How much time would it take for 9000 atoms of nobellium-253 (half-life is 97 s) to decay to 2250 atoms?Please help ASAP!!! :(

Answers

Answer 1
Answer:

Answer:it’s 828292atoms

Explanation


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Classify each of the following as a compound, a homogeneous mixture, or a heterogeneous mixture: (a) orange juice; (b) vegetable soup; (c) cement; (d) calcium sulfate; (e) teas

Answers

Explanation:

A compound is a substance that contains more than two different atoms in a fixed ratio by mass. Elements of a compound are chemically combined together.

A homogeneous mixture is defined as a mixture in which solute particles are uniformly distributed into the solvent.

Whereas a heterogeneous mixture is defined as a mixture in which solute particles are non-uniformly distributed in a solvent.

In both homogeneous and heterogeneous mixture there is no chemical combination between solute and solvent particles.

Therefore, each given substance is classified as follows.

(a) Orange juice :  As it contains pulp of orange along with the liquid which are not present in uniform composition. Hence, orange juice is a heterogeneous mixture.

(b) vegetable soup : This soup also contains vegetable pieces and spices which are non-uniformly distributed. Hence, it is also a heterogeneous mixture.

(c) cement : It contains several different compound present in definite composition. Hence, cement is a homogeneous mixture.

(d) calcium sulfate : Its chemical formula is CaSO_(4) and in this compound both calcium and sulfate atoms are chemically combined together. Therefore, calcium sulfate is a compound.

(e) Tea : It is a homogeneous mixture as there is uniform composition of tea water in milk.

Calculate the molarity of each solution.a. 0.38 mol of lino3 in 6.14 l of solution
b. 72.8 g c2h6o in 2.34 l of solution
c. 12.87 mg ki in 112.4 ml of solution

Answers

Q1)
molarity is defined as the number of moles of solute in 1 L solution 
the number of moles of LiNO₃ - 0.38 mol
volume of solution - 6.14 L
since molarity is number of moles in 1 L 
number of moles in 6.14 L - 0.38 mol
therefore number of moles in 1 L - 0.38 mol / 6.14 L = 0.0619 mol/L
molarity of solution is 0.0619 M

Q2)
the mass of C₂H₆O in the solution is 72.8 g
molar mass of C₂H₆O is 46 g/mol 
number of moles = mass present / molar mass of compound
the number of moles of C₂H₆O - 72.8 g / 46 g/mol 
number of C₂H₆O moles - 1.58 mol
volume of solution - 2.34 L
number of moles in 2.34 L - 1.58 mol
therefore number of moles in 1 L - 1.58 mol / 2.34 L = 0.675 M
molarity of C₂H₆O is 0.675 M

Q3)

Mass of KI in solution - 12.87 x 10⁻³ g
molar mass - 166 g/mol
number of mole of KI = mass present / molar mass of KI
number of KI moles = 12.87 x 10⁻³ g / 166 g/mol = 0.0775 x 10⁻³ mol
volume of solution - 112.4 mL 
number of moles of KI in 112.4 mL - 0.0775 x 10⁻³ mol
therefore number of moles in 1000 mL- 0.0775 x 10⁻³ mol / 112.4 mL x 1000 mL
molarity of KI - 6.90 x 10⁻⁴ M

The molarities of the given solutions: (a). 0.38 mol of LiNO₃ in 6.14 L of solution has a molarity of 0.062 M. (b). 72.8 g of C₂H₆O in 2.34 L of solution has a molarity of 0.675 M. (c). 12.87 mg of KI in 112.4 mL of solution has a molarity of 0.000688 M.

To calculate the molarity (M) of a solution, you can use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

a. 0.38 moles of LiNO₃ in 6.14 L of solution:

Molarity (M) = 0.38 moles / 6.14 L = 0.062 M

b. 72.8 grams of C₂H₆O (ethyl alcohol) in 2.34 L of solution:

First, you need to convert grams to moles using the molar mass of C₂H₆O.

Molar mass of C₂H₆O = 2(12.01 g/mol) + 6(1.01 g/mol) + 1(16.00 g/mol) = 46.08 g/mol

Now, calculate moles of C₂H₆O:

moles = 72.8 g / 46.08 g/mol = 1.58 moles

Molarity (M) = 1.58 moles / 2.34 L = 0.675 M

c. 12.87 mg of KI in 112.4 mL of solution:

First, convert milligrams to grams (1 g = 1000 mg):

12.87 mg = 12.87 g (since 12.87 mg / 1000 = 0.01287 g)

Now, convert mL to liters (1 L = 1000 mL):

112.4 mL = 0.1124 L

Calculate moles of KI:

Molar mass of KI = 39.10 g/mol (for K) + 126.90 g/mol (for I) = 166.00 g/mol

moles = 0.01287 g / 166.00 g/mol = 7.75 × 10⁻⁵ moles

Molarity (M) = (7.75 × 10⁻⁵ moles) / 0.1124 L = 0.000688 M

So, the molarities of the solutions are as follows:

a. 0.062 M

b. 0.675 M

c. 0.000688 M

To know more about moles:

brainly.com/question/34302357

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The radius of an atom of gold (Au) is about 1.35 Å.How many gold atoms would have to be lined up to span 5.5 mm ?

Answers

The number of gold atoms that would be needed to span this distance is 20,370.4 atoms.

How many gold atoms would have to be lined up?

To calculate how many gold atoms would need to be lined up to span a given distance, we will us the following method.

The number of gold atoms that would be needed to span this distance:

Distance  = Diameter of a gold atom

Distance = 2 x Radius

Distance = 2 x 1.35 Å

Number of gold atoms = Total distance / Distance spanned by a single atom

Number of gold atoms = (5.5 x 10⁻⁴ cm) / (2 x 1.35 Å)

1 Å = 10⁻⁸ cm.

Number of gold atoms = (5.5 x 10⁻⁴ cm) / (2 x 1.35 x 10⁻⁸ cm)

Number of gold atoms = 20,370.4 atoms

Learn more about number of atoms here: brainly.com/question/6258301

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depends how many sig figs you are rounding to so I won't round to tenth or hundredth but the answer is 2.037 * 10^7

A gas has a volume of 300 mL and a pressure of 2 atm. What volume will the gas occupy when the pressure isincreased to 7 atm (total)?

Answers

Answer:

The answer is 85.71 mL

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

V_2 =  (P_1V_1)/(P_2)  \n

We have

V_2 =  (300 * 2)/(7)  =  (600)/(7)   \n  = 85.714285...

We have the final answer as

85.71 mL

Hope this helps you

Partc. explain why equal volumes of 0.1 m ch3cooh and 0.1 m nach3co2 function as a buffer solution, but equal volumes of 0.1 m hcl and 0.1 m naoh do not.

Answers

Answer : As per the definition of the buffer solution "It is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa".

so considering the above given condition for 
CH_(3) COOH and NaCH_(3)CO_(2) act as buffer because it satisfies and qualifies the conditions of behaving as a buffer when mixed in equal amounts,

whereas HCl and NaOH are strong acid and strong base which does not satisfies the criteria for being called as buffer.

As buffer needs a weak acid and its conjugate base to behave and act as buffer and resist any pH change.

Pls answer this question

Answers

Answer:

A carbon dioxide and oxygen