Station 9: Iodine ______________ g I2 Perform the calculations in the space between each lettered problem. Enter the answer with correct significant figures and units on the line provided.

Answers

Answer 1
Answer:

Answer:

a) Moles of iodine molecules = 0.0748 moles of Iodine molecules

b) Moles of iodine atoms = 0.150 moles of iodine atoms

c) Number of iodine atoms = 9.03 * 10²² atoms

d) Number of iodine molecules = 4.50 * 10²² molecules

Note: The complete question is found in the attachment below.

Explanation:

a. Number of moles of iodine molecules in 19.0 g of I₂

Molar mass of iodine molecule = 2 * 127 g/mol = 254g/mol

Number of moles = mass / molar mass

Number of moles = 19.0 g / 254 g/mol

Moles of iodine molecules = 0.0748 moles of Iodine molecules

b) Number of moles of iodine atoms

I mole of iodine molecules contains 2 moles of iodine atoms

Therefore, 0.0748 moles of iodine molecules will contain 2 * 0.0748 moles of iodine atoms

Moles of iodine atoms = 0.150 moles of iodine atoms

c) Number of iodine atoms = number of moles of iodine atoms * 6.02 * 10²³

Number of iodine atoms = 0.150 * 6.02 * 10²³

Number of iodine atoms = 9.03 * 10²² atoms

d) Number of iodine molecules = number of moles of iodine molecules * 6.02 * 10²³

Number of iodine molecules = 0.0748 * 6.02 * 10²³

Number of iodine molecules = 4.50 * 10²² molecules


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Name the physical properties used in seperating kerosene and petrol

Answers

step by step explanation

simple distillation can be used when the temperature difference between the boiling points of two miscible liquid is at least 25°c. the temperature difference between the boiling points of kerosene and petrol is 25c. hence, this mixture can separated using simple distillation.

answer:

simple distillation

A cylinder is filled with 10.0L of gas and a piston is put into it. The initial pressure of the gas is measured to be 96.0kPa. The piston is now pulled up, expanding the gas, until the gas has a final volume of 45.0L. Calculate the final pressure of the gas. Be sure your answer has the correct number of significant digits.

Answers

Answer:

The final pressure of the gas is:- 21.3 kPa

Explanation:

Using Boyle's law  

{P_1}* {V_1}={P_2}* {V_2}

Given ,  

V₁ = 10.0 L

V₂ = 45.0 L

P₁ = 96.0 kPa

P₂ = ?

Using above equation as:

{P_1}* {V_1}={P_2}* {V_2}

{96.0\ kPa}* {10.0\ L}={P_2}* {45.0\ L}

{P_2}=\frac {{96.0}* {10.0}}{45.0}\ kPa

{P_2}=21.3\ kPa

The final pressure of the gas is:- 21.3 kPa

Compare and contrast how observations and results can be used tosupport a conclusion to an experiment.

Answers

Answer:

by statistical analyses, especially by determining the p-value

Explanation:

In general, observations and results obtained from experimental procedures are subjected to a statistical test to check the robustness of the working hypothesis. The p-value is the most widely used statistical index in order to test such observations and results. The p-value is the statistical probability of obtaining extreme observed results when the null hypothesis is considered correct. A p-value lesser than 0.05 generally is considered statistically significant and then the null hypothesis can be rejected. In consequence, a very low p-value (which is obtained by statistical analysis of the observations and results), indicates that there is strong evidence in support of the alternative hypothesis.

A first-order decomposition reaction has a rate constant of 0.00140 yr−1. How long does it take for [reactant] to reach 12.5% of its original value? Be sure to report your answer to the correct number of significant figures.

Answers

Reactants take 504.87 yr to reach 12.5% of their original value in first-order decomposition reaction.

Equation for the first-order decomposition reaction:-

A_(t) =A_(0) e^(-kt)....(1)

Here,  A_(t) is the final concentration, t is the time,  A_(0) is the initial concentration, and k is the rate constant.

Given:-

A_(t) =0.125A_(0)

k= 0.00140yr^(-1)

Substitute the above value in equation (1) as follows:-

0.125A_(0) =A_(0) e^(-kt) \n0.125A_(0) =A_(0) e^{-k*0.00140 yr^(-1) }\nln(0.125)/(-0.00140)=t\nt=504.87 year

So, 504.87 yr does it take for the reactant to reach 12.5% of its original value.

Find more information about first- order decomposition reaction here:-

brainly.com/question/20607444

Final answer:

The time required for a reactant to reach 12.5% of its original value in a first-order reaction is approximately 1482 years, obtained by applying the formula for the half-life of a first-order reaction and multiplying by 3.

Explanation:

In a first-order reaction, the half-life of the reaction, which is the time it takes for half of the reactant to be consumed, is independent of the concentration of the reactant. Also, for a first-order reaction, it would take approximately 3 half-lives for the reactant to be reduced to 12.5% of its original value. The Integrated Rate Law for a First-Order Reaction can be applied to determine the time it will take.

Given the rate constant (k) is 0.00140 yr¯¹, we will use the formula for the half-life of a first-order reaction: t₁/₂ = 0.693 / k. After calculating the half-life (t₁/₂), multiply it by 3 to determine the time for the reactant concentration to reach 12.5% of its original value. Hence, it would take approximately 1482 years to reach 12.5% of the original value when rounded to the correct number of significant figures.

Learn more about First Order Reaction here:

brainly.com/question/1769080

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I need soon this is due at 10:30 pm its curently 6:00 pm
What is parasitism?

Answers

Answer:

the practice of living as a parasite in or on another organism.

Hope this HELPS!!!

Explanation:

Assuming 54.81 grams of Al are consumed in the presence of excess copper II chloride dihydrate, how many grams of AlCl3 can be produced if the reaction will only produce 66.93 % yield?

Answers

Answer:

181.39g of AlCl3 is produced

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3CuCl2•2H2O + 2Al → 2AlCl3 + 6H2O + 3Cu

Next, we shall determine the mass of Al that reacted and the mass of AlCl3 produced from the balanced equation. This is illustrated below:

Molar mass of Al = 27g/mol

Mass of Al from the balanced equation = 2 x 27 = 54g

Molar mass of AlCl3 = 27 + (3x35.5) = 133.5g/mol

Mass of AlCl3 from the balanced equation = 2 x 133.5 = 267g

Summary:

From the balanced equation above,

54g of Al reacted to produce 267g of AlCl3.

Next, we shall determine the theoretical yield of AlCl3. This can be achieved as shown below:

From the balanced equation above,

54g of Al reacted to produce 267g of AlCl3.

Therefore, 54.81g of Al will react to produce = (54.81 x 267)/54 = 271.01g of AlCl3.

Therefore, the theoretical yield of AlCl3 is 271.01g.

Finally, we shall determine the actual yield of AlCl3 produced from the reaction.

This can be obtain as follow:

Percentage yield of AlCl3 = 66.93%

Theoretical yield of AlCl3 = 271.01g

Actual yield of AlCl3 =?

Percentage yield = Actual yield/Theoretical yield x 100

66.93% = Actual yield /271.01g

Actual yield = 66.93% x 271.01

Actual yield = 66.93/100 x 271.01g

Actual yield = 181.39g.

Therefore, 181.39g of AlCl3 is produced from the reaction.