becomes associated with potential energy and kinetic energy on a molecular level12. _____. the process by which water vapor changes from gas to liquid13. _____. in a closed system in changing from one form to another, matter and energy cannot be created or destroyed; in this sense, conservation means that the physical quantity of matter and energy is entirely preserved during transformations and reactions14. _____. physical form of matter, such as solid, liquid, and gas; a distinct state of matter in a system; matter that is identical in chemical composition and physical state, and is separated from other material by the phase boundary; for example, the reaction occurs in the liquid phase of the system15. _____. the process by which water changes to water vapor16. _____. net release of energy17. _____. SI-derived unit to measure energy, work, and quantity of heat; for work, a joule is the amount of work done by a force of 1 N acting through 1 m; also newton-meter18. _____. matter with definite volume but no definite shape.WORDS.1. condensation2. conduction3. conservation4. depostion5. endothermic6. evaporation7. exothermic8. gas9. heat10. joule11. kinetic theory12. liquid13. phase14. plasma15. solid16. sublimation17. temperature18. thermal energy
What is the partial pressure of nitrogen in a container that contains 3.96mol of oxygen, 7.49 mol of nitrogen and 1.19 mol of carbon dioxide when the total pressure is 563 mmHg?
A super slow snail can travel 2.2cm in one minute. How far (in pm) can it travel in 24 hours? Please round to appropriate number of significant figures, and show required steps used to reach your answer.
The genetic code from DNA is carried into the cytoplasm by____
The following data is given to you about a reaction you are studying: Overall reaction: 2A  D Proposed mechanism: Step 1 A + B  C (slow) Step 2 C + A  D + B (fast) [A]o = 0.500 M [B]o = 0.0500 M [C]o = 0.500 M [D]o = 1.50 M This reaction was run at a series of temperatures and it was found that a plot of ln(k) vs 1/T (K) gives a straight line with a slope of -982.7 and a Y intercept of -0.0726. What is the initial rate of the reaction at 298K?

True or False: Observations are just things that you see

Answers

Answer:

False

Explanation:

"Observations is the action of observing something or someone carefully or in order to gain information" - google dictionary. This definition does not completely match the definition given, so the answer is false.

I hope this helps!

Answer: true

Explanation: the action or process of observing something or someone carefully or in order to gain information that is the real definition

2 SO2 (g) + O2 (g) 2 SO3 (g)If the TEMPERATURE on the equilibrium system is suddenly increased :The value of Kc A. IncreasesB. DecreasesC. Remains the sameThe value of Qc A. Is greater than KcB. Is equal to KcC. Is less than KcThe reaction must: A. Run in the forward direction to restablish equilibrium.B. Run in the reverse direction to restablish equilibrium.C. Remain the same. Already at equilibrium.The concentration of O2 will: A. Increase.B. Decrease.C. Remain the same.

Answers

Answer:

Part one: B. Kc decreases

Part two: B. Is equal to Kc

Part three: B. Run in the reverse direction to reestablish equilibrium

Part four: A. Increase

Explanation:

Part one: Sulfur dioxide combines with oxygen to form sulphur trioxide in an exothermic reaction. If the temperature is suddenly is increased, while the reaction is at equilibrium, the backward reaction (the endothermic one) is favored to "sweep up the excess heat". An increase in reactants means a decrease in Kc since the denominator(reactants) is becoming bigger while the numerator (products) become smaller.

Part two: Qc is a varying version of Kc. For this set of circumstances, it will be equal to Kc since Kc varies with temperature

Part three: The reaction must run in the reverse to reestablish the equilibrium.

Part four: The concentration of of oxygen will increase as more of the reactants are formed

Final answer:

The increase in temperature for this exothermic reaction will cause the value of Kc to decrease, the value of Qc to be greater than Kc, the reaction to run in the reverse direction, and the concentration of O2 to increase.

Explanation:

The given chemical reaction represents a type of equilibrium reaction, specifically an exothermic reaction, as it produces sulfur trioxide (SO3), which releases heat. According to Le Chatelier's principle, to maintain equilibrium, if a system is disturbed by an external factor, the system will adjust accordingly.

