To solve this problem it is necessary to apply Snell's law and thus be able to calculate the angle of refraction.
From Snell's law we know that
Where,
n_i = Refractive indices of each material
= Angle of incidence
= Refraction angle
Our values are given as,
Replacing
Re-arrange to find
Therefore the angle will the beam make with the normal in the glass is 26°
Answer:
The tension in the steel beam is 14.72 Newtons.
Explanation:
To calculate the tension in the steel beam when a car is hanging from it, you can use the principles of static equilibrium. In this situation, the gravitational force acting on the car must be balanced by the tension in the steel beam.
First, let's calculate the gravitational force acting on the car:
F_gravity = mass × gravity
Where:
Mass (m) = 1560 kg
Gravity (g) ≈ 9.81 m/s² (standard acceleration due to gravity)
F_gravity = 1560 kg × 9.81 m/s² ≈ 15306 N
Now, this gravitational force is balanced by the tension in the steel beam. Since the beam bends with an angle of 0.055°, we need to consider the vertical component of the tension force.
The vertical component of the tension (T_vertical) can be calculated using trigonometry (considering the angle θ):
T_vertical = T × sin(θ)
Where:
T_vertical is the vertical component of tension.
T is the tension in the beam.
θ is the angle in radians.
We need to convert the angle from degrees to radians:
θ = 0.055° × (π/180) ≈ 0.000959 radians
Now, we can calculate T_vertical:
T_vertical = 15306 N × sin(0.000959) ≈ 14.72 N
So, the tension in the steel beam is 14.72 Newtons.
Answer:
2.0 amps
Explanation:
Current is the ratio of voltage to resistance:
I = V/R = (3.0)/(1.5) = 2.0
The current in the wire is 2.0 amps.
Answer:
(a)
(b) Initial velocity of the projectile is 22.54 m/s
(c) Straight line perpendicular to the plane of the car's motion
(d) Parabolic
(e) The initial velocity is 23.04 m/s
Solution:
As per the question:
Velocity of the cart, v = 0.500 m/s
Distance moved by the cart, d = 2.30 m
Now,
(a) The projectile must be fired at an angle of so that it mounts on the top of the cart moving with constant velocity.
(b) Now, for initial velocity, u':
Time of flight is given by;
(1)
where
T = Flight time
D = Distance covered
(b) The component of velocity w.r.t an observer:
Horizontal component,
Vertical component,
Also, the vertical component of velocity at maximum height is zero,
Therefore,
Total flight time, (2)
Now, from eqn (1) and (2):
(c) The shape of the projectile w.r.t an observer will be a straight line perpendicular to the plane of cart's motion.
(d) The shape of the path of the projectile seen by the physics student outside the reference frame of the cart is parabolic
(e) The initial velocity is given by:
u = u' + v = 22.54 + 0.5 = 23.04 m/s
Answer:
the correct option is C
Explanation:
The intensity of a lamp depends on the power of the lamp that is provided by the current flowing over it, therefore the intensity would increase if we raise the current.
Another way to increase the intensity is to decrease the area with a focusing lens, as the intensity is power over area, decreasing the area increases the power.
When we see the possibilities we see that the correct option is C
Answer:
The acceleration of the mower will be "4.7 m/s²".
Explanation:
Balance of vertical force will be:
⇒
For wheel to take off at A,
⇒
Hence,
Balancing moments about G will be:
⇒
As we know,
Force, F =
On putting the values, we get
⇒ =
⇒ =
Now,
Acceleration, a =
⇒ =
⇒ =
Answer:
Seismology.
Explanation: