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If u trust urself do itStudy these images.

4 photos of clouds. 1: Sky covered with large, flat layers of blue, grey clouds. 2: A tall, fluffy cloud shaped like an anvil. 3: Round, puffy clouds in a blue sky. 4: Thin, wispy clouds high in the sky.

Which image shows a cumulonimbus cloud?

1
2
3

Answers

Answer 1

Answer:

Answer:

Explanation:

Edge 2021

Answer 2

Answer:

Answer:

Explanation:

I wish you the best, its three or 2

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Explain the arrangement of the first 20 elements in the periodic table. Please help! Will give brainliest!

Boyd takes additional measurements of the mass of product formed in a reaction. He uses a balance that has smaller graduations than the first balance he used. What is Boyd most likely trying to change?
He is trying to increase his accuracy but not his precision.
He is trying to increase his precision but not his accuracy.
He is trying to decrease his precision and increase his accuracy.
He is trying to increase his precision and decrease his accuracy.

apparently not He is trying to increase his accuracy but not his precision.

Answers

Boyd is most likely trying to increase his accuracy but not his precision. Therefore, option A is correct.

What are accuracy and precision?

Accuracy and precision can be described as two measures of observational error. Accuracy can be defined as how close a given set of measurements, are to their true value, while precision can be defined as how close the measurements are with respect to each other.

In other words, precision can be considered a description of random errors, as well as a measure of statistical variability. Accuracy is a description of systematic errors while low accuracy can bring a difference between a result and a true value.

Accuracy as describing a combination of both kinds of observational error, so high accuracy needs both high precision and high trueness.

In simpler terms, given a set of data points from repeated measurements of the same amount, the sample can be said to be accurate if its average is close to the true value being measured.

Learn more about accuracy and precision, here:

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Answer:

The answer is D) He is trying to increase his accuracy and precision.

Explanation:

edg2020

hope this helped :)

Ne belongs to what group. a. noble gases, b.alkali metals, c. halogens, d. alkaline earth metals

Answers

The answer is A hope this helps

When radioactive uranium decays to produce thorium, it also emits a particle. As seen in the balanced nuclear equation, this particle can BEST be described asA) a helium atom.
B) an alpha particle or a helium atom.
C) a beta particle or a hydrogen nucleus.
D) an alpha particle or a helium nucleus.

Answers

The radioactive uranium decays to produce thorium and it emits an alpha particle or helium atom. Thus, option A is correct.

What is radioactive decay?

Unstable heavy isotopes of elements undergo nuclear decay to produce stable atoms by the emission of charged particle such as alpha or beta particles.

Based on the emitted particle, there are two types of decay process namely alpha decay and beta decay. In alpha decay atoms emits alpha particles which are helium nuclei and the atom losses its mass number by 4 units and atomic number by two units,

In beta decay, electrons are emitted by the atom, where no change occurs in mass number and atomic number increases by one unit. Uranium undergo alpha decay by emitting alpha particle or helium nuclei.

To find more on alpha decay, refer here:

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You’re answer would be D love!

A compound contains only carbon, hydrogen, and oxygen. Combustion of 139.1 g of the compound yields 208.6 g of CO2 and 56.93 g of H2O. The molar mass of the compound is 176.1 g/mol. *Each part of this problem should be submitted separately to avoid losing your work* 1. Calculate the grams of carbon (C) in 139.1 g of the compound: grams 2. Calculate the grams of hydrogen (H) in 139.1 g of the compound. grams 3. Calculate the grams of oxygen (O) in 139.1 g of the compound. grams

Answers

Answer:

1. Mass of Carbon is 56.89g

2. Mass of Hydrogen is 6.33g

3. Mass of Oxygen is 75.88

Explanation:

The following were obtained from the question.

Mass of the compound = 139.1g

Mass of CO2 produced = 208.6g

Mass of H2O produced = 56.93

1. Determination of mass of Carbon (C). This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 208.6

Mass of C = 56.89g

2. Determination of the mass of Hydrogen (H). This is illustrated below:

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H = 2/18 x 56.93

Mass of H = 6.33g

3. Determination of the mass of oxygen (O).

This is illustrated below:

Mass of the compound = 139.1g

Mass of C = 56.89g

Mass of H = 6.33g

Mass of O = Mass of compound - (mass of C + Mass of H)

Mass of O = 139.1 - (56.89 + 6.33)

Mass of O = 139.1 - 63.22

Mass of O = 75.88

Given the following equation: 8 Fe + S8 ---> 8 FeSHow many moles of iron are needed to react with 16.0 moles of sulfur?
A FULL STEP EXPLANATION WILL BE APPRECIATED

Answers

The number of moles of iron needed to react with 16.0 moles of sulfur is 128.0 moles.

