Answer:
C
Explanation:
Wastes from nuclear power plants are harmful and difficult to manage.
Answer:
C
Explanation:
The chemical equation presented in option A follows the law of conservation of mass.
The principle of conservation of mass states, mass can neither be created nor destroyed but can be transformed from one form to another.
A reaction that follows the law of conservation of mass, must have equal number of moles each elements in reactants side and products side.
Only option A follows the law of conservation of mass;
Thus, we can conclude that the chemical equation presented in option A follows the law of conservation of mass.
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Answer:
Option A
Explanation:
The expression that obeys the law of conservation of mass is choice A;
2LiOH + H₂CO₃ → Li₂CO₃ + 2H₂O
According to the law of conservation of mass; "in a chemical reaction, matter is neither created nor destroyed". By this law, mass is usually conserved.
The equation shows that mass is conserved because the number of moles of each specie is found on both sides
Number of moles
Li O H C
Reactants 2 5 4 1
Products 2 5 4 1
This shows that mass is indeed conserved.
Answer:
A carbon dioxide and oxygen
61.8 % is the mass percentage of magnesium sulphate.
Explanation:
The mass percent of individual solute or ion in a compound is calculated by the formula:
Grams of solute ÷ grams of solute + solvent × 100
mass percent of magnesium is calculated as 1 mole of magnesium having 24.305 grams/mole will have weight of 24.305 grams and 1 mole of MgSO4 will have 120.366 grams
Putting the values in the equation:
24.305 ÷ 144.671 × 100
= 16.8% of magnesium is in the mixture
The mass percentage of SO4 is calculated as
= 96.06 ÷ 216.426 × 100
= 44.38 %
The mass percentage of the mixture MgSO4 is 44.38 + 16.8 = 61.8 %
Mass percentage is a representation of the concentration of element or elements in a compound.
To increase the polarity of HBr, the bromine atom can be replaced with a hydrogen atom.
A polar molecule is one in which a dipole moment exists. There is a positive end and a negative end in a polar molecule. Conventionally, the direction of the dipole is from the positive end of the molecule towards the negative end of the molecule.
If we want to increase the polarity of the molecule then we must substitute the bromine atom with a more electronegative atom. In this case, chlorine is the best option.
Missing parts;
If you wanted to change the polarity of hydrogen bromide (HBr) by substitutingthe bromine by a different atom. Which atom would increase the polarity of the molecule?
A. chlorine (CI)
B. iodine (1)
C. sulfur (S)
D. hydrogen (H)
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Answer:
This question is incomplete as it lacks options, the options are:
A. chlorine (CI)
B. iodine (1)
C. sulfur (S)
D. hydrogen (H)
The answer is A. Chlorine
Explanation:
Polarity of a substance in chemistry is a function of electric charges in the atoms of the molecules involved. Polarity, however, can be increased or decreased in molecules depending on the charges of the atoms that form them.
Since polarity increases when an atom in the molecule has a high ability to pull electrons toward itself i.e. electronegativity, one atom that can be substituted for Bromine in the hydrogen bromide (HBr) molecule in order to increase its polarity is CHLORINE. This is because Chlorine (Cl) is more electronegative than Bromine atom, hence, will pull more electrons from hydrogen to make the HCl molecule more polar than HBr.
Answer:
1.7820210165667731 your welcome :)
Explanation: