Answer:
bxnhdjxjdjvxjsj sbdhhxhchdbd
Answer:
I dont know about the yield but I think mno2 is the limiting reactant
Answer:
Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound.
Explanation:
got it right on edge 2020 :)
Answer:
Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound.
Explanation:
Matter is not created nor destroyed.
The total mass of the products is greater than the total mass of the reactants.
The total mass of the reactants is less that the total mass of the products.
Matter is not changed.
Answer
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
Answer:
Water.
Explanation:
Hello,
In this case, you are referring to the dissociation or formation of water at the equilibrium, that is:
In such a way, the water is the conjugate acid of the hydroxile ion as long as it gains a proton.
Best regards.
Answer:
2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O
α =2
β = 19
γ = 12
δ = 14
53.2moles of O₂
Explanation:
Proper equation of the reaction:
αC₆H₁₄ + βO₂ → γCO₂ + δH₂O
This is a combustion reaction for a hydrocarbon. For the combustion of a hydrocarbon, the combustion equation is given below:
CₓHₙ + (x + )O₂ → xCO₂ + H₂O
From the given combustion equation, x = 6 and n = 14
Therefore:
β = x + = 6 + = 6 + 3.5 = 9
γ = 6
δ = = = 7
The complete reaction equation is therefore given as:
C₆H₁₄ + 9O₂ → 6CO₂ + 7H₂O
To express as whole number integers, we multiply the coefficients through by 2:
2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O
Problem 2
From the reaction:
2 moles of hexane are required to completely react with 19 moles of O₂
∴ 5.6 moles of hexane would react with k moles of O₂
This gives: 5.6 x 19 = 2k
k =
k = 53.2moles of O₂