Give an example of coupling reaction​

Answers

Answer 1
Answer:

Answer:

An example is the formation of ATP, which is an endergonic process and is coupled to the dissipation of a proton gradient.

Explanation:

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If 35.2 g of magnesium react with excess hydrochloric acid, how many grams of magnesium chloride are produced? Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(aq)

Answers

Answer:

139.33 g of magnesium chloride, MgCl2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(aq)

Next, we shall determine the mass of Mg that reacted and the mass of MgCl2 from the balanced equation.

This is illustrated below:

Molar mass of Mg = 24 g/mol

Mass of Mg from the balanced equation = 1 x 24 = 24 g

Molar mass of MgCl2 = 24 + (2x35.5) = 95 g/mol

Mass of MgCl2 from the balanced equation = 1 x 95 = 95 g

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgCl2.

Finally, we shall determine the mass of MgCl2 produced by reacting 35.2 g of Mg.

This can be obtained as follow:

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgCl2.

Therefore, 35.2 g of Mg will react to produce = (35.2 x 95)/24 = 139.33 g of MgCl2.

From the calculations made above, 139.33 g of magnesium chloride, MgCl2 were produced.

Using her new telescope Ashley discovers a spherical meteor passing between the earth and the moon and measures it’s radius as 3 kilometers how many cubic kilometers are in the meteor

Answers

Answer:

113 km³

Explanation:

Step 1: Given data

Radius of the meteor (r): 3 km

Step 2: Calculate the volume (V) of the meteor

The meteor is spherical. Given the radius (r), we can calculate the volume of a sphere using the following expression.

V = 4/3 × π × r³

V = 4/3 × π × (3 km)³

V = 4/3 × π × 27 km³

V = 113 km³

The volume of the meteor is 113 km³.

What type(s) of intermolecular forces exist between two molecules of 1-pentanol? (BLB Ch. 11)

Answers

Answer:

Hydrogen bonding

London dispersion forces

Explanation:

The most pronounced and consequential intermolecular forces at play has to be hydrogen bonding due to the dipole created between the oxygen and hydrogen in the hydroxyl group. And then to a lesser extent there are very weak London dispersion forces that are always going to be there in between any two molecules of any species.

Which yield comes from measurements obtained during a real experiment?A) actual yield
B) theoretical yield
C) percent yield

Answers

Answer:

A) actual yield

Explanation:

Theoretical yield is the amount of product expected based on the stoichiomety.

Percent yield is the actual yield over the theoretical yield.

In the equilibrium system described by: PO43-(aq) + H2O(1) = HPO42-(aq) + OH-(aq) Brønsted-Lowry theory would designate: A) PO43- and H20 as the bases B) H20 and OH as a conjugate pair C) HPO42- and OH"" as the acids D) HPO42- and H20 as a conjugate pair E) PO43-as amphiprotic

Answers

Answer:

The correct option is:  B) H₂0 and OH⁻ as a conjugate pair

Explanation:

According to Brønsted-Lowry theory, theacids are the chemical substances that form a conjugate base by donating a proton and bases are the chemical substances that form conjugate acid by accepting a proton.

In the given chemical reaction: PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)

According to Brønsted-Lowry theory, PO₄³⁻ and OH⁻ are bases. Whereas, H₂O and HPO₄²⁻ are acids.

Also, PO₄³⁻ and HPO₄²⁻ are the conjugate acid-base pair; and H₂O and OH⁻ are the conjugate acid-base pair.

At 25.0 ⁰C the henry's law constant for hydrogen sulfide(H2S) gas in water is 0.087 M/atm. Caculate the mass in grams of H2S gas that can be dissolved in 400.0 ml of water at 25.00 C and a H2S partial pressure of 2.42atm.

Answers

Answer: The mass of hydrogen sulfide that can be dissolved is 2.86 grams.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the gas.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_(H_2S)=K_H* p_(liquid)

where,

K_H = Henry's constant = 0.087M/atm

p_(H_2S) = partial pressure of hydrogen sulfide gas = 2.42 atm

Putting values in above equation, we get:

C_(H_2S)=0.087M/atm* 2.42atm\n\nC_(H_2S)=0.2105M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.2105 M

Molar mass of hydrogen sulfide = 34 g/mol

Volume of solution = 400.0 mL

Putting values in above equation, we get:

0.2105M=\frac{\text{Mass of hydrogen sulfide}* 1000}{34g/mol* 400.0mL}\n\n\text{Mass of }H_2S=(0.2105* 34* 400)/(1000)=2.86g

Hence, the mass of hydrogen sulfide that can be dissolved is 2.86 grams.