CHEMISTRY COLLEGE

Ionic equation for Sr3(PO4)2 and its solubility product (Ksp)?

Answers

Answer 1

Answer:

Answer:

$Sr_3(PO_4)_2(s)\rightleftharpoons 3Sr^(+2)(aq)+2(PO_4)^(-3)(aq)$

$Ksp=[Sr^(+2)]^3[(PO_4)^(-3)]^2$

Explanation:

Hello,

In this case, for strontium phosphate, we find an ionic equation for its dissociation as shown below:

$Sr_3(PO_4)_2(s)\rightleftharpoons 3Sr^(+2)(aq)+2(PO_4)^(-3)(aq)$

Next, the solubility product is found by applying the law of mass action, considering that the solid salt is not considered but just the aqueous species due to heterogeneous equilibrium:

$Ksp=[Sr^(+2)]^3[(PO_4)^(-3)]^2$

Best regards.

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Polymers are large molecules composed of simple units repeated many times. Thus, they often have relatively simple empirical formulas. Calculate the empirical formulas of the following polymers: (a) Lucite (Plexiglas); 59.9% C, 8.06% H, 32.0% O (b) Saran; 24.8% C, 2.0% H, 73.1% Cl (c) polyethylene; 86% C, 14% H (d) polystyrene; 92.3% C, 7.7% H (e) Orlon; 67.9% C, 5.70% H, 26.4% N

What coefficients must be added to balance the following reaction?_____ Pb + _____ H3PO4 yields _____ H2 + _____ Pb3(PO4)2

A: 3, 2, 1, 1

B: 3, 2, 2, 1

C: 3, 1, 3, 1

D: 3, 2, 3, 1

Answers

D: 3, 2, 3, 1 The Pb3(PO4) comes from having 3 Pb and 2 H3PO4. The H2 comes from the 2H3PO4

Two samples of carbon tetrachloride were decomposed into their constituent elements. One sample produced 38.9 g of carbon and 463 g of chlorine, and the other sample produced 14.8 g of carbon and 144 g of chlorine. Part A Are these results consistent with the law of definite proportions?

Answers

Explanation:

Firstly, defining Law of definite proportion which states that in any chemical compound, the elements are the same and are in the same proportion by mass. It is also called Proust's law.

In sample A;

38.9 g of carbon

463 g of chlorine

In sample B;

14.8 g of carbon

144 g of chlorine.

Sample A, Ratio of mass of Carbon to mass of Chlorine

= 38.9 : 463

= 0.084

Sample B, Ratio of mass of Carbon to mass of Chlorine

= 14.8 : 144

= 0.103

These results above show that the ratio of the masses of Carbon to Chlorine in both samples A and B are not the same so therefore, the results are not consistent with the law of definite proportion.

5.75 x 1021 molecules of oxygen is the equivalent of how many
moles?

Answers

765.75

................................

Why do organisms evolve?Organisms make changes to help them survive and reproduce in their environment

Organisms with traits that help them survive and reproduce in their environment pass on those traits.

Changes in the environment cause organisms to change.
Organisms naturally select traits that help them survive and reproduce

Answers

In an ecosystem, organisms evolve to make changes to help them survive and reproduce in their environment.

What is an ecosystem?

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

Learn more about ecosystem,here:

brainly.com/question/1673533

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How many atoms are in 2.3 moles Au?

Answers

Answer:

6.02×10^23atoms of au

Answer:

i think 3

Explanation:

Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices

Answers

Complete Question

Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in n=4 and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices

Answer:

$n=2$

Explanation:

From the question we are told that:

Wavelength $\lambda=486nm=>486*10^(-9)$

Generally the equation for Atom Transition is mathematically given by

$(1)/(\lambda)=R_(\infty )((1)/(n_1^2)-(1)/(n_2^2))$

Where

Rydberg constant $R_(\infty)=1.097*10^7$

Therefore

$(1)/(486*10^(-9))=1.097*10^7*((1)/(n_1^2)-(1)/(4^2))$

$((1)/(n_1^2)-(1)/(4^2))=(1)/(486*10^(-9)*1.097*10^7)$

$n_1^2=3.98$

$n=1.99$

$n=2$

Final answer:

The final value of n in the hydrogen atom transition is 4.

Explanation:

The end value of n in a hydrogen atom transition can be determined using the equation En = Eo * Z^2 / n^2, where En is the energy of the excited state and Eo is the ionization energy. Since the electron starts in the ground state (n = 1) and emits a photon of light with a wavelength of 486 nm, we can use Equation 6.49 to solve for n. By substituting m = 1 and λ = 486 nm into Equation 6.49, we find that n is approximately 4. Therefore, the final value of n in the hydrogen atom transition is 4.