Which substance is most likely a lipid? -long chains of molecules composed of carbon, hydrogen, and oxygen atoms -compounds that are composed of amino acids and atoms, such as nitrogen, that are joined together by peptide bonds -a nonpolar organic compound that is insoluble in water -a molecule that constitutes the building blocks of more complex molecules that are soluble in water

Answers

Answer 1
Answer:

Answer:

The answer is

Explanation:

- A nonpolar organic compound that is insoluble in water

Answer 2
Answer:

Answer:

A nonpolar organic compound that is insoluble in water

Explanation:


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A cubic box with sides of 20.0 cm contains 2.00 × 1023 molecules of helium with a root-mean-square speed (thermal speed) of 200 m/s. The mass of a helium molecule is 3.40 × 10-27 kg. What is the average pressure exerted by the molecules on the walls of the container? (The Boltzmann constant is 1.38 × 10-23 J/K and the ideal gas constant is R = 8.314 J/mol•K .) (12 pts.)
Determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
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Give an example of an element and an example of a compound.

Answers

Answer:

an element is a atom like titanium and a compound is like a water, glucose, alcohol and salt

Explanation:

the titanium is a element and water, glucose, alcohol, and salt those are a compound

The standard free energy change for a reaction in an electrolytic cell is always:_________ a. Positive
b. Negative
c. Zero
d. Impossible to determine

Answers

Answer: The standard free energy change for a reaction in an electrolytic cell is always positive.

Explanation:

Electrolytic cells use electric currents to drive a non-spontaneous reaction forward.

Relation of standard free energy change and emf of cell

\Delta G^o=-nFE^0_(cell)

where,

\Delta G^o = standard free energy change

  n= no of electrons gained or lost

F= faraday's constant

E^0_(cell) = standard emf

E^0_(cell)   = standard emf = -ve  , for non spontaneous reaction

Thus  \Delta G^o=(-ve)(-ve)=+ve

Thus standard free energy change for a reaction in an electrolytic cell is always positive.

Two hypothetical ionic compounds are discovered with the chemical formulas XCl2 and YCl2, where X and Y represent symbols of the imaginary elements. Chemical analysis of the two compounds reveals that 0.25 mol XCl2 has a mass of 100.0 g and 0.50 mol YCl2 has a mass of 125.0 g. (a) What are the molar masses of XCl2 and YCl2

Answers

Answer:

THE MOLAR MASS OF XCL2 IS 400 g/mol

THE MOLAR MASS OF YCL2 IS 250 g/mol.

Explanation:

We calculate the molar mass of XCL2 and YCL2 by bringing to mind the formula for molar mass when mass and amount or number of moles of the substance is given.

Number of moles = mass / molar mass

Molar mass = mass / number of moles.

For XCL2,

mass = 100 g

number of mole = 0.25 mol

So therefore, molar mass = mass / number of moles

Molar mass = 100 g / 0.25 mol

Molar mass = 400 g/mol.

For YCL2,

mass = 125 g

number of mole = 0.50 mol

Molar mass = 125 g / 0.50 mol

Molar mass = 250 g/mol.

So therefore, the molar mass of XCL2 and YCL2 IS 400 g/mol and 250 g/mol respectively.

Final answer:

The molar mass of XCl2 is 400 g/mol and the molar mass of YCl2 is 250 g/mol.

Explanation:

To find the molar masses of XCl2 and YCl2, we can use the relationship between molar mass, moles, and mass. The molar mass is calculated by dividing the mass of a compound by the number of moles.

For XCl2, we have 0.25 mol and 100.0 g. So, the molar mass of XCl2 is 100.0 g / 0.25 mol = 400 g/mol.

For YCl2, we have 0.50 mol and 125.0 g. So, the molar mass of YCl2 is 125.0 g / 0.50 mol = 250 g/mol.

Learn more about Molar mass here:

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Two samples of carbon tetrachloride were decomposed into their constituent elements. One sample produced 38.9 g of carbon and 463 g of chlorine, and the other sample produced 14.8 g of carbon and 144 g of chlorine. Part A Are these results consistent with the law of definite proportions?

Answers

Explanation:

Firstly, defining Law of definite proportion which states that in any chemical compound, the elements are the same and are in the same proportion by mass. It is also called Proust's law.

In sample A;

38.9 g of carbon

463 g of chlorine

In sample B;

14.8 g of carbon

144 g of chlorine.

Sample A, Ratio of mass of Carbon to mass of Chlorine

= 38.9 : 463

= 0.084

Sample B, Ratio of mass of Carbon to mass of Chlorine

= 14.8 : 144

= 0.103

These results above show that the ratio of the masses of Carbon to Chlorine in both samples A and B are not the same so therefore, the results are not consistent with the law of definite proportion.

Mg(OH)2 is a sparingly soluble salt with a solubility product, Ksp, of 5.61×10−11. It is used to control the pH and provide nutrients in the biological (microbial) treatment of municipal wastewater streams. What is the ratio of solubility of Mg(OH)2 dissolved in pure H2O to Mg(OH)2 dissolved in a 0.180 M NaOH solution? Express your answer numerically as the ratio of molar solubility in H2O to the molar solubility in NaOH.

Answers

Answer:

The ration of the molar solubility is 165068.49.

Explanation:

The solubility reaction of the magnesium hydroxide in the pure water is as follows.

Mg(OH)_(2)\Leftrightarrow Mg^(2+)(aq)+2(OH)^(-)(aq)

              [Mg^(2+)][OH^(-)]

Initial      0          0

Equili     +S       +2S

Final      S          2S

K_(sp)=[Mg^(2+)][OH^(-)]

5.61* 10^(-11)=(S)(2S)^(2)

S=((5.61* 10^(-11))/(4))^(1/3)=2.41* 10^(-4)M

Solubility of Mg(OH)_(2) in 0.180 M NaOH is a follows.

Mg(OH)_(2)\Leftrightarrow Mg^(2+)(aq)+2(OH)^(-)(aq)

              [Mg^(2+)][OH^(-)]

Initial      0          0

Equili     +S       +2S

Final      S          2S+0.180M

K_(sp)=[Mg^(2+)][OH^(-)]

5.61* 10^(-11)=(S)(2S+0.180)^(2)

S=1.46* 10^(-9)M

Ratio\,of\,solubility=(2.41* 10^(-4))/(1.46* 10^(-9))=165068.49

Therefore, The ration of the molar solubility is 165068.49.

Calculate the mass of a sample of lead (cPb = 0.16 J/g℃) when it loses 200 J cooling from 75.0℃ to 42.0℃.

Answers

looses 299 please collins 75.0