Answer:
I assume you mean which best describes heat.
The answer is The energy transferred between samples of matter because of a difference in their temperatures.
To explain this further, heat is total energy of an object, temperature is average energy. The change in temperature between two objects is called heat!
Think about transfers of heat in everyday terms: if you put an ice cube in your tea (I don't know, just bear with me), the cold does not transfer to the tea. The heat of the tea is transferred to the ice cube! And this is clearly a difference in heat.
Answer:
= 261 nm
Silver is not a good choice.
Explanation:
Where,
h is Plank's constant having value
c is the speed of light having value
is the wavelength of the light
Given that:- Energy =
= 261 nm
Visible range has a spectrum of 380 to 740 nm
So, Silver is not a good choice.
The maximum wavelength needed to remove an electron from silver is approximately 262 nm. Silver is not a good choice for a photocell that uses visible light.
To find the maximum wavelength needed to remove an electron from silver, we can use the work function of silver, which is Φ = 4.73 eV. The threshold wavelength for observing the photoelectric effect in silver can be calculated using Equation 6.16, which is λ = hc/Φ. Substituting the given values, we have λ = (1240 eV⋅nm) / (4.73 eV), which gives us a threshold wavelength of approximately 262 nm. Since visible light ranges from 400 to 700 nm, silver is not a good choice for a photocell that uses visible light.
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The conjugate acidand base
and the term would be Amphoteric.
Conjugate acid-
Amphoteric is described as the term employed to denote a substance that possesses the characteristics of both an acid, as well as, a base.
Given equilibrium:
→
Therefore, the dissolution of in water leads to the display acid that is conjugate
and the conugate base
.
In case, the properties of both are reflected, it shows amphoteric nature.
Learn more about "Acid" here:
Answer:
Conjugate acid- H^+
Conjugate base- SO4^2-
Terminology- Amphoteric
Explanation:
Consider the equilibrum shown below;
HSO4^-(aq)<-------> H^+(aq) + SO4^2-(aq)
Hence, When HSO4^- is dissolved in aqueous solution, it's conjugate acid is H^+ and it's conjugate base is SO4^2- as shown in the equation above.
If a substance behaves both as an acid and as a base, then the substance is Amphoteric in nature.
Answer:
two monosaccharides join by dehydration synthesis
Explanation:
A disaccharide is formed when two monomers join together by a loss of water molecule.
A disaccharide is formulated when two monosaccharides join through dehydration synthesis. A water molecule is dropped, and a glycosidic bond is formed between the two sugar elements. Sucrose, lactose, and maltose are crucial disaccharides for humans.
A disaccharide forms when two monosaccharides join by dehydration synthesis. This reaction involves a hydroxyl group (-OH) of one monosaccharide combining with a hydrogen atom of another monosaccharide. As a result, a molecule of water (H₂O) is released, and a covalent bond, specifically known as a glycosidic bond, forms between the two sugar molecules. Disaccharides critical for humans include sucrose (table sugar), lactose (milk sugar), and maltose (malt sugar). However, the human body cannot directly use these. They must first be split into their constituent monosaccharides via a separate process known as hydrolysis in the digestive tract.
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Answer:
B
Explanation:
Use your periodic table to find out the charge on a Fl ion if your periodic table is constructed that way. In any event, the charge on Fl when it becomes an ion is -1. I don't think it has any other charge. So all of the elements in column 17 will have at least -1 in common.
Group 17 elements, also known as halogens, have seven valence electrons and tend to gain one electron to become stable, forming a -1 ion.
The elements in Group 17 on the periodic table are also known as halogens. These elements, which include fluorine, chlorine, bromine, iodine, and astatine, have seven valence electrons. Hence, they tend to gain one electron to achieve a stable electron configuration, forming a -1 ion. Therefore, the correct answer to your question is B. -1 ion.
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