b. Intermolecular forces become weaker
c. Intermolecular forces do not change
d. Energy increases
Engshus
ratoway
As the speed of the particles decreases, intermolecular forces become stronger. Thus, the correct option for this question is A.
The intermolecular forces may be defined as the forces of attraction. that is present between atoms, molecules, and ions when they are placed close to each other in order to form a compound or element. This force is continuously acting on the neighboring particles of different molecules.
It is found that at low temperature, when the speed of molecules/particles decrease, they migrate closer to one another that results in their intermolecular forces that become stronger as compared to the initial one.
As the attraction between molecules gradually increases, their movement decreases, and undergo fewer collisions between them.
Therefore, as the speed of the particles decreases, intermolecular forces become stronger. Thus, the correct option for this question is A.
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Answer:
B
Explanation:
Answer:
2Ag⁺ (aq) + CrO₄⁻² (aq) ⇄ Ag₂CrO₄ (s) ↓
Ksp = [2s]² . [s] → 4s³
Explanation:
Ag₂CrO₄ → 2Ag⁺ + CrO₄⁻²
Chromate silver is a ionic salt that can be dissociated. When we have a mixture of both ions, we can produce the salt which is a precipitated.
2Ag⁺ (aq) + CrO₄⁻² (aq) ⇄ Ag₂CrO₄ (s) ↓ Ksp
That's the expression for the precipitation equilibrium.
To determine the solubility product expression, we work with the Ksp
Ag₂CrO₄ (s) ⇄ 2Ag⁺ (aq) + CrO₄⁻² (aq) Ksp
2 s s
Look the stoichiometry is 1:2, between the salt and the silver.
Ksp = [2s]² . [s] → 4s³
The density of the element in grams per cubic centimeter can be rewritten in kilograms per cubic meter as 11,300 kg/m³
Given the parameter:
The density of an element is 11.3 g/cm³
To convert the density from grams per cubic centimeter to kilograms per cubic meter, we can use the following conversion factors:
1 gram = 0.001 kilograms
1 cm³ = 1000000m³
Density in kg/m³ = Density in g/cm³ × (0.001 kg/g) × ( 1000000 m³/cm³)
Density in kg/m³ = 1000
Now, given the density of the element as 11.3 g/cm³:
Density in kg/m³ = 11.3 × 1000
Density in kg/m³ = 11,300 kg/m³
Therefore, the density of the element is approximately 11,300 kg/m³.
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Answer:
11.3 g/cm³ = 11.3x100x100x100/ 1000 = 11300kg/m³
Explanation:
In this case, the problem is asking for the balance of a redox reaction in acidic media, in which nickel is reduced to a metallic way and nitrogen oxidized to an ionic way.
Thus, according to the given information, it turns out possible for us to balance this equation in acidic solution by firstly setting up the half reactions:
Next, we cross multiply each half-reaction by the other's carried electrons:
Finally, we add them together to obtain:
Which can be all simplified by a factor of 2 to obtain:
Hence, the coefficients in front of Ni and H⁺ are 4 and 10 respectively.
Learn more:
When a student mixes 5.00 g of NH4NO3 with 50.0 mL of water in a coffee-cup calorimeter, the temperature of the resultant solution decreases from 22.0 °C to 16.5 °C. Assume the density of water is 1.00 g/ml and the specific heat capacity of the resultant solution is 4.18 J/g·°C.
1) Calculate q for the reaction. You must show your work.
2) Calculate the number of moles of NH4NO3(s) which reacted. You must show your work.
3) Calculate ΔH for the reaction in kJ/mol. You must show your work.
Answer:
Explanation:
NH₄NO₃ = NH₄⁺ +NO₃⁻
heat released by water = msΔ T
m is mass , s is specific heat and ΔT is fall in temperature
= 50 x 4.18 x ( 22 - 16.5 ) ( mass of 50 mL is 50 g )
= 1149.5 J .
This heat will be absorbed by the reaction above .
q for the reaction = + 1149.5 J
2 )
molecular weight of NH₄NO₃ = 80
No of moles reacted = 5/80 = 1 / 16 moles.
3 )
5 g absorbs 1149.5 J
80 g absorbs 1149.5 x 16 J
= 18392 J
= 18.392 kJ.
= + 18.392 kJ
ΔH = 18.392 kJ / mol
The density of the cylinder would be 3.652 gram/ cm³
.
It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
As given in the problem, you just measured a metal cylinder and obtained the following information: mass - 3.543 grams, diameter 0.53 cm, height = 4.40 cm , and we have to calculate the density of the cylinder,
mass of the cylinder = 3.543 grams
the volume of the cylinder = πr²h
= 3.14 ×.265²×4.4
=0.97 cm³
By using the above formula for density
ρ = mass of the cylinder/volume of the cylinder
= 3.543 grams/0.97 cm³
=3.652 grams/ cm³
Thus,the density of the cylinder would be 3.652 grams/ cm³.
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Answer:
V cylinder =
note that
density =