Answers
Answer:
F1 = 80
Explanation:
f1= f2 √ (F1/F2)
Where f1 = 300, f2 = 260 and F2 = 60
Putting in the above formula
300 = 260√(F1/60)
Dividing both sides by 260
=> 1.15 = √(F1/60)
Squaring both sides
=> 1.33 = F1/60
Multiplying both sides by 60
=> F1 = 80
Related Questions
You know that you sound better when you sing in the shower. This has to do with the amplification of frequencies that correspond to the standing-wave resonances of the shower enclosure. A shower enclosure is created by adding glass doors and tile walls to a standard bathtub, so the enclosure has the dimensions of a standard tub, 0.75 m wide and 1.5 m long. Standing sound waves can be set up along either axis of the enclosure. What are the lowest two frequencies that correspond to resonances on each axis of the shower? These frequencies will be especially amplified. Assume a sound speed of 343 m/s.
If you have two substances, one with a density of 2.0 g/cm3 and one with a density of 1.3 g/cm3 and you combined them, which one would float on topother and why?
A spinning wheel on a fireworks display is initially rotating in a counterclockwise direction. The wheel has an angular acceleration of -4.46 rad/s2. Because of this acceleration, the angular velocity of the wheel changes from its initial value to a final value of -31.4 rad/s. While this change occurs, the angular displacement of the wheel is zero. (Note the similarity to that of a ball being thrown vertically upward, coming to a momentary halt, and then falling downward to its initial position.) Find the time required for the change in the angular velocity to occur.
Find an expression for the center of mass of a solid hemisphere, given as the distance R from the center of the flat part of the hemisphere. Express your answer in terms of R. Express the coefficients using three significant figures.
Answers
Answer:
In the clarification portion elsewhere here, the definition of the concern is mentioned.
Explanation:
So like optical telescopes capture light waves, introduce it to concentrate, enhance it, as well as make it usable through different instruments via study, so radio telescopes accumulate weak signal light waves, introduce that one to focus, enhance it, as well as make this information available during research. To research naturally produced radio illumination from stars, galaxies, dark matter, as well as other natural phenomena, we utilize telescopes.
Optical telescopes detect space-borne visible light. There are some drawbacks of optical telescopes mostly on the surface:
- Mostly at night would they have been seen.
- Unless the weather gets cloudy, bad, or gloomy, they shouldn't be seen.
Although radio telescopes monitor space-coming radio waves. Those other telescopes, when they are already typically very massive as well as costly, have such an improvement surrounded by optical telescopes. They should be included in poor weather and, when they travel through the surrounding air, the radio waves aren't obscured by clouds. Throughout the afternoon and also some at night, radio telescopes are sometimes used.
Answers
Answer:
42.67N
Explanation:
Step one:
Given
mass m= 0.32kg
intital velocity, u= 14m/s
final velocity v= 22m/s
time= 0.06s
Step two:
Required
Force F
the expression for the force is
F=mΔv/t
F=0.32*(22-14)/0.06
F=(0.32*8)/0.06
F=2.56/0.06
F=42.67N
The average force exerted on the bat 42.67N
Answers
where m is the mass of an electron and v is the velocity of the electron.
v = momentum ÷ m
= (1.05×10∧-24)÷(9.1×10∧-31) = 1,153,846.154 m/s
kinetic energy = (mv∧2)÷2
= (9.1×10∧-31 × 1,153,846.154∧2) ÷2
= (1.21154×10∧-18) ÷ 2
= 6.05769×10∧-19 J
Answer:
K = 6.02 × 10⁻¹⁹ J
Explanation:
The momentum (p) of an electron is its mass (m) times its speed (v).
p = m × v
v = p / m = (1.05 × 10⁻²⁴ kg.m/s) / 9.11 × 10⁻³¹ kg = 1.15 × 10⁶ m/s
We can find the kinetic energy (K) using the following expression.
K = 1/2 × m × v²
K = 1/2 × 9.11 × 10⁻³¹ kg × (1.15 × 10⁶ m/s)²
K = 6.02 × 10⁻¹⁹ J
2. The earth is heated and its atmosphere is cooled by terrestrial radiation.
3. The earth is cooled and its atmosphere is heated by terrestrial radiation.
4. The earth is heated and its atmosphere is cooled by solar radiation.
Don't answer unless you know for sure. Thank you so much!
Answers
Answer: The option 4 is correct answer.
Explanation:
Terrestrial radiation is a long wave electromagnetic radiation. It originates from the earth and its atmosphere.
The sun emits a huge amount of energy. It travels across the space. The atmosphere is not directly heated by the solar radiation. It is heated by the terrestrial radiation that the planet itself emits.
When the land is heated then it emits radiation which heats up the atmosphere.
The earth is cooled and its atmosphere is heated by terrestrial radiation.
Therefore, the relationship between the earth, its atmosphere and radiation is correctly compared by statement 4.
Answers
Answer:
Breaths per minute is a frequency. The period is its reciprocal.
Explanation:
In simple harmonic motion, a period (T) is the time taken for one point to start in a position and reach that position again, in other words to complete a cycle or lapse. In this case, a period is the time one takes from starting to inspire the air to releasing all of it from the lungs.
In simple harmonic motion, the frequency (f) is how many times a point completes a cycle or lapse in one unity of time (could be one second, one minute, one hour, etc). In this case, the frequency is how many times one breathes in one minute. This is the breathing rate, since it is breathings per minute. Breaths per minute is a frequency.
Period (T) and frequency (f) relate to each other in the following formulae: or
.
Therefore, breaths per minute is a frequency, and since it is related to the period, we say the period is reciprocal to it.
True or false
Answers
Answer:
False
whenever the string breaks, the ball will follow the straight line tangential path
Explanation:
No, the ball will not follow a curved path after the string breaks. Since, the the direction of velocity is tangential to each point of the circular motion. Therefore, it changes at every point. This produces an acceleration in the circle called centripetal acceleration. There is also a tangential component of acceleration acting on the ball during this motion.
So, whenever the string breaks, the ball will follow the straight line tangential path. Hence, the given statement is false.