Answer:
a) Moles of iodine molecules = 0.0748 moles of Iodine molecules
b) Moles of iodine atoms = 0.150 moles of iodine atoms
c) Number of iodine atoms = 9.03 * 10²² atoms
d) Number of iodine molecules = 4.50 * 10²² molecules
Note: The complete question is found in the attachment below.
Explanation:
a. Number of moles of iodine molecules in 19.0 g of I₂
Molar mass of iodine molecule = 2 * 127 g/mol = 254g/mol
Number of moles = mass / molar mass
Number of moles = 19.0 g / 254 g/mol
Moles of iodine molecules = 0.0748 moles of Iodine molecules
b) Number of moles of iodine atoms
I mole of iodine molecules contains 2 moles of iodine atoms
Therefore, 0.0748 moles of iodine molecules will contain 2 * 0.0748 moles of iodine atoms
Moles of iodine atoms = 0.150 moles of iodine atoms
c) Number of iodine atoms = number of moles of iodine atoms * 6.02 * 10²³
Number of iodine atoms = 0.150 * 6.02 * 10²³
Number of iodine atoms = 9.03 * 10²² atoms
d) Number of iodine molecules = number of moles of iodine molecules * 6.02 * 10²³
Number of iodine molecules = 0.0748 * 6.02 * 10²³
Number of iodine molecules = 4.50 * 10²² molecules
simple distillation can be used when the temperature difference between the boiling points of two miscible liquid is at least 25°c. the temperature difference between the boiling points of kerosene and petrol is 25c. hence, this mixture can separated using simple distillation.
simple distillation
Answer:
The final pressure of the gas is:- 21.3 kPa
Explanation:
Using Boyle's law
Given ,
V₁ = 10.0 L
V₂ = 45.0 L
P₁ = 96.0 kPa
P₂ = ?
Using above equation as:
The final pressure of the gas is:- 21.3 kPa
Answer:
by statistical analyses, especially by determining the p-value
Explanation:
In general, observations and results obtained from experimental procedures are subjected to a statistical test to check the robustness of the working hypothesis. The p-value is the most widely used statistical index in order to test such observations and results. The p-value is the statistical probability of obtaining extreme observed results when the null hypothesis is considered correct. A p-value lesser than 0.05 generally is considered statistically significant and then the null hypothesis can be rejected. In consequence, a very low p-value (which is obtained by statistical analysis of the observations and results), indicates that there is strong evidence in support of the alternative hypothesis.
Reactants take 504.87 yr to reach 12.5% of their original value in first-order decomposition reaction.
....(1)
Here, is the final concentration, t is the time, is the initial concentration, and k is the rate constant.
Given:-
k=
Substitute the above value in equation (1) as follows:-
So, 504.87 yr does it take for the reactant to reach 12.5% of its original value.
Find more information about first- order decomposition reaction here:-
The time required for a reactant to reach 12.5% of its original value in a first-order reaction is approximately 1482 years, obtained by applying the formula for the half-life of a first-order reaction and multiplying by 3.
In a first-order reaction, the half-life of the reaction, which is the time it takes for half of the reactant to be consumed, is independent of the concentration of the reactant. Also, for a first-order reaction, it would take approximately 3 half-lives for the reactant to be reduced to 12.5% of its original value. The Integrated Rate Law for a First-Order Reaction can be applied to determine the time it will take.
Given the rate constant (k) is 0.00140 yr¯¹, we will use the formula for the half-life of a first-order reaction: t₁/₂ = 0.693 / k. After calculating the half-life (t₁/₂), multiply it by 3 to determine the time for the reactant concentration to reach 12.5% of its original value. Hence, it would take approximately 1482 years to reach 12.5% of the original value when rounded to the correct number of significant figures.
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What is parasitism?
Answer:
the practice of living as a parasite in or on another organism.
Hope this HELPS!!!
Explanation:
Answer:
181.39g of AlCl3 is produced
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
3CuCl2•2H2O + 2Al → 2AlCl3 + 6H2O + 3Cu
Next, we shall determine the mass of Al that reacted and the mass of AlCl3 produced from the balanced equation. This is illustrated below:
Molar mass of Al = 27g/mol
Mass of Al from the balanced equation = 2 x 27 = 54g
Molar mass of AlCl3 = 27 + (3x35.5) = 133.5g/mol
Mass of AlCl3 from the balanced equation = 2 x 133.5 = 267g
Summary:
From the balanced equation above,
54g of Al reacted to produce 267g of AlCl3.
Next, we shall determine the theoretical yield of AlCl3. This can be achieved as shown below:
From the balanced equation above,
54g of Al reacted to produce 267g of AlCl3.
Therefore, 54.81g of Al will react to produce = (54.81 x 267)/54 = 271.01g of AlCl3.
Therefore, the theoretical yield of AlCl3 is 271.01g.
Finally, we shall determine the actual yield of AlCl3 produced from the reaction.
This can be obtain as follow:
Percentage yield of AlCl3 = 66.93%
Theoretical yield of AlCl3 = 271.01g
Actual yield of AlCl3 =?
Percentage yield = Actual yield/Theoretical yield x 100
66.93% = Actual yield /271.01g
Actual yield = 66.93% x 271.01
Actual yield = 66.93/100 x 271.01g
Actual yield = 181.39g.
Therefore, 181.39g of AlCl3 is produced from the reaction.