Calculation of number of moles of iron

Given equation, 8Fe + S8 = 8 FeS

Moles of sulfur = 16.0

To react 1 mole of sulfur, we need 8 moles of Fe

So, for 16.0 moles of sulfur we need

$16.0* 8 = 128.0 moles$

Thus, to react with 16.0 moles of Sulfur, 128.0 moles of Fe is needed.

Learn more about sulfur, here:

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Answer:

To react with 16.0 moles of sulfur we need 128.0 moles of iron (Fe).

Explanation:

Step 1: Data given

Number of moles Sulfur = 16.0 moles

Step 2: The balanced equation

8 Fe + S8 → 8 FeS

Step 3: Calculate mole Fe

For 8 moles Fe we need 1 mol S8 to produce 8 moles FeS

For 16.0 moles of Sulfur we need 8*16.0 = 128.0 moles

To react with 16.0 moles of sulfur we need 128.0 moles of iron (Fe).

Calculate the pH of a solution prepared by adding 20.0 mL of 0.100 M HCl to 80.0 mL of a buffer that is comprised of 0.25 M C2H5NH2 and 0.25 M C2H5NH3Cl. Kb of C2H5NH2 = 9.5 x 10-4.

Answers

Answer: The pH of resulting solution is 10.893

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}* 1000}{\text{Volume of solution (in mL)}}$

For ethylamine:

Molarity of ethylamine solution = 0.25 M

Volume of solution = 80 mL

Putting values in above equation, we get:

$0.25M=\frac{\text{Moles of ethylamine}* 1000}{80mL}\n\n\text{Moles of ethylamine}=(0.25* 80)/(1000)=0.02mol$

For HCl:

Molarity of HCl = 0.100 M

Volume of solution = 20.0 mL

Putting values in above equation, we get:

$0.100M=\frac{\text{Moles of HCl}* 1000}{20.0mL}\n\n\text{Moles of HCl}=(0.100* 20)/(1000)=0.002mol$

For $C_2H_5NH_3Cl$ :

Molarity of $C_2H_5NH_3Cl$ solution = 0.25 M

Volume of solution = 80 mL

Putting values in above equation, we get:

$0.25M=\frac{\text{Moles of }C_2H_5NH_3Cl* 1000}{80mL}\n\n\text{Moles of }=(0.25* 80)/(1000)=0.02mol$

The chemical reaction for ethylamine and HCl follows the equation:

$C_2H_5NH_2+HCl\rightarrow C_2H_5NH_3Cl$

Initial: 0.02 0.002 0.02

Final: 0.018 - 0.022

Volume of solution = 20.0 + 80.0 = 100 mL = 0.100 L (Conversion factor: 1 L = 1000 mL)

To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:

$pOH=pK_b+\log(([salt])/([base]))$

$pOH=pK_b+\log(([C_2H_5NH_3Cl])/([C_2H_5NH_2]))$

We are given:

$pK_b$ = negative logarithm of base dissociation constant of ethylamine = $-\log(9.5* 10^(-4))=3.02$

$[C_2H_5NH_3Cl]=(0.022)/(0.100)$

$[C_2H_5NH_2]=(0.018)/(0.100)$

pOH = ?

Putting values in above equation, we get:

$pOH=3.02+\log((0.022/0.100)/(0.018/0.100))\n\npOH=3.107$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\npH=14-3.107=10.893$

Hence, the pH of the solution is 10.893

The pH of the solution is 10.9

Data;

Volume of buffer = 80mL
Volume of HCL = 20.0mL
conc. of C2H5NH2 = 0.25M
conc. of C2H5NH3Cl = 0.25
Kb of C2H5NH2 = 9.5*10^-4

pH of a Solution

The pH of buffer can be calculated by using Henderson-Hasselbalch's equation

$pOH = _pKb+ log ([salt])/([base])$

The initial moles of salt present is calculated as

$0.25 * 80*10^-^3 = 0.02mmoles$

The initial moles of base present is calculated as

$0.25*80*10^-^3 = 20mmoles$

On adding HCl the following reaction will occurs

$C_2H_5NH_2 + HCl \to C_2H_5NH_3Cl$

This will lead to formation of extra moles of salt that is equal to moles of acid added and eventually lead to decrease in number of moles of base by equal measure.

Moles of HCl added is

$moles of HCL= 0.1 * 20 * 10^-^3 = 2mmoles$