Which of the following organisms has an adaptation that will allow it to survive in tundra biome? *A.)Plants with roots that are short and grows sideways with hairy stems and small leaves.
B.)Plants that have broad leaves to capture sunlight and long roots to penetrate the soil.
C.)Animals with thin fur that allows them to get rid of heat efficiently.
D.)Animals with long tongues for capturing prey and sticky pads for climbing trees.

Answers

Answer 1

Answer:

Answer:

the awnser is A becuse the hair help.

Related Questions

A physics student standing on the edge of a cliff throws a stone vertically downward with an initial speed of 10.0 m/s. The instant before the stone hits the ground below, it is traveling at a speed of 30.0 m/s. If the physics student were to throw the rock horizontally outward from the cliff instead, with the same initial speed of 10.0 m/s, what is the magnitude of the velocity of the stone just before it hits the ground? Ignore any effects of air resistance.
Halogen lightbulbs allow their filaments to operate at a higher temperature than the filaments in standard incandescent bulbs. For comparison, the filament in a standard lightbulb operates at about 2900K, whereas the filament in a halogen bulb may operate at 3400K. Which bulb has the higher peak frequency? Calculate the ratio of the peak frequencies. The human eye is most sensitive to a frequency around 5.5x10^14 Hz. Which bulb produces a peak frequency close to this value?
An ideal gas is at a temperature of 320 K. What is the average translational kinetic energy of one of its molecules
. An electron moving at 4.00×103m/s in a 1.25-T magnetic field experiences a magnetic force of 1.40×10−16N . What angle does the velocity of the electron make with the magnetic field? There are two answers.
A large rectangular tub is filled to a depth of 2.60 m with olive oil, which has density 915 kg/m3 . If the tub has length 5.00 m and width 3.00 m, calculate (a) the weight of the olive oil, (b) the force of air pressure on the sur- face of the oil, and (c) the pressure exerted upward by the bottom of the tub.

Light emitted by element X passes through a diffraction grating that has 1200 slits/mm. The interference pattern is observed on a screen 75.0 cm behind the grating. First-order maxima are observed at distances of 56.2 cm, 65.9 cm, and 93.5 cm from the central maximum. What are the wavelengths of light emitted by element X?

Answers

Answer:

Explanation:

Width of slit = 10⁻³ / 1200

d = 8.3 x 10⁻⁷ m

First order maxima will be observed at

x = λD/d

D = 75 cm = 75 x 10⁻² m

56.2 x 10⁻² = λ₁D/d

= λ₁ x 75 x 10⁻² / 8.3 x 10⁻⁷

λ₁ = 56.2 x 8.3 x 10⁻⁷ / 75

= 6.219 x 10⁻⁷ m

= 6219 A

Similarly

λ₂ = 65.9 x 8.3 x 10⁻⁷ / 75

= 7293 A

λ₃ = 93.5 x 8.3 x 10⁻⁷ / 75

= 10347 A

In a physics laboratory experiment, a coil with 170 turns enclosing an area of 10.9 cm2 is rotated during the time interval 3.50×10−2 s from a position in which its plane is perpendicular to Earth's magnetic field to one in which its plane is parallel to the field. The magnitude of Earth's magnetic field at the lab location is 5.60×10−5 T. What is the total magnitude of the magnetic flux (initial) through the coil before it is rotated?

Answers

$N= 170 turns\nA=10.9cm^2\nt=3.5*10^(-2)s \n\B = 5.6*10^(-5)T$

The Magnetic flow $\Phi_(initial)$ is given by the formula,

$\Phi_(Initial)=BAsin\theta$

Replacing the values

$\Phi_(Initial) =(5.6*10^(-5))(10.9)((10^(-4)m^2)/(1cm^2)) sin90\°$

$\Phi_(Initial) =6.104*10^(-7) Wb$

What frequency corresponds to a period of 4.31s.
T =1/f = 1/4.31s = 0.232hz correct?

Answers

Answer:correct

Explanation: Period T is the reciprocal of frequency (i.e T=1/f)

Frequency is the reciprocal of period (i.e F= 1/T)

Therefore if T=4.31s

Frequency F= 1/4.31s=0.232hz

Write down the DE of motion of a particle moving under the influence of gravity and experiencing a resistive force. .

Answers

Answer:

The DE will be $(d^2x)/(dt^2)-(k)/(m)(dx)/(dt)-g=0$

Explanation:

We have to find differential equation under the influence of gravity and experiencing a resistive force

Let an object of mass m falling under the influence of gravity

So the force experience under gravity $=mg$

Le the a resistive force of magnitude kv opposes this gravity force, here k is constant and v is velocity.

So net force $F_(NET)=mg-kv$ -----eqn 1

$F_(NET)=ma$

So $ma=mg-kv$

We know that velocity is rate of change of position so $v=(dx)/(dt)$ , and acceleration is rate of change of velocity so $a=(d^2x)/(dt^2)$

Putting all these value in eqn 1

$m(d^2x)/(dt^2)=mg-k(dx)/(dt)$

$(d^2x)/(dt^2)-(k)/(m)(dx)/(dt)-g=0$

A vibrating tuning fork makes 500 vibrations in one second. What is the wavelength of the sound produced if the air temperature is 20°C? Group of answer choices0.500 m
0.686 m
0.343 m
1.46 m
1.87 m

Answers

Answer:

wavelength will be 0.686 m

So option (b) is correct

Explanation:

We have given vibration in one second that is frequency = 500 Hz

We know that velocity of sound is 343 m/sec

We have to find the wavelength

We know that velocity is given by $v=\lambda f$

So wavelength $\lambda =(v)/(f)=(343)/(500)=0.686m$

So wavelength will be 0.686 m

So option (b) is correct

Dogs can hear higher-pitched whistles that humans do. How do you
think the sound frequencies that dogs can
hear compare to the frequencies that humans
can hear?

Answers

Dogs can hear sounds at higher frequencies than humans. The range of sound frequencies that dogs can hear is approximately 40 Hz to 60,000 Hz, while the range for humans is 20 Hz to 20,000 Hz. This means that dogs can hear ultrasonic sounds that are beyond the range of human hearing.

What is sound about?

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave.

Sound is the reception of these waves and the brain's perception of them in terms of human physiology and psychology. Dogs have the ability to hear ultrasonic sounds that are audible only to them.

Learn more about sound on:

brainly.com/question/16093793

#SPJ1

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