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KOH(Ac) + HNO3 → KNO3(Ac) + H2O
cual es su reacio

Answers

Answer 1
Answer:

Answer:

corbonization for dictionnal

Explanation:

correct

Answer 2
Answer:

Answer:

neutralization reaction forms water and salt , neutralization is the reaction!

Explanation:

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Redox reactions stand for oxidation/reduction reactions. True or false: an oxidation reaction is always paired with a reduction reaction.
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QUESTION 2: The molar mass for this compound is 1.11g / m * o * l The molecular formula for this compound is

Answers

I need the percentage again dude

Solve for x . 875 = 5 x 3 Express the answer to the hundredths place (i.e., two digits after the decimal point).

Answers

Answer : The value of 'x' for this expression is, 5.59

Explanation :

The given expression is:

875=5x^3

Now we have to determine the value of 'x' by solving the above expression.

875=5x^3

(875)/(5)=x^3

175=x^3

x=(175)^(1/3)

x=5.59

Thus, the value of 'x' for this expression is, 5.59

When a liquid sample is taken from sea level to a higher elevation, what happens to the external (atmospheric) pressure on the liquid and the boiling point of the liquid

Answers

Answer:

The external atmospheric pressure decreases and so does the boiling point of the liquid.

Explanation:

We know that pressure decreases with height. Thus atmospheric pressure decreases at higher elevation.

The implication of this is that, if I take a liquid from sea level to a higher elevation, the external atmospheric pressure on the liquid will decrease and so does its boiling point.

Hence, the liquid boils at a lower temperature when placed at a higher elevation. For this reason, the boiling point of a liquid is lower on the mountain.

What is the chemical formula for the ionic compound formed by Au3+ and
HSO3-?

Answers

Answer:

The chemical formula for the ionic compound formed by Au3+ and

HSO3-compound  is Au(HSO3)3

Explanation:

The charge on Au ion is +3

And the charge on HSO3- is -1

Thus, the number of atoms required by HSO3- to complete its octate is 1. On the other hand Au has 3 excess ions and hence it is to be released to reach the stable state.

So three molecules of HSO3- will combine with one atom of Au 3+

Thus, the compound formed by these two is Au(HSO3)3

Final answer:

The chemical formula for the ionic compound formed by Au3+ and HSO3- is Au(HSO3)3, as ionic compounds are always neutral.

Explanation:

The ionic compound formed by Au3+ (Gold ion) and HSO3- (Bisulfite ion) must have a net charge of zero since ionic compounds are neutral. Hence, we need 3 bisulfite ions to balance out one gold ion, which gives us the chemical formula as Au(HSO3)3.

Indeed, the formation of ionic compounds is a fascinating process. It involves the transfer of electrons from one atom (usually a metal) to another (usually a nonmetal), resulting in the formation of ions. These ions are then attracted to each other due to their opposite charges, forming an ionic compound. In this case, the gold ion (Au3+) donates three electrons, which are accepted by three bisulfite ions (HSO3-). This results in a neutral compound, as the positive and negative charges balance each other out. The resulting compound, Au(HSO3)3, is an example of how elements can combine in specific ratios to form neutral compounds.

Learn more about Chemical Formula here:

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A sample of gas has an initial volume of 3.00 L and an initial pressure of 2.14 atm. If the volume expands to 8.15 L, what is the final pressure?a. 0.855 atm b. 0.788 atm c. 3.49 atm d. 5.81 atm

Answers

Answer:

The final pressure is 0.788 atm (option b).

Explanation:

Boyle's law says that the volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure. That is: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases. This is expressed mathematically as the product of pressure times volume equal to a constant value:

P*V=k

Assuming a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1*V1=P2*V2

In this case:

  • P1= 2.14 atm
  • V1= 3 L
  • P2= ?
  • V2= 8.15 L

Replacing:

2.14 atm*3 L= P2* 8.15 L

Solving:

(2.14 atm*3 L)/(8.15 L) =P2

0.788 atm= P2

The final pressure is 0.788 atm (option b).

A student dissolved 1.805g of a monoacidic weak base in 55mL of water. Calculate the equilibrium pH for the weak monoacidic base (B) solution. Show all your work.pKb for the weak base = 4.82.

Molar mass of the weak base = 82.0343g/mole.

Note: pKa = -logKa

pKb = -logKb

pH + pOH = 14

[H+ ] [OH- ] = 10^-14

Answers

Answer:

11.39

Explanation:

Given that:

pK_(b)=4.82

K_(b)=10^(-4.82)=1.5136* 10^(-5)

Given that:

Mass = 1.805 g

Molar mass = 82.0343 g/mol

The formula for the calculation of moles is shown below:

moles = (Mass\ taken)/(Molar\ mass)

Thus,

Moles= (1.805\ g)/(82.0343\ g/mol)

Moles= 0.022\ moles

Given Volume = 55 mL = 0.055 L ( 1 mL = 0.001 L)

Molarity=(Moles\ of\ solute)/(Volume\ of\ the\ solution)

Molarity=(0.022)/(0.055)

Concentration = 0.4 M

Consider the ICE take for the dissociation of the base as:

                                  B +   H₂O    ⇄     BH⁺ +        OH⁻

At t=0                        0.4                          -              -

At t =equilibrium     (0.4-x)                        x           x            

The expression for dissociation constant is:

K_(b)=\frac {\left [ BH^(+) \right ]\left [ {OH}^- \right ]}{[B]}

1.5136* 10^(-5)=\frac {x^2}{0.4-x}

x is very small, so (0.4 - x) ≅ 0.4

Solving for x, we get:

x = 2.4606×10⁻³  M

pOH = -log[OH⁻] = -log(2.4606×10⁻³) = 2.61

pH = 14 - pOH = 14 - 2.61 = 11.39
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