Here are my answers to the specific questions:

When the temperature is increased in an exothermic reaction, the system tries to consume the excess heat by moving in the endothermic direction, which is the reverse reaction in this case. Therefore, the value of Kc decreases (B).
Since the equilibrium has been disturbed, the value of Qc will not be equal to Kc. Considering more products are formed, Qc will be greater than Kc (A).
As a response to the increase in temperature, to re-establish equilibrium, the reaction will run in the reverse direction (B).
As the reaction goes in reverse to establish a new equilibrium, the concentration of reactants increases. Thus, the concentration of O2 will increase (A).

Learn more about Chemical Equilibrium here:

brainly.com/question/3920294

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A piston confines 0.200 mol Ne(g) in 1.20 at 25 degree C. Two experiments are performed. (a) The gas is allowed to expand through an additional 1.20 L against a constant of 1.00atm. (b) The gas is allowed to expand reversibly and isothermally to the same final volume. Please calculate the work done by the gas system in these two processes, respectively. Which process does more work? (revised from 6/e exercise 8.11) Please show calculation details.

Answers

Answer:

The second experiment (reversible path) does more work

Explanation:

Step 1:

A piston confines 0.200 mol Ne(g) in 1.20L at 25 degree °C

(a) The gas is allowed to expand through an additional 1.20 L against a constant of 1.00atm

Irreversible path: w =-Pex*ΔV

⇒ with Pex = 1.00 atm

⇒ with ΔV = 1.20 L

W = -(1.00 atm) * 1.20 L

W = -1.20L*atm *101.325 J /1 L*atm = -121.59 J

(b) The gas is allowed to expand reversibly and isothermally to the same final volume.

W = -nRTln(Vfinal/Vinitial)

⇒ with n = the number of moles = 0.200

⇒ with R = gas constant = 8.3145 J/K*mol

⇒ with T = 298 Kelvin

⇒ with Vfinal/Vinitial = 2.40/1.20 = 2

W = -(0.200mol) * 8.3145 J/K*mol *298K *ln(2.4/1.2)

W = -343.5 J

The second experiment (reversible path) does more work

What is colloidal solutions

Answers

Explanation:

Colloidal solutions, or colloidal suspensions, are nothing but a mixture in which the substances are regularly suspended in a fluid. ... Colloidal systems can occur in any of the three key states of matter gas, liquid or solid. However, a colloidal solution usually refers to a liquid concoction.

Answer:

Colloidal solutions, or colloidal suspensions, are nothing but a mixture in which the substances are regularly suspended in a fluid.

The osmotic pressure, π, of a solution of glucose is 132 atm . find the molarity of the solution at 298 k.

Answers

The formula for osmotic pressure is:

$\Pi = iMRT$

where $\Pi$ is osmotic pressure, $i$ is van't Hoff's factor, $M$ molarity, $R$ is Ideal gas constant, and T is Temperature.

$\Pi$ = 132 atm

The van't Hoff's factor for glucose, $i$ = 1

$R = 0.08206 Latmmol^(-1)K^(-1)$

$T = 298 K$

Substituting the values in the above equation we get,

$132 atm = 1* M* 0.08206 Latmmol^(-1)K^(-1)* 298$

$M = (132 atm)/(1* 0.08206 Latmmol^(-1)K^(-1)* 298) = 5.4797 molL^(-1) \simeq 5.48 molL^(-1)$

So, the molarity of the solution is $5.48 molL^(-1)$ .

A student dissolves 12.g of sucrose C12H22O11 in 300.mL of a solvent with a density of 1.01/gmL . The student notices that the volume of the solvent does not change when the sucrose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits. molarity = molality =

Answers

Answer:

Molarity → 0.17 M

Molality → 0.11 m

Explanation:

The student notices that the volume of the solvent does not change when the sucrose dissolves in it; therefore we assume the volume of solvent as solution.

Molarity = Mol of solute/L

Let's calculate the mol of solute (mass / molar mass)

12 g / 342 g/mol = 0.0351 moles

Let's conver the volume (mL) to L

300 mL / 1000 = 0.3 L

Molarity (mol/L) = 0.0351 mol / 0.3L → 0.17 M

Molality = mol of solute / 1kg of solvent.

Let's find out the mass of solvent with the density

Solvent density = Solvent mass / Solvent volume

1.01 g/mL = Solvent mass / 300 mL

1.01 g/mL . 300 mL = Solvent mass →303 g

Let's convert the mass to kg