Chemical energy is the energy that is stored or released during a chemical reaction. It exists within the chemical bonds of molecules and can be converted into other forms of energy.
Chemical energy refers to the energy that is stored or released during a chemical reaction. It is a form of potential energy that exists within the chemical bonds of molecules. When a chemical reaction takes place, these bonds are broken or formed, resulting in the release or absorption of energy.
For example, when a fuel such as gasoline is burned, the chemical energy stored in the hydrocarbon molecules is converted into heat and light energy. Similarly, during photosynthesis, plants convert sunlight into chemical energy in the form of glucose.
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Explanation:
Chemical energy
Chemical energy is energy stored in the bonds of chemical compounds, like atoms and molecules. This energy is released when a chemical reaction takes place.
Usually, once chemical energy has been released from a substance, that substance is transformed into a completely new substance.
The theoretical yield : = 10.251 g
Given
Reaction
3H₂(g)+N₂(g)→2NH₃(g)
1.81 g H₂
10.2 g N₂
2.19 g NH₃
Required
The theoretical yield
Solution
Find limiting reactant :
H₂ : 1.81 g : 2 g/mol = 0.905 mol
N₂ : 10.2 g : 28 g/mol = 0.364 mol
mol : coefficient
H₂ = 0.905 : 3 = 0.302
N₂ = 0.364 : 1 = 0.364
H₂ as a limiting reactant(smaller ratio)
Moles NH₃ based on H₂, so mol NH₃ :
= 2/3 x mol H₂
= 2/3 x 0.905
=0.603
Mass NH₃ :
= mol x MW
=0.603 x 17 g/mol
= 10.251 g
Explanation:
Colloidal solutions, or colloidal suspensions, are nothing but a mixture in which the substances are regularly suspended in a fluid. ... Colloidal systems can occur in any of the three key states of matter gas, liquid or solid. However, a colloidal solution usually refers to a liquid concoction.
Answer:
Colloidal solutions, or colloidal suspensions, are nothing but a mixture in which the substances are regularly suspended in a fluid.
The formula for osmotic pressure is:
where is osmotic pressure, is van't Hoff's factor, molarity, is Ideal gas constant, and T is Temperature.
= 132 atm
The van't Hoff's factor for glucose, = 1
Substituting the values in the above equation we get,
So, the molarity of the solution is .
Answer:
70.88 mL volume of 1.27 M of HCl is required.
Explanation:
Given data:
Initial volume = ?
Initial molarity = 1.27 M
Final volume = 197.4 mL
Final molarity = 0.456 M
Solution:
Formula:
M₁V₁ = M₂V₂
Now we will put the values in formula.
1.27 M × V₁ = 0.456 M × 197.4 mL
V₁ = 0.456 M × 197.4 mL/1.27 M
V₁ = 90.014M.mL/1.27 M
V₁ = 70.88 mL
70.88 mL volume of 1.27 M of HCl is required.
To prepare 197.4 mL of 0.456 M HCl from 1.27 M HCl, you need 71.03 mL of 1.27 M HCl.
The subject of this problem involves using the concept of molarity in Chemistry. We can use a simple formula for dilution, M1V1 = M2V2, to find the volume. Here M1 (1.27 M) is the molarity of stock HCl, V1 is the required volume, M2 (0.456 M) is the desired molarity, and V2 (197.4 mL) is the volume of the solution. Solving for V1, we get V1 = M2V2 / M1 = (0.456 M * 197.4 mL) / 1.27 M = 71.03 mL. Therefore, 71.03 mL of 1.27 M HCl is needed to prepare 197.4 mL of 0.456 M HCl.
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Answer:
164 g
Explanation:
When a student mixes 5.00 g of NH4NO3 with 50.0 mL of water in a coffee-cup calorimeter, the temperature of the resultant solution decreases from 22.0 °C to 16.5 °C. Assume the density of water is 1.00 g/ml and the specific heat capacity of the resultant solution is 4.18 J/g·°C.
1) Calculate q for the reaction. You must show your work.
2) Calculate the number of moles of NH4NO3(s) which reacted. You must show your work.
3) Calculate ΔH for the reaction in kJ/mol. You must show your work.
Answer:
Explanation:
NH₄NO₃ = NH₄⁺ +NO₃⁻
heat released by water = msΔ T
m is mass , s is specific heat and ΔT is fall in temperature
= 50 x 4.18 x ( 22 - 16.5 ) ( mass of 50 mL is 50 g )
= 1149.5 J .
This heat will be absorbed by the reaction above .
q for the reaction = + 1149.5 J
2 )
molecular weight of NH₄NO₃ = 80
No of moles reacted = 5/80 = 1 / 16 moles.
3 )
5 g absorbs 1149.5 J
80 g absorbs 1149.5 x 16 J
= 18392 J
= 18.392 kJ.
= + 18.392 kJ
ΔH = 18.392 kJ / mol