You need to prepare an acetate buffer of pH 5.47 from a 0.809 M acetic acid solution and a 2.20 M KOH solution. If you have 680 mL of the acetic acid solution, how many milliliters of the KOH solution do you need to add to make a buffer of pH 5.47 ? The pa of acetic acid is 4.76. Be sure to use appropriate significant figures.

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Answer 1

Answer:

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A chemist prepares a solution of magnesium fluoride MgF2 by measuring out 0.00598μmol of magnesium fluoride into a 50.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /μmolL of the chemist's magnesium fluoride solution. Round your answer to 2 significant digits.

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Answer:

0,12 μmol/L of MgF₂

Explanation:

Preparation of solutions is a common work in chemist's life.

In this porblem says that you measure 0,00598 μmol of MgF₂ in 50,0 mL of water and you must calculate concentration in μmol/L

You have 0,00598 μmol but not Liters.

To obtain liters you sholud convert mL to L, knowing 1000mL are 1 L, thus:

50,0 mL (1L/1000mL) = 0,05 L of water.

Thus, concentration in μmol/L is:

0,00598 μmol / 0,05 L = 0,12 μmol/L -The problem request answer with two significant digits-

I hope it helps!

All light travels at the same speed.
O True
O False

Answers

False

thank me later

Answer:

False

Explanation:

It depends on wixh kid of light is it

Example

Sun light difders from lamp light

how many grams of F2 are needed to react with 3.50 grams of Cl2 Equation needed for question- Cl2+3F2-->2ClF3 please explain how to get the answer.

Answers

Answer:

5.62 g of F2

Explanation:

We have to start with the chemical reaction:

$Cl_2~+~3F_2~-->~2ClF_3$

We have a balanced reaction, so we can continue with the mol calculation. For this, we need to know the molar mass of $Cl_2$ (70.906 g/mol), so:

$3.5~g~Cl_2(1~mol~Cl_2)/(70.906~g~Cl_2)=0.049~mol~Cl_2$

Now, with the molar ratio between $Cl_2$ and $F_2$ we can convert from moles of $Cl_2$ and $F_2$ (1:3), so:

$0.049~mol~Cl_2(3~mol~F_2)/(1~mol~Cl_2)=0.148~mol~F_2$

Finally, with the molar mass of $F_2$ we can calculate the gram of $F_2$ (37.99 g/mol), so:

$0.148~mol~F_2(37.99~g~F_2)/(1~mol~F_2)=5.62~g~F_2$

I hope it helps!

What is the correct noble gas configuration for oxygen?

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Oxygen (O) is a chemical element which you're surely familiar with since you breathe it every second of your life. The noble gas configuration is [He] 2s2 2p4. This shows that there is a total of 8 electrons (two in the 1s orbital, another 2 in the 2s orbital and the rest in the 2p orbital)

Let me know if you need anything else.

- Dotz :)

Blood samples for research or medical tests sometimes have heparin added. Why is this done?

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It is essential for accurate results that the correct volume of blood is sampled to achieve a correct concentration (and dilution, if liquid heparin is used), and that blood and anticoagulant are well mixed immediately after sampling.

A chemical equation is balanced when thesubscripts of the reactants equal the subscripts of the products,
coefficients of the reactants equal the coefficients of the products,
products and reactants are the same chemicals,
same number of each kind of atom appears in the reactants and in the products,

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same number of each kind of atom appears in the reactants and in the products

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