Answer:
General Characteristics of Acids:
Sour taste (though you should never use this characteristic to identify an acid in the lab) Reacts with a metal to form hydrogen gas. Increases the H+ concentration in water. Donates H+ ions. Turns blue litmus indicator red.
8
6
2
Answer:
8
Explanation:
7 is neutral any anything above it is basic and anything below is acidic which means 8 would be the lowest base
Answer:
The pH of a weak base falls somewhere between 7 and 10.
Explanation:
Like weak acids, weak bases do not undergo complete dissociation; instead, their ionization is a two-way reaction with a definite equilibrium point
How many moles of CO 2 are produced when 5.95 mol of ethane is burned in an excess of oxygen?
CO₂ produced : 11.92 moles
Reaction
2C₂H₆ (g)+7O₂ (g) ⇒4CO₂ (g)+6H₂O(g)
mol ratio C₂H₆ : CO₂ = 2 : 4
moles of CO₂ :
Answer :
(i) The value of equilibrium constants for this reaction is, 10
(ii) The value of equilibrium constants for this reaction is, 0.1
Explanation :
The given equilibrium reaction is,
Now we have to determine the equilibrium constants for the following equilibrium reactions.
(i)
From the given reaction we conclude that, the reaction (i) will takes place when the given main reaction will be multiplied by half (1/2). That means when reaction will be half then the equilibrium constant will be:
The value of equilibrium constants for this reaction is, 10
(ii)
From the given reaction we conclude that, the reaction (ii) will takes place when the reaction (i) will be reverse. That means when reaction will be reverse then the equilibrium constant will be:
The value of equilibrium constants for this reaction is, 0.1
Answer:
enantiomeric excess = 68%
Explanation:
Enantiomeric excess is a value used to determine the purity of chiral molecules. It is possible to determine enantiomeric excess (ee) using:
ee = R - S / R + S * 100
Where R is the mass (In this case percentage) of the R enantiomer and S of the S enantiomer.
Replacing with values of the problem:
ee = 84% - 16% / 84% + 16% * 100
The enantiomeric excess of the mixture, defined as the difference between the concentrations of the R and S enantiomers, is 68.0%.
The enantiomeric excess (ee) is defined as the absolute difference between the mole percentage of the major enantiomer and the minor enantiomer in a mixture. In a sample that contains 84.0 % of the R enantiomer and 16.0 % of the S enantiomer, the enantiomeric excess is calculated as follows:
Therefore, the enantiomeric excess of the mixture is 68.0%.
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Answer:
In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.
Explanation: