A 60.0-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.57 m, and ends with a speed of 8.50 m/s. How much nonconservative work was done on the boy

Answers

Answer 1
Answer:

Answer:

Work = 1167.54 J

Explanation:

The amount of non-conservative work here can be given by the difference in kinetic energy and the potential energy. From Law of conservation of energy, we can write that:

Gain in K.E = Loss in P.E + Work

(0.5)(m)(Vf² - Vi²) - mgh = Work

where,

m = mass of boy = 60 kg

Vf = Final Speed = 8.5 m/s

Vi = Initial Speed = 1.6 m/s

g = 9.8 m/s²

h = height drop = 1.57 m

Therefore,

(0.5)(60 kg)[(8.5 m/s)² - (1.6 m/s)²] - (60 kg)(9.8 m/s²)(1.57 m) = Work

Work = 2090.7 J - 923.16 J

Work = 1167.54 J


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A piece of soft iron is placed in a solenoid increasing the magnetic field in an arrangement that can be switched on and off. Such a device is calleda. a hysteresis loop.b. an electrosolenoid.c. a permanent magnet.d. a ferromagnet.

Answers

Question:

A piece of soft iron is placed in a solenoid increasing the magnetic field in an arrangement that can be switched on and off. Such a device is called

Answer

a hysteresis loop.

an electrosolenoid.

a permanent magnet.

a ferromagnet.

an electromagnet

Answer:

A piece of soft iron is placed in a solenoid increasing the magnetic field in an arrangement that can be switched on and off. Such a device is called an electromagnet.

Explanation:

When a magnet is processed by supplying electricity than it is called as electromagnet and therefore its strength can be fluctuated as dependent on amount of electricity supplied.

Here, when a iron piece is moved closer to a long coil of wire named solenoid physical interaction named electromagnetic force take place between two electrically charged particles.

This force is supplied by electromagnetic fields constructed from electric and magnetic field. This is also called as Lorentz force constituted from both electricity and magnetism. This property itself gives evidence of characteristics of material used for electromagnetism.

A small space probe of mass 170 kg is launched from a spacecraft near Mars. It travels toward the surface of Mars, where it will eventually land. At a time 22.9 seconds after it is launched, the probe is at location <5600, 7200, 0> m, and at this same instant its momentum is <51000, -7000, 0> kg·m/s. At this instant, the net force on the probe due to the gravitational pull of Mars plus the air resistance acting on the probe is <-4000, -780, 0> N.Assuming that the net force on the probe is approximately constant during this time interval, what is the change of the momentum of the probe in the time interval from 22.6 seconds after the probe is launched to 22.9 seconds after the launch?

Answers

Answer:

The change  in momentum is  \Delta p = <-1200 , -234  , 0>  kg \cdot m/s      

Explanation:

From the question we are told that  

       The mass of the probe is  m = 170 kg

       The location of the prob at time t = 22.9 s is  A  = <5600, 7200,0>

       The  momentum at time  t = 22.9 s is  p = < 51000, -7000, 0> kg m/s

        The net force on the probe is  F = <-4000 , -780 , 0> N

Generally the change in momentum is mathematically represented as

              \Delta p = F * \Delta t

The initial time is   22.6 s

 The final time  is  22.9 s

             Substituting values  

           \Delta p = <-4000 , -780 , 0> * (22.9 - 22.6)

            \Delta p = <-4000 , -780 , 0> * (0.3)  

              \Delta p = <-1200 , -234  , 0>  kg \cdot m/s        

 

A simple pendulum takes 2.20 s to make one compete swing. If we now triple the length, how long will it take for one complete swing?

Answers

Answer:

Time taken for 1 swing = 3.81 second

Explanation:

Given:

Time taken for 1 swing = 2.20 Sec

Find:

Time taken for 1 swing , when triple the length(T2)

Computation:

Time taken for 1 swing = 2π[√l/g]

2.20 = 2π[√l/g].......Eq1

Time taken for 1 swing , when triple the length (3L)

Time taken for 1 swing = 2π[√3l/g].......Eq2

Squaring and dividing the eq(1) by (2)

4.84 / T2² = 1 / 3

T2 = 3.81 second

Time taken for 1 swing = 3.81 second

in the demolition of an old building,a 1,300 kg wrenching ball hits the building at 1.07m/s^2.Calculate the amount of force at which the wrecking ball strikes the building

Answers

Answer:

1391 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1300 × 1.07

We have the final answer as

1391 N

Hope this helps you

When you walk at an average speed (constant speed, no acceleration) of 24 m/s in 94.1 secyou will cover a distance of__?

Answers

Answer:

2258.4 m

Explanation:

Distance covered is a product of speed and time hence

s=vt where s is the displacement/distance covered, v is the speed and t is the time taken

s=24*94.1=2258.4 m

Therefore, the distance covered is 2258.4 m

What is the difference between V(peak voltage) and Vrms (root-mean-square) of AC voltage source?

Answers

Answer:

V(peak voltage) is the highest voltage that the waveform will ever attain and the Vrms(root-mean-square) is the effective voltage of the total waveform representing the AC source.