Which is more water soluble hexanoic acid or sodium hexanoate?

Answers

Answer 1

Answer:

Answer:

Explanation:

Hexanoic acid [CH 3(CH 2) 4COOH] is barely soluble in water (about 1.0 g/100 g of water). Palmitic acid [CH 3(CH 2) 14COOH], with its large nonpolar hydrocarbon component, is essentially insoluble in water. The carboxylic acids generally are soluble in such organic solvents as ethanol, toluene, and diethyl ether.

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Which one of the following compounds will NOT be soluble in water? Which one of the following compounds will NOT be soluble in water? LiOH BaSO4 NaNO3 MgCl2 K2S

Answers

Answer:

$BaSO_(4)$ will be not soluble in water

Explanation:

LiOH is a strong base. Hence it gets completely dissociated in aqueous solution.

$NaNO_(3)$ is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

$MgCl_(2)$ is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

$K_(2)S$ is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

$BaSO_(4)$ is a sparingly soluble salt. Hence it is not dissociated and hence dissolved in water. This is due to the fact that both $Ba^(2+)$ and $SO_(4)^(2-)$ ions are similar in size. Hence crystal structure of $BaSO_(4)$ is quite stable. Hence $BaSO_(4)$ is reluctant to undergo any dissociation in aqueous solution.

You wish to prepare 100 mL of a 0.100 M solution by dilution of a 1.00 M solution. Which of the following pieces of glassware will you use? A. 100 mL graduated cylinder
B. 100 mL volumetric flask
C. 10 mL volumetric pipet
D. 25 mL volumetric pipet
E. 10 mL graduated pipet
F. 25 mL graduated pipet

Answers

Answer:

Explanation:

The volumetric pipet is designed for a specific volume of solution. In this case, a 10 mL of volumetric pipet is required to take exactly 10 mL of the solution 1.00 M and add into a volumetric flask of 100 mL. Then water or solvent(s) can be added to reach the ring of the volumetric flask. This volumetric flask is also a laboratory equipment for precis dilutions beside the volumetric pipet

Find the initial velocity for an enzymatic reaction when Vmax = 6.5 x 10–5 mol•sec–1 , [S] = 3.0 x 10–3 M, and KM = 4.5 x 10–3 M. A) not enough information is given to make this calculation B) 2.6 x 10–5 mol•sec–1 C) 1.4 x 10–2 mol•sec–1 D) 8.7 x 10–3 mol•sec–1 E) 3.9 x 10–5 mol•sec–1

Answers

Answer: correct option is the option B= 2.6 × 10^-5 mol.sec^-1

Explanation:

Check attached file/picture for the plot of graph of reaction velocity against substrate concentration.

Initial velocity can be defined as the velocity at the beginning of an enzyme-catalyzed reaction. It is usually denoted as V°.

In the equation of reaction below;

A + B----------> [AB] ------------>Product

<--------

Where the forward reaction is k1 that is the rection producing the intermediate [AB].

And, the backward reaction is k-1 that is the arrow pointing back to the Reactants.

K2 is the arrow from the intermediate [AB] to the products.

Note that k1 and k-1

represent rapid non-covalent dissociation of substrate from enzyme active site. Also, K2 is the rate constant for the formation of the products.

In order to calculate the initial velocity,V° we need to use the Michaelis- Menteen equation.

V° = Vmax ×(S)/ Km + (S)-------------------------------------------------------------(1).

From the question the parameters given are;

Vmax = 6.5 x 10–5 mol•sec–1 , [S] = 3.0 x 10–3 M, and KM = 4.5 x 10–3 M.

Therefore, slotting in the above parameters into the equation (1) above, we have;

V° = 6.5 x 10–5 mol•sec–1 × 3.0 x 10–3 M / 4.5 x 10–3 M + 3.0 x 10–3 M.

Initial velocity,V° = 2.6 x 10-5 moles per sec..

What is the relationship between potential and kinetic energy?*As potential energy increases, kinetic energy increases.
O As potential energy increases, kinetic energy decreases.
As potential energy decreases, kinetic energy decreases.
O Potential and kinetic energy are two separate things and have no relationship.

Answers

Answer:

As potential energy increases, kinetic energy decreases

It's an inverse relationship

Final answer:

Potential energy and kinetic energy are related through the law of conservation of energy. When potential energy increases, kinetic energy decreases, and vice versa, as energy is simply converted between these two forms.

Explanation:

The relationship between kinetic energy and potential energy lies within the law of conservation of energy. This law states that energy cannot be created or destroyed, only converted from one form to another.

Potential energy is the energy stored in an object due to its position in a force field or due to its configuration. For example, when you lift a book off the ground, it gains potential energy because of the work done against the force of gravity.

On the other hand, kinetic energy is the energy of an object due to its motion. The same book, when dropped, loses potential energy and gains kinetic energy as it falls towards the ground.

Hence, when potential energy increases, kinetic energy decreases, and vice versa. This is because the total energy (potential + kinetic) must be conserved, assuming no energy is lost to other forms like heat or sound.

Learn more about Conservation of Energy here:

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Which one of the following combinations cannot function as a buffer solution?A) HCN and KCN
B) NH3 and (NH4)2SO4
C) HNO3 and NaNO3
D) HF and NAF
E) HNO2 and NaNO2

Answers

Answer:

it is B

; )

Which one of the following combinations cannot function as a buffer solution?

A) HCN and KCN

B) NH3 and (NH4)2SO4

C) HNO3 and NaNO3

D) HF and NAF

E) HNO2 and NaNO2

What is the mass of silver chlorate (191.32 g/mol) that decomposes to release 0.466L of oxygen gas at STP? AgC1036) _AgCl). _026) A) 1.33g B) 597 E) 7.968 C) 3.988 D) 2658