The density of metal will be "0.469 g/mL".
The given values in the question are:
Now,
The density of metal will be:
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By substituting the given values, we get
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Thus the above is the appropriate answer.
Learn more about volume of metal here:
The density of the metal is 0.47 g/mL
The density of an object is defined as the mass of the object per unit volume of the object.
With the above formula, we can obtain the density of the metal. This is illustrated below:
Volume of metal = change in volume of water = 3.2 mL
Mass of metal = 1.5 g
Density = mass / volume
Density = 1.5 / 3.2
Therefore, the density of the metal is 0.47 g/mL
Learn more: brainly.com/question/24472494
b. Is colorless in the presence of water
c. Does not exist as a hydrate
d. Forms different hydrates which have different colors
Answer:Forms different hydrates which have different colors
Explanation:
CoCl2 in its anhydrous form is blue in colour. This anhydrous compound could absorb moisture, first forming the purple dihydrate and absorbs more water molecules to form the hexahydrate. Hence various hydrates of cobalt II chloride have different colours as stated above. Equations of reaction for the formation of the two hydrates are attached.
Answer and Explanation:
(a) Na and H : The compound formed by Na and H is sodium hydride which formula is NaH
(b) B and O : The compound formed by Ba and O is barium oxide which formula is BaO
(C)Na and S : The compound formed by Na and S is sodium sulfide which formula is
(D) Al and F : The compound formed by Al and F is aluminium fluoride which formula is
(E) F and O : The compound formed by F and O is oxygen fluoride which formula is
(F) Sr and Cl : The compound formed by Sr and Cl is strontium chloride which formula is
Answer:
THE NEW FREEZING POINT IS -4.196 °C
Explanation:
ΔTf = 1 Kf m
molarity of MgCl2:
Molar mass = (24 + 35.5 *2) g/mol
molar mass = 95 g/mol
7.15 g of MgCl2 in 100 g of water
7.15 g = 100 g
(7.15 * 100 / 1000) = 1000 g or 1 L or 1 dm3
= 0.715 g /dm3
Molarity in mol/dm3 = molarity in g/dm3 / molar mass
= 0.715 g /dm3 / 95 g/mol
m = 0.00752 mol/ dm3
So therefore:
ΔTf = i Kf m
1 = 3 (1 Mg and 2 Cl)
Kf = 1.86 °C/m
M = 0.752 moles
So we have:
ΔTf = 3 * 1.86 * 0.752
ΔTf = 4.196 °C
The new freezing point therefore will be 0 °C - 4.196 °C which is equals to - 4.196 °C
B. its speed increases due to air resistance,
C. it moves at a constant speed,
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OD. it moves at a constant velocity
Answer:
The answer is C!
Explanation:
Hope it helps
Answer D
Explanation: did the quiz ψ(`∇´)ψ