How do test with crash dummies, seat belts, and air bags illustrate newton's first law of motion??

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Answer 1
Answer:

Answer:

Newton’s law of inertia is illustrated in tests with crash dummies, seat belts, and airbags, wherein the object stays in motion unless there is an unbalanced force applied to it.

Inertia is the main reason why there are seatbelts and airbags in the car. In this case, when the seatbelt is trapped to the passenger, the passenger experiences the same state of motion as the car. If the car accelerates/decelerates, the passenger experiences it too. When the car experiences collision, an unbalance force is acted upon it. This causes the car to stop abruptly, and the passenger shares the same state of motion because of the seatbelt and the airbags that apply the unbalanced force to stop the passenger to go forward.


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What mass of nitrogen gas is required to react completely with 2.79 g of hydrogen gas to produce ammonia?

When a chemical reaction occurs blank happens

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Answer:

In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Explanation:

What are the conjugate base and conjugate acid for HSO4−? What is the term used to describe species that can behave as either an acid or a base, depending on the chemical environment?

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The conjugate acidH^+and baseSO4^2- and the term would be Amphoteric.

Conjugate acid-

What is Amphoteric?

Amphoteric is described as the term employed to denote a substance that possesses the characteristics of both an acid, as well as, a base.

Given equilibrium:

HSO4^-(aq)H^+(aq) + SO4^2-(aq)

Therefore, the dissolution of HSO4^- in water leads to the display acid that is conjugateH^+ and the conugate base SO4^2-.

In case, the properties of both are reflected, it shows amphoteric nature.

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Answer:

Conjugate acid- H^+

Conjugate base- SO4^2-

Terminology- Amphoteric

Explanation:

Consider the equilibrum shown below;

HSO4^-(aq)<-------> H^+(aq) + SO4^2-(aq)

Hence, When HSO4^- is dissolved in aqueous solution, it's conjugate acid is H^+ and it's conjugate base is SO4^2- as shown in the equation above.

If a substance behaves both as an acid and as a base, then the substance is Amphoteric in nature.

Give an example of an element and an example of a compound.

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Answer:

an element is a atom like titanium and a compound is like a water, glucose, alcohol and salt

Explanation:

the titanium is a element and water, glucose, alcohol, and salt those are a compound

Name the following : [Ni(NH3) 4(H2O)2(NO3)2​

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Any member of the family of chemicals known as coordination compounds has a core metal atom that is surrounded by nonmetal atoms or groups of atoms, known as ligands, that are connected to it by chemical bonds. The name of the compound is tetraaminodiaquanickel (II)nitrate.

The additional molecular compounds known as coordination compounds are those that are stable in both the solid and dissolved states. In these compounds, ions or molecules connected by coordinate bonds connect the main metal atom or ion.

Coordination compounds are used in both vital catalytic processes that lead to the polymerization of organic molecules like polyethylene and polypropylene as well as hydrometallurgical processes that remove metals like nickel, cobalt, and copper from their ores.

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Suppose 0.10 mol of Cu(NO_3)_2 and 1.50 mol of NH_3 are dissolved in water and diluted to a total volume of 1.00 L. Calculate the concentrations of Cu(NH_3)_4^2+ and of Cu^2+ at equilibrium.

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Explanation:

It is known that the coefficients change in concentration and in the exponents.  Hence, the reaction equation will be as follows.

     Cu^(2+)(aq) + 4NH_(3)(aq) \rightarrow Cu(NH_(3))^(2)_(4)(aq)

According to the ICE table,

      Cu^(2+)(aq) + 4NH_(3)(aq) \rightarrow Cu(NH_(3))^(2)_(4)(aq)

Initial :    0.10         1.50                        0

Change : -x         -4x                        +x

Equilibrium: 0.10 - x  1.50 - 4x            x  

Hence, the mass action expression is as follows.

    K_(f) = ([Cu(NH3)^(2+)_(4)])/([Cu^(2+)][NH_(3)]_(4))

                        = (x)/((0.10 - x)(1.50 - 4x)^(4))

As, the value of is huge, it means that the reaction is very product favored. Hence, we need to find the limiting reactant first and then  we get to know what x should be.

In the given reaction ammonia is the limiting reactant, because there is less than 4 times the ammonia as the copper cation. Thus, we expect it to run out first, and so, x is approximately equal to 0.25 M.

So, putting the given values into the above equation as follows.

   1.03 * 10^(13) = (0.25)/((0.10 - 0.25)(1.50 - 4x))^(4)

                              =

From here

   [NH_(3)] = 1.50 - 4x = ((2.33)/(1.03 * 10^(13)))^{(1)/(4)

                       = M

Therefore, we can "re-solve" for x to get and verify that it is still ≈0.250 M.

                x = [Cu(NH_(3))^(2+)_(4)]

                  = \frac{1.50 - 2.31284 * 10{-4}}{4}]

                    = 0.37491425 M

Thus, we can conclude that concentration of (Cu^(2+)) is  0.37491425 M.

Draw the predominant product(s) of the following reactions including stereochemistry when it is appropriate. CH3CH2 C C CH3 H2O/H2SO4/HgSO4

Answers

Answer:

Draw the predominant product(s) of the following reactions including stereochemistry when it is appropriate.

CH3CH2 C C CH3 H2O/H2SO4/HgSO4

Explanation:

The given compound is: pent-2-yne.

When it reacts with water, in presence of sulphuric acid and mercuric sulphate then a ketone is formed as shown below:

This reaction is an example of nucleophilic attack of water on carbon carbon triple bond.

The general mechanism of the reaction is hsown below:

Pent-2-yne reacts with water and form 3-pentanone.

The reaction is shown below:

Final answer:

The reaction is the hydration of an alkene in an acidic environment, resulting in the formation of 2-butanol. This result is in accordance with Markovnikov's rule, which determines the position of the hydroxyl group in the resultant product.

Explanation:

The question refers to the acidity-catalyzed hydration of an alkene. In this case, you have an alkene CH3CH2 - CC - CH3 reacting in an acidic environment with water (H2O). The reactants have been exposed to H2O/H2SO4/HgSO4. In this reaction scenario, the acidic medium (H2SO4) and the water enact the role of a nucleophile and attack the alkene, thereby hydrating it.

The product of this reaction will be 2-butanol. Its formation is guided by Markovnikov's rule, which states that in the addition of a protic acid HX to an alkene, the acid hydrogen (H) becomes attached to the carbon with fewer alkyl substituents, and the halide (X) group becomes attached to the carbon with more alkyl substituents. This rule is why the hydroxyl group (-OH) attaches itself to the 2nd carbon atom in the major (predominant) product.

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