Answer:
The ratio of the model size is 1 : 2000
Explanation:
Given
Real Diameter = 0.012 um
Scale Diameter = 24 um
Required
Determine the scale ratio
The scale ratio is calculated as follows;
Substitute values for real and scale measurements
Divide the numerator and the denominator by 0012um
Represent as ratio
Hence, the ratio of the model size is 1 : 2000
The ratio of the model size to the actual size is 1 : 2000. This means the model represents the white blood cell's diameter 2000 times larger than its actual size.
The ratio of the model size to the actual size can be calculated using the given measurements:
Actual Diameter = 0.012 um
Model Diameter = 24 um
Ratio = Model Diameter / Actual Diameter
Ratio = 24 um / 0.012 um
Ratio = 2000
So, the ratio of the model size to the actual size is 1 : 2000. This means the model represents the white blood cell's diameter 2000 times larger than its actual size.
Learn more about white blood from the link given below.
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B.) perception.
C.) similarity.
D.) continuity.
Answer:
C
Explanation:
Similarity
Wave speed = (wavelength) x (frequency)
We know the wavelength, but we don't know the frequency. How can we find the frequency ? "Here frequency frequency."
We know the period, and frequency is just (1 / period). So . . .
Wave speed = (wavelength) / (period)
Wave speed = (2.1 meters) / (9.4 seconds)
Wave speed = (2.1 / 9.4) m/s
Wave speed = 0.223 m/s
A speed skater moving across frictionless ice at 8.8 m/s hits a 6.0 m -wide patch of rough ice. Her acceleration on the rough ice is -3.65 m/s².
v² - u² = 2 a ∆x, where u and v are initial and final velocities, respectively; a is acceleration.
and ∆x is the distance traveled (because the skater moves in only one direction).
Thus, (5.8 m/s)² - (8.8 m/s)² = 2 a (6.0 m)
a = ((5.8 m/s)² - (8.8 m/s)²) / (12 m)
a = -3.65 m/s².
Thus, A speed skater moving across frictionless ice at 8.8 m/s hits a 6.0 m -wide patch of rough ice. Her acceleration on the rough ice is -3.65 m/s².
Learn more about Acceleration, refer to the link:
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Recall that
v² - u² = 2 a ∆x
where u and v are initial and final velocities, respectively; a is acceleration; and ∆x is the distance traveled (because the skater moves in only one direction).
So we have
(5.8 m/s)² - (8.8 m/s)² = 2 a (6.0 m)
a = ((5.8 m/s)² - (8.8 m/s)²) / (12 m)
a = -3.65 m/s²
Answer:
a) The fly is 2.24 m from the origin.
b) In polar coordinates, the position of the fly is (2.24 m, 26.7°).
Explanation:
Hi there!
The position vector of the fly is r = (2.00, 1.00)m. The distance from that point to the origin is the magnitude of the vector "r" (see figure).
a) Notice in the attached figure that the distance from the origin to the point where the fly is located is the hypotenuse of the triangle formed by r, the x-component of r (2.00 m) and the y-component ( 1.00 m). Then:
r² = (2.00 m)² + (1.00 m)²
r² = 5.00 m²
r = 2.24 m
The fly is 2.24 m from the origin.
b) To find the angle θ (see figure) we can use trigonometry:
cos θ = adjacent / hypotenuse
cos θ = 2.00 m / √5 m
θ = 26.7°
The same will be obtained if we use sin θ:
sin θ = opposite / hypotenuse
sin θ = 1.00 m / √5 m
θ = 26.7°
In polar coordinates, the position of the fly is (2.24 m, 26.7°).
The angular speed should be 17.18 rad / s
Since
moment of inertia of the disc I = 1/2 m r²
= .5 x 8 x .25²
= .25 kg m²
Now the work done by force should be converted into the rotational kinetic energy
F x d = 1/2 I ω²
here,
F is the force applied,
d is displacement,
I is moment of inertia of disc
and ω is angular velocity of disc
So,
41 x .9 = 1/2 x .25 ω²
ω² = .25
ω = 17.18 rad / s
Learn more about speed here: brainly.com/question/18742396
Answer:
Explanation:
moment of inertia of the disc I = 1/2 m r²
= .5 x 8 x .25²
= .25 kg m²
The wok done by force will be converted into rotational kinetic energy
F x d = 1/2 I ω²
F is force applied , d is displacement , I is moment of inertia of disc and ω
is angular velocity of disc
41 x .9 = 1/2 x .25 ω²
ω² = .25
ω = 17.18 rad / s
Answer:
Length = 2.453 m
Explanation:
Given:
Resistivity of the wire (ρ) = 1 × 10⁻⁶ Ω-m
Diameter of the wire (d) = 0.250 mm = 0.250 × 10⁻³ m
Resistance of the wire (R) = 50 Ω
Length of the wire (L) = ?
The area of cross section is given as:
We know that, for a constant temperature, the resistance of a wire is directly proportional to its length and inversely proportional to its area of cross section. The constant of proportionality is called the resistivity of the wire. Therefore,
Expressing the above in terms of length 'L', we get:
Plug in the given values and solve for 'L'. This gives,
Therefore, length of No. 30 wire (of diameter 0.250 mm) is 2.453 m.