Answer:
1. Co ( s ) - metallic bonding
2. CoCl₂ ( s ) - ionic bonding
3. CCl₄ ( l ) - covalent bonding
Explanation:
Metallic bonding -
It is the type of bonding present between the atoms of the metals , via the electrostatic interaction between the metal and the delocalized electrons , is known as metallic bonding .
For example ,
Mostly metals show metallic bonding .
Ionic bonding -
It is the type of bonding present between the ions i.e. , the cation and the anion is known as ionic bonding .
For example ,
Mostly ionic compound , like salts show ionic bonding .
Covalent bonding -
It is the type of bonding which is present between shared pair of electrons , is known as covalent bonding .
For example ,
Most of the carbon compounds are capable to show covalent bonding .
Hence , from the question ,
1. Co ( s ) - metallic bonding
2. CoCl₂ ( s ) - ionic bonding
3. CCl₄ ( l ) - covalent bonding
Co(s) forms metallic bonds, CoCl2(s) forms ionic bonds, and CCl4(l) forms covalent bonds.
The type of bonding within each substance can be identified by understanding the nature of the substances.
#SPJ6
Answer:
ΔHrxn = 193107.69 J/mol
Explanation:
ΔHrxn = mcΔT
m = mass
c = heat capacity
ΔT = temperature variation
density = m/V
m = density x V
m = 1.00 g/mL x 400.0 mL
m = 400.0 g
ΔHrxn = mcΔT
ΔHrxn = 400 g x 4.184 J/g°C x 6.00 °C
ΔHrxn = 10041.6 J
CaO + 2HCl → CaCl₂ + H₂O
CaO = 56.0774 g/mol
2.90 g CaO = 0.052 mol
400.0 mL of 1.500 mol/L HCl = 0.6 mol HCl
ΔHrxn = 10041.6 J is for 0.052 mol of CaO
ΔHrxn = 193107.69 J is for 1 mol of CaO
Explanation:
..(1)
Manganese (II) carbonate and oxygen reacts to give manganses (III) oxide with carbon-dioxide gas.
..(2)
Manganese (III) oxide reacts with aluminum metal to give aluminum oxide and manganese metal
On adding (1) and 2(2) we will get the net net chemical equation for the production of manganese. So,
The net balanced equation we got:
The production of manganese from manganese (II) carbonate, oxygen, and aluminum involves two chemical reactions. Heating manganese (II) carbonate with oxygen yields manganese(III) oxide and carbon dioxide. This manganese (III) oxide then reacts with aluminum to produce manganese and aluminum oxide.
The chemical reaction can be described in terms of a net chemical equation after properly balancing the chemicals involved on both sides of the equation. The first step is to understand and correctly write down the formula of reactants and products for the reaction. Here: Manganese (II) Carbonate (MnCO3), Oxygen (O2), and Aluminum (Al).
In the process of manganese production, Manganese (II) Carbonate is first heated in the presence of oxygen to yield Manganese (III) Oxide (Mn2O3) and Carbon Dioxide (CO2):
MnCO3 + 1/2 O2 -> Mn2O3 + CO2.
The resulting Manganese (III) Oxide reacts with Aluminum (which acts as a reducing agent in this case) to generate Manganese and Aluminum Oxide:
3 Mn2O3 + 4 Al -> 6 Mn + 2 Al2O3.
These two equations combined represent the net chemical equation for the production of manganese from manganese (ii) carbonate, oxygen, and aluminum.
#SPJ12
Answer:
I think the second space is chemical bonds
Answer:
Moles of hydrogen formed = 3.5 moles
Explanation:
Given that:-
Moles of aluminium= 4.0 mol
Moles of hydrogen bromide = 7.0 mol
According to the reaction:-
2 moles of aluminum react with 6 moles of hydrogen bromide
1 mole of aluminum react with 6/2 moles of hydrogen bromide
4 moles of aluminum react with (6/2)*4 moles of hydrogen bromide
Moles of hydrogen bromide = 12 moles
Available moles of hydrogen bromide = 7.0 moles
Limiting reagent is the one which is present in small amount. Thus, hydrogen bromide is limiting reagent. (7.0 < 12)
The formation of the product is governed by the limiting reagent. So,
6 moles of hydrogen bromide on reaction forms 3 moles of hydrogen
1 moles of hydrogen bromide on reaction forms 3/6 moles of hydrogen
7 moles of hydrogen bromide on reaction forms (3/6)*7 moles of hydrogen
Moles of hydrogen formed = 3.5 moles
Answer:
3.5 mol H2, HBr (limiting reactant)
Explanation:
4.0 mol Al × 3 mol H2/ 2 mol Al = 6.0 mol H2
7.0 mol HB ×3 mol H2/ 6mol HBr = 3.5 mol H2
Since 7.0mol of HBr will produce less H2 than 4.0mol of Al, HBr will be the limiting reactant, and the reaction will produce 3.5mol of H2.
A) less kinetic energy.
B)
more kinetic energy.
more total energy.
D) the same total energy.
Answer:
its not more kinetic energy i put that and got it wrong
Answer:
Polarity
Cohesion
Adhesion
High Specific Heat
Explanation: