Answer:
1. The coefficients are: 1, 3, 2
2. From the balanced equation, we obtained the following:
3 moles oxygen, O2 reacted.
2 moles of Hydrogen sulfide, H2S reacted.
2 moles of water were produced.
2 moles of sulphur dioxide, SO2 were produced.
Explanation:
1. Determination of the coefficients of the equation.
This is illustrated below:
P2O5(s) + H2O(l) <==> H3PO4(aq)
There are 2 atoms of P on the left side and 1 atom on the right side. It can be balance by putting 2 in front of H3PO4 as shown below:
P2O5(s) + H2O(l) <==> 2H3PO4(aq)
There are 2 atoms of H on the left side and 6 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
P2O5(s) + 3H2O(l) <==> 2H3PO4(aq)
Now the equation is balanced.
The coefficients are: 1, 3, 2.
2. We'll begin by writing the balanced equation for the reaction. This is given below:
2H2S(g) + 3O2(g) => 2H2O(l) + 2SO2(g)
From the balanced equation above,
3 moles of oxygen, O2 reacted with 2 moles of Hydrogen sulfide, H2S to produce 2 moles of water, H2O and 2 moles of sulphur dioxide, SO2.
In the balanced chemical equation provided, 3 moles of oxygen react with 2 moles of hydrogen sulfide to produce 2 moles of water and 2 moles of sulfur dioxide.
When the balanced chemical equation 2H2S(g) + 3O2(g) =2H2O(l) + 2SO2(g) is considered, we can deduce that 3 moles of oxygen and 2 moles of hydrogen sulfide react together in this reaction. The products of this chemical reaction are 2 moles of water and 2 moles of sulfur dioxide. Each of these quantities is directly inferred from the coefficients in front of each compound in the balanced chemical equation.
B. 161 kPa
C. 16 kPa
D. 41 kPa
Answer:
A. 60 kPa
Explanation:
P2 = p1 times t2 / t1
Answer:
joe mama
Explanation:
400 + 20 + 420
OB. only the important elements that exist in the world.
OC. only the important compounds that exist in the world.
OA. all the known elements that exist in the world today.
The percent composition of nitrogen in sodium nitride is 16.86%
Sodium nitride is an inorganic compound that is used in preservatives and antidote for cyanide poisoning.
The molar mass of Na3N is 83 M
The mass of Na3N is 14 g
Thus, the percent composition of nitrogen in sodium nitride is 16.86%.
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Answer:
16.86%
Explanation:
Na3N is sodium nitride.
% of N = mass of N/ molar mass of Na3N *100
% of N = 14/83*100= 16.86%
Answer:
9.09
Explanation:
Please kindly check attachment for the step by step solution of the given problem.