Taking into account the Charles's law, the same amount of gas at the same pressure and 55 ∘C would occupy a volume of 26.91 L.
Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure.
This law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
Studying an initial state 1 and a final state 2, it is satisfied:
In this case, you know:
Replacing:
Solving:
V2= 26.91 L
Finally, the same amount of gas at the same pressure and 55 ∘C would occupy a volume of 26.91 L.
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Answer:26.9L
Explanation: this is Charles' law which states that the volume of a gas is directly proportional to the absolute temperature at contant pressure. The expression is V1/T1 = V2/T2
Making V2 the subject of the formula we have
V2 = V1 xT2/T1
= 22.4 x 328/273
= 26.9L
b)Ca(OH)2
c)C12H22O11
d)CH3OH
"0.154 L" is the volume of the balloon.
Given:
Pressure,
Volume,
As we know,
→
or,
→
By substituting the values, we get
Thus the above answer i.e., "option a" is correct.
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Answer:
Option a . 0.154L
Explanation:
P₁ . V₁ = P₂ . V₂
when we have constant temperature and constant moles for a certain gas.
At sea level, pressure is 1 atm so:
0.5 L . 1atm = V₂ . 3.25 atm
(0.5L . 1atm) / 3.25 atm = 0.154 L
B) 1.77 m
C) 6.39 m
D) 2.41 m
E) none of these
Answer: D) 2.41 m
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
where,
n = moles of solute
= weight of solvent in kg
moles of solute =
volume of solution = 1L = 1000 ml (1L=1000ml)
Mass of solution=
mass of solute = 292 g
mass of solvent = mass of solution - mass of solute = (1108- 292) g = 816g = 0.816 kg
Now put all the given values in the formula of molality, we get
Therefore, the molality of solution will be 2.41 mole/kg
In this problem, we calculate molality by using the given mass of the solute, the mass of the solvent, and the molar mass of the solute. After performing the necessary calculations, we find that the molality is 2.41 m.
The subject of this student's question is molality, which is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per kilogram of solvent. To find the molality (m), we need to know the mass of the solute and the mass of the solvent in the solution.
Given, that the solution contains 292g of Mg(NO3)2 per liter (which is the mass of the solute). The density of the solution is 1.108g/mL. We know that 1L = 1000mL, so the mass of the solution is density x volume = 1.108g/mL x 1000mL = 1108g.
We need to find the mass of the solvent (water). The mass of the solution is the mass of the solute + the mass of the solvent. So, the mass of the solvent is 1108g(mass of the solution) - 292g(mass of solute) = 816g or 0.816gkg.
The molar mass of Mg(NO3)2 is 148.31452 g/mol. So, the number of moles of Mg(NO3)2 in the solution is moles = mass / molar mass = 292g / 148.31452 g/mol = 1.97 moles.
Now we can calculate molality (m) = moles of solute/mass of solvent in kg = 1.97 moles / 0.816 kg = 2.41 m. Therefore, the answer is D) 2.41 m.
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Answer:
C) plasma
Explanation:
Plasma is the state where electrons are stripped allow these gases to conduct electricity.