C.Only CuS will precipitate from solution
Aqueous solutions of sodium sulfide and copper(II) chloride are mixed together.
Na₂S(aq) + CuCl₂(aq) → Products
Na₂S(aq) + CuCl₂(aq) → CuS(s) ↓ + 2NaCl(aq)
When the sulfide bond to the cation Cu²⁺ it makes a precipitate (s)
Thus,the correct answer is C.
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Answer:
The correct state for the answer is c.
Only CuS will precipitate from solution
Explanation:
We analyse the compounds for the reaction and we write the equation:
Na₂S(aq) + CuCl₂(aq) → Products
For this case, the products are NaCl and CuS. The complete balanced reaction is:
Na₂S(aq) + CuCl₂(aq) → CuS(s) ↓ + 2NaCl(aq)
When the sulfide bond to the cation Cu²⁺ it makes a precipitate (s)
Salts from chlorides are soluble except for the Ag⁺, Pb⁺ or Cu⁺
Salts from S⁻² which are soluble, are found in the group 2 of the Periodic Table (Ca²⁺, Ba²⁺, Mg²⁺)
The correct state for the answer is c.
The best explanation for the observation is that, the Pressure is proportional to temperature for a fixed volume of gas. (Option A)
From the question given above, the following data were obtained:
From the above, we can see that the volume is constant.
Applying the combine gas equation, we can conclude as follow:
P₁V₁ / T₁ = P₂V₂ / T₂
V₁ = V₂
P₁ / T₁ = P₂ / T₂
P/T = constant
P = constant × T
Thus, we can conclude that the pressure is proportional to the temperature at constant volume. This simply implies that the pressure will increase if the temperature increase and it will also decrease if the temperature decreases.
The correct answer to the question is Option A.
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Answer:
A
Explanation:
PV=nRT
PV/nT
V/T -> (1)/(300)=(x)/(150)
x=.420
3.3 x 10^-25 atoms
1.01 x 10^-3 moles
n = 0.20 mol
N
N = n × 6.02 × 10²³ atoms/mol
N = 0.2 mol × 6.02 × 10²³ atoms/mol
N = 1.20 × 10²³ atoms
Therefore, there are 1.20 × 10²³ gold atoms in 0.2 mol of a gold sample.
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1.01 x 10^-3 moles
Answer : The mass of NaOH present in the solution is, 0.0625 grams
Explanation : Given,
Mass % = 25 %
Mass of solution = 0.250 g
Formula used :
Now put all the given values in this formula, we get the mass of NaOH.
Therefore, the mass of NaOH present in the solution is, 0.0625 grams
Explanation:
There are 1.51 x 1024 molecules of carbon dioxide in 2.50 moles of carbon dioxide.
Density = mass / volume
Thus, Mass of the solution can be expressed as:
Mass of solution = Density of solution × volume of solution
Given- Density of solution = 1.126 g/ml
volume of solution = 20.0 ml
∴ Mass of 14 wt% solution of CaCl2 = (1.126 g/ml) × (20 ml)
= 22.52 g
= 22520 mg
Answer:
Hydrogen bonding
London dispersion forces
Explanation:
The most pronounced and consequential intermolecular forces at play has to be hydrogen bonding due to the dipole created between the oxygen and hydrogen in the hydroxyl group. And then to a lesser extent there are very weak London dispersion forces that are always going to be there in between any two molecules of any species.