A car is decelerating at the rate of 2 km/s square. If its initial speed is 66 km/s, how long will it take the car to come to a complete stop?

Answers

Answer 1
Answer:

Answer:

It will take 33 seconds to stop the car.

Explanation:

Using the first equation of kinematics we have

v=u+at

where

'v' is final speed of object

'u' is initial speed of object

'a' is acceleration of object

't' is time of acceleration of object

Now since it is given that a=-2km/s^(2) since acceleration is negative  and u=66km/s

We know that the object will stop when it's velocity reduces to zero hence in the equation above setting v = 0 we get

0=66-2* t\n\n\therefore t=(66)/(2)=33seconds


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A 8.00-μF capacitor that is initially uncharged is connected in series with a 3.00-Ω resistor and an emf source with E = 70.0 V and negligible internal resistance. At the instant when the resistor is dissipating electrical energy at a rate of 300 W, how much energy has been stored in the capacitor?

Answers

Answer:

The energy stored is E_s = 0.0064 \  J

Explanation:

From the question we are told that  

   The capacitance  is  C =  8 \ \mu F = 8*10^(-6) \  F

    The resistance is  R = 3.00-Ω

    The emf is  E_t = 70.0 V

      The power  is  P = 300 W

Generally the total  emf is mathematically represented as

   E_t = E_c + E_r

Here  E_c is the emf across that capacitor which is mathematically represented as

      E_c  =  (q)/(C)

and E_r is the emf across the resistor which is mathematically represented as

       E_r  = √(P R)

So  

       E_t  =  √(PR)  + (q)/(C)

=>    q = C[E_t - √(PR) ]

Generally the energy stored in a capacitor is mathematically represented as

          E_s = (q^2)/(2C)

=>      E_s = ([C [ E_t - √(PR) ]]^2)/(2C)

=>      E_s = ([8.0*10^(-6) [ 70 - √(300 * 3))/(2 *(8.0*10^(-6)))

=>      E_s = 0.0064 \  J

Final answer:

The energy stored in the capacitor is 0 J.

Explanation:

When a 8.00-μF capacitor that is initially uncharged is connected in series with a 3.00-Ω resistor and an emf source with E = 70.0 V

At the instant when the resistor is dissipating electrical energy at a rate of 300 W, we can calculate the current flowing through the circuit using Ohm's law: I = V/R = 70.0 V / 3.00 Ω = 23.33 A.

The energy stored in a capacitor can be calculated using the formula: E = 1/2 * C * V^2, where C is the capacitance and V is the voltage across the capacitor.

Since the capacitor is initially uncharged, the voltage across it is also zero. So the energy stored in the capacitor is 0.5 * 8.00 x 10^-6 F * (0 V)^2 = 0 J.

Learn more about Energy stored in a capacitor here:

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In general terms, the efficiency of a system can be thought of as the output per unit input. Which of the expressions is a good mathematical representation of efficiency e of any heat engine?
Where,
Qh: the absolute value (magnitude) of the heat absorbed from the hot reservoir during one cycle or during some time specified in the problem
Qc: the absolute value (magnitude) of the heat delivered to the cold reservoir during one cycle or during some time specified in the problem
W: the amount of work done by the engine during one cycle or during some time specified in the problem

A) e=QhW
B) e=QcQh
C) e=QcW
D) e=WQh
E) e=WQc

Answers

Answer:

Efficiency e =  W/Qh

Explanation:

As written above efficiency of a system is calculated as the output per unit input. For heat Engine, Efficiency is calculated by dividing the Work done by Engine by Heat absorbed from hot reservoir.

In theoretical terms The maximum efficiency of a heat engine (which no engine ever attains) is equal to the temperature difference between the hot and cold ends divided by the temperature at the hot end, each expressed in absolute temperature (Kelvin).

But in practical calculations, it is calculated as  e =  W/Qh ,  and we define the thermal efficiency, of any heat engine as the ratio of the work it does, W, to the heat input at the high temperature, Qh.

Your friend is trying to construct a clock for a craft show and asks you for some advice. She has decided to construct the clock with a pendulum. The pendulum will be a very thin, very light wooden bar with a thin, but heavy, brass ring fastened to one end. The length of the rod is 80 cm and the diameter of the ring is 10 cm. She is planning to drill a hole in the bar to place the axis of rotation 15 cm from one end. She wants you to tell her the period of this pendulum.

Answers

Answer:

The period of the pendulum is  T  =  1.68 \  sec

Explanation:

The diagram illustrating this setup is shown on the first uploaded image

From the question we are told that

     The length of the rod is L =  80 \ cm

       The diameter of the ring is d = 10 \ cm

       The distance of the hole from the one end  D =  15cm

From the diagram we see that point A is the center of the brass ring

 So the length from the axis of  rotation is mathematically evaluated as

          AP = 80 + 10 -5 -15  

          AP =  70 \ cm =  (70)/(100)  =  0.7 \ m

Now the period of the pendulum is mathematically represented as

             T  = 2 \pi  \sqrt{(AP)/(g) }

             T  =  2 \pi \sqrt{(0.7)/(9.8 ) }

             T  =  1.68 \  sec

     

     

     

As you take the stoppered part of the tube up the staircase you begin to see the water level drop around the 4th floor. As you continue up it does not continue up with you but stays at a constant level. What does that mean?a. The pressure in the tubing is equal to the barometric pressure.
b. The tubing was unable to supply any more water to the tube for use.
c. The pressure outside the tube is higher that the water pressure inside the tube.

Answers

Answer:

a. The pressure in the tubing is equal to the barometric pressure.

Explanation:

Since in the question it is mentioned that the if you take the stoppert part of the tube than the level of warer would be fall approx 4th floor and if it is continued than it wont be continue but remains constant.

Now here first we do that the tube i.e. connected to the bucket should be taken up. In the first instance, the bucket supplies the water to the tube but it would not increased far away to the level of the barometric pressure

Hence, the correct option is a.

Suppose you are pushing on a crate across a floor as shown below. Assume the friction force is 47.0 N. How much time will it take for the crate to reach 6.0 m/s if it started from rest? Assume the weight of the crate is 2058 N. (250 N force applied)(Question is no longer a priority but i’d like to know the answer and how it’s found) pls don’t scam i’m serious man i need to know

Answers

Answer:

6.2 seconds

Explanation:

Using Newton's second law, ∑F=ma, we know the net force acting on the object is Force applied-Force of friction. The net force is 203 N. Newton's second law requires the mass of an object, not the weight force, so we will have to calculate the mass. We know that m*g=weight force,  in this case, solve for the mass and you will get 210 kg. Now that we have the value of the net force and the mass, we can solve for acceleration. (F)/(m)=a=0.967 m/s^2. Now, since we have the acceleration, initial velocity(0 m/s), and the final velocity (6m/s) we will use these to solve for time using the kinematic equation Vf=Vi + at. Plug in the values we know and solve for time and you will get 6.2 seconds

Trevor and Nick are taxi drivers. Trevor drives a taxi using diesel oil while Nick drives a taxi using LPG. Whose taxi will cause higher levels of air pollution and why?

Answers

Answer:

Trevor's taxi would cause higher levels of air pollution

Explanation:

Trevor's taxi use diesel oil.

Diesel is less cleaner than LPG.

Compared to automotive pollution from petrol and diesel, pollutants from LPG-driven cars include lower amounts of petroleum hydrocarbons, nitrogen oxides , sulphur oxides, ozone contamination and particulate matter.