You just measured a metal cylinder and obtained the following information: mass - 3.543 g diameter -0.53 cm height = 4.40 cm. 265 • Determine the volume (V). (V=nrºh, where r = radius, h = height, T - 3.14) V= (3.14 36205² 4.402.17cm? • Determine density of the cylinder D. 3. SMS-365923 197
Answers
The density of the cylinder would be 3.652 gram/ cm³
.
What is density?
It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
As given in the problem, you just measured a metal cylinder and obtained the following information: mass - 3.543 grams, diameter 0.53 cm, height = 4.40 cm , and we have to calculate the density of the cylinder,
mass of the cylinder = 3.543 grams
the volume of the cylinder = πr²h
= 3.14 ×.265²×4.4
=0.97 cm³
By using the above formula for density
ρ = mass of the cylinder/volume of the cylinder
= 3.543 grams/0.97 cm³
=3.652 grams/ cm³
Thus,the density of the cylinder would be 3.652 grams/ cm³.
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Answer:
V cylinder =
note that
density =
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The amount of heat required to melt 2 lbs of ice is twice the amount of heat required to melt 1 ib of ice. is this observation a macroscopic or microscopic description of chemical behavior? Explain your answer.
An isotope contains 26 protons, 24 electrons, and 32 neutrons. What is the identity of the isotope
B. two
C. three
D. four
Answers
Answer:
C. three
Explanation:
Final answer:
A lithium atom must lose one valence electron to achieve a full valence shell, resulting in a positively charged lithium cation (Lit) with a noble gas configuration similar to helium.
Explanation:
To achieve a full valence shell, a lithium atom must lose one electron. Lithium has an atomic number of 3, which means it has three electrons: two in the first shell and one in the second shell. Since the first shell (1s) is already full with two electrons, lithium has a single electron in the 2s subshell of the second shell. This single electron is the valence electron.
According to the Lewis diagram, lithium (Li) has only one valence electron in its second shell. By transferring this lone electron to another atom, lithium's electron configuration will resemble that of helium (He), with two electrons in its first shell, thus achieving a stable noble gas configuration. This transfer results in the formation of a lithium cation, denoted as Lit, with a charge of 1+.
It is important to note that when lithium becomes a cation, it does not necessarily mean it has a complete valence shell in terms of helium or neon. Instead, it has achieved stability by having a full inner shell, which mimics the noble gas configuration of helium.
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Answers
Answer: No, it does not represent a good separation.
Explanation: Resolution is the measure of extent of separation between two components and the base-line separation. It is calculated using the formula
Where, = resolution
= Difference between the retention times of two components.
= Spot widths of two components.
The perfect resolution is considered as 100.
Here, we are given that the two components in a mixture both have a resolution at 2.0 that means both the peaks are overlapping each other and thus the components cannot be determined accurately.
Thus, this does not represent a good separation as as the two components are spotted closely.
Final answer:
A resolution of 2.0 in TLC separation indicates good separation, as values of 1.0 or higher are generally acceptable. It demonstrates that the mixture's components have been well resolved on the chromatogram, and each component can be distinctly identified.
Explanation:
A resolution of 2.0 in TLC separation indicates good separation of a two-component mixture. In chromatography, resolution measures how well two components in a mixture are separated based on their differences in migration rates on the chromatogram. A resolution value of 1.0 or above is generally acceptable, with higher values indicating better separation. In your case, a resolution of 2.0 suggests that the two components have been well resolved, with each peak being distinctly separated from the other, allowing for easier identification and quantification.
Additionally, the effectiveness of separation can often be improved by repeating the separation process. This iterative approach is based on the Le Chatelier's principle, which involves upsetting the phase distribution equilibrium to achieve a higher purity product. Such methods are also touched upon when discussing column chromatography and repetitive extraction protocols in automated systems.
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Answers
Answer:
A base pair is a pair of bases that form hydrogen bonds in the double stranded DNA molecule.
- Adenine-thymine: A-T
- Guanine-cytosine: G-C
Replication Process:
- Double strand unwinds.
- New nucleorides line up via base pairing.
- Colvalent bonds link nucleotides together in the new strands.
Explanation:
Answers
Answer:
0.113 M
Explanation:
Since B and D are on opposite sides of the reaction, the concentration of D increases when the concentration of B decreases. The amount by which D increases is determined by the coefficients of B and D in the balanced chemical equation:
[D]=(0.045 M)=0.113 M.
2.phenolphthalein
3.bromcresol green
Answers
In acid it is colourless and in water also colourless
i) Before adding NaOH
ii) After adding 24.00 mL NaOH
Answers
Answer:
i) pH = 0.6990
ii) pH = 2.389
Explanation:
i) Before adding aqueous NaOH, there are 25.00 mL of 0.2000 M HCl. HCl reacts with the water in the aqueous solution as follows:
HCl + H₂O ⇒ H₃O⁺ + Cl⁻
The HCl and H₃O⁺ are related to each other through a 1:1 molar ratio, so the concentration of H₃O⁺ is equal to the HCl concentration.
The pH is related to the hydronium ion concentration as follows:
pH = -log([H₃O⁺]) = -log(0.2000) = 0.699
ii) Addition of NaOH causes the following reaction:
H₃O⁺ + NaOH ⇒ 2H₂O + Na⁺
The H₃O⁺ and NaOH react in a 1:1 molar ratio. The amount of NaOH added is calculated:
n = CV = (0.2000 mol/L)(24.00 mL) = 4.800 mmol NaOH
Thus, 4.800 mmol of H₃O⁺ were neutralized.
The initial amount of H₃O⁺ present was:
n = CV = (0.2000 mol/L)(25.00 mL) = 5.000 mmol H₃O⁺
The amount of H₃O⁺ that remains after addition of NaOH is:
(5.000 mmol) - (4.800 mmol) = 0.2000 mmol
The concentration of H₃O⁺ is the amount of H₃O⁺ divided by the total volume. The total volume is (25.00 mL) + (24.00 mL ) = 49.00 mL
C = n/V = (0.2000 mmol) / (49.00 mL) = 0.004082 M
The pH is finally calculated:
pH = -log([H₃O⁺]) = -log(0.004082) = 2.389