Which one of these could be in the unknown anion "X" in this acid: H3Xcarbonate
fluorate
nitrogen
nitrite

Could you explain how to find this? The process?

Answers

Answer 1

Answer:

Answer:

the answer is nitrogen

Related Questions

indigestion tablets neutralise acid in the stomach. what does this tell you about indigestion tablets?
Which beat describes heat
Answer True or False for each of the following statements. (a) The carburization surface was maintained at slightly less than 0.25 wt% carbon for each specimen. (b) Comparing the finished specimens at a depth of 0.20 mm, specimen A features the lowest carbon concentration. (c) Comparing the finished specimens as a whole, specimen D features the lowest overall amount of carbon.
You need to prepare an acetate buffer of pH 5.47 from a 0.809 M acetic acid solution and a 2.20 M KOH solution. If you have 680 mL of the acetic acid solution, how many milliliters of the KOH solution do you need to add to make a buffer of pH 5.47 ? The pa of acetic acid is 4.76. Be sure to use appropriate significant figures.
____________ acids are proton donors. ____________ bases are proton acceptors. The ____________ the pKₐ the stronger the acid. ____________ acids are electron pair acceptors.

State and explain grahms law of diffusion

Answers

Answer:

Graham's law of effusion was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. This formula can be written as: , where: Rate₁ is the rate of effusion for the first gas.

Explanation:

r1 = rate of effusion for gas 1

r2 = rate of effusion for gas 2

M1 = molar mass of gas 1

M2 = molar mass of gas 2

Dumbledore thinks the students are now confident with significant figures; Snape is not so confident of this... Begrudgingly Snape decides to move forward in his lesson. His next lesson is in naming ionic compounds. He presents his students with sodium hydrogen sulfate and potassium permanganate. Which pair of ionic formulas is correct for these two compounds?(A) NaHSO3, KMnO4
(B) NaHSO2, KMnO4
(C) NaHSO4, KMnO4
(D) NaHSO4, KMnO3
(E) NaHSO3, KMnO3

Answers

Answer:

C) $NaHSO_(4), KMnO_(4)$

Explanation:

- For the sodium hydrogen sulfate:

The ending -ate of the word sulfate indicates that the compound comes from the ion sulfate that is $SO_(4)^(-)$ , so the compound formed by this ion will be $NaHSO_(4)$

- For the potassium permanganate:

The ending -ate of the word permanganate indicates that the compound comes from the ion $MnO^(-)_(4)$ , so the compound formed by this ion will be $KMnO_(4)$

A system absorbs 12 J of heat from the surroundings; meanwhile, 28 J of work is done on the system. What is the change of the internal energy ΔEth of the system?

Answers

Answer: The value of change in internal energy of the system is, 40 J.

Explanation : Given,

Heat absorb from the surroundings = 12 J

Work done on the system = 28 J

First law of thermodynamic : It is a law of conservation of energy in which the total mass and the energy of an isolated system remains constant.

As per first law of thermodynamic,

$\Delta U=q+w$

where,

$\Delta U$ = internal energy = ?

q = heat absorb from the surroundings

w = work done on the system

Now put all the given values in this formula, we get the change in internal energy of the system.

$\Delta U=12J+28J$

$\Delta U=40J$

Therefore, the value of change in internal energy of the system is, 40J.

A biochemist studying breakdown of the insecticide DDT finds that it decomposes by a first-order reaction with a half-life of 12.0 yr. How long does it take DDT in a soil sample to decompose from 809 ppbm to 10.0 ppbm (parts per billion by mass)

Answers

Answer:

76.0 years

Explanation:

Step 1: Given data

Half-life (t1/2): 12.0 y

Initial concentration of DDT ([A]₀): 809 ppbm

Final concentration of DDT ([A]): 10.0 ppbm

Time elapsed (t): ?

Step 2: Calculate the rate constant (k)

We will use the following expression.

k = ln 2/ t1/2 = ln 2 / 12.0 y = 0.0578 y⁻¹

Step 3: Calculate the time elapsed

For a first-reaction order, we will use the following equation.

ln [A]/[A]₀ = -k × t

t = ln [A]/[A]₀ / (-k)

t = (ln 10.0 ppbm/809 ppbm) / (-0.0578 y⁻¹)

t = 76.0 y

Given the information about each pair of acids fill in the correct answer. a. Acid A has a lower % ionization than B:_______ is a stronger acid.
b. Acid B has a larger K_a than acid A._______ will have a larger percent ionization.
c. A is a stronger acid than B. Acid B will have________ percent ionization than A.

Answers

Answer:

a. Acid B

b. Acid B

c. lower

Hope this helps you

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution? Kb = 0.51°C/m for water. Enter your answer with 2 decimal places and no units.