Answer:
d. there is a rearrangement of the electrons in the ball
Explanation:
Inside the neutral metal ball, there are equal no. of positive charges (protons) and negative charges (electrons). Normally, the charges are distributed evenly throughout the ball.
However, when the positively charged insulating rod is brought near, since positive charges and negative charges attract each other, the electrons (-ve charges) in the metal ball moves towards the side nearest to the rod. The metal ball gets attracted to the rod.
a and b are not correct because the rod is insulating, so electrons cannot be transferred between them to induce a net charge in the metal ball. the no. of electrons is unrelated to the attraction between opposite charges , so e is incorrect as well.
B. friction
C. weather
D. convergence
Answer:
Temperaturereduces the wind speed on earth.
Explanation:
Answer:
your answer would be A. temperature
Explanation:
Wind speed on Earth is reduced by temperature, it depends on the temperature because let's say there is a nice sunny day, then obviously it will reduce the wind speed
Wave speed = (wavelength) x (frequency)
We know the wavelength, but we don't know the frequency. How can we find the frequency ? "Here frequency frequency."
We know the period, and frequency is just (1 / period). So . . .
Wave speed = (wavelength) / (period)
Wave speed = (2.1 meters) / (9.4 seconds)
Wave speed = (2.1 / 9.4) m/s
Wave speed = 0.223 m/s
B) Will the spheres attract, repel, or not interact with each other? Explain.
C) When the spheres make contact, they repel each other. Explain this behavior.
Answer:
A) A negative charge of value Q is induced on sphere B
B) there is an attraction between sphere
C) The charge of sphere A is distributed between the two spheres,
Explanation:
This is an electrostatic problem, in general charges of the same sign attract and repel each other.
with this principle let's analyze the different situations
A) The sphere A that is insulating has a charge on its surface and zero charge is its interior
The conducting sphere B has zero charge, but the sphere A creates an attraction in the electrons, therefore a negative charge of the same value as the charge of the sphere A is induced in the part closest and in the part farther away than one that a positive charge.
A negative charge of value Q is induced on sphere B
B) In this case there is an attraction between sphere A with positive charge and sphere B with negative induced charge
C) When the two spheres come into contact, the charge of sphere A is distributed between the two spheres, therefore each one has a positive charge of value half of the initial charge, as now we have net positive charges in the two spheres charges of the same sign repel each other so the spheres separate
Answer:
True
Explanation:
The normal line is defined as the line which is perpendicular to the reflecting surface at the point where the incident ray meet with the reflecting surface.
The angle of incident is defined as the angle which is subtended by the incident ray with respect to the normal ray by consider the normal ray as the base line and angle is measured from the point where incident ray is incident on the reflecting surface of the mirror.
Similarly reflecting ray can be defined as the ray which is reflected after the incident of a ray and the angle subtended by the reflecting ray is measure with respect to normal ray by considering normal ray as a base line.
Therefore, the normal ray is the perpendicular line to the reflecting surface at the point of incidence.
Answer:
The linear velocity is represented by the following expression:
Explanation:
From Rotation Physics we know that linear velocity of a point moving with uniform circular motion is:
(Eq. 1)
Where:
- Radius of rotation of the particle, measured in meters.
- Angular velocity, measured in radians per second.
- Linear velocity of the point, measured in meters per second.
But we know that angular velocity is also equal to:
(Eq. 2)
Where:
- Angular displacement, measured in radians.
- Time, measured in seconds.
By applying (Eq. 2) in (Eq. 1) we get that:
(Eq. 3)
From Geometry we must remember that circular arc (), measured in meters, is represented by:
The linear velocity is represented by the following expression: