Answers
Answer:
It will take 313.376 sec to raise temperature to boiling point
Explanation:
We have given that potential difference V = 120 Volt
Current i = 4.50 A
So resistance
Heat flow in resistor will be equal to
It is given that this heat is used for boiling the water
Mass of the water = 0.525 kg = 525 gram
Specific heat of water 4.186 J/gram/°C
Initial temperature is given as 23°C
Boiling temperature of water = 100°C
So change in temperature = 100-23 = 77°C
Heat required to raise the temperature of water
So
t = 313.376 sec
So it will take 313.376 sec to raise temperature to boiling point
Answer:
Explanation:
Voltage, V = 120 V
Current, i = 4.5 A
mass of water, m = 0.525 kg
initial temperature of water, T1 = 23°C
Final temperature of water, T2 = 100 °C
specific heat of water, c = 4.18 x 1000 J/kg °c
let the time taken is t.
Heat given by the heater = heat gain by the water
V x i x t = m x c x (T2 - T1)
120 x 4.5 x t = 0.525 x 4.18 x 1000 x (100 - 23)
540 t = 47701.5
t = 88.34 s
Related Questions
John and Suzie are trying to improve the speed of their race car by adjusting the angle of the rear spoiler. Which choice is the controlled variable(s)?the maximum speed and the angle of the rear spoilerthe type of tire and the type of fuelonly the maximum speedonly the angle of the rear spoiler
A person is making homemade ice cream. She exerts a force of magnitude 26 N on the free end of the crank handle on the ice-cream maker, and this end moves on a circular path of radius 0.26 m. The force is always applied parallel to the motion of the handle. If the handle is turned once every 2.0 s, what is the average power being expended?
3.what does this stand for ??
Which one defines force?
Answers
All of that is fascinating information. Thank you for sharing.
Answers
Answer:
The atomic nucleus is the small, dense region consisting of protons and neutrons at the center of an atom, discovered in 1911 by Ernest Rutherford based on the 1909 Geiger–Marsden gold foil experiment.
Explanation:
Answers
Answer:
1.56 - 1.67
Explanation:
Refractive index of any material is given as the ratio of the speed of light in a vacuum to the speed of light in that medium.
Mathematically, it is given as:
n = c/v
Where c is the speed of light in a vacuum and v is the speed of light in the medium.
Given that the speed of light in the optical medium varies from 1.8 * 10^8 m/s to 1.92 * 10^8 m/s, we can find the range of the refractive index.
When the speed is 1.8 * 10^8 m/s, the refractive index is:
n = (3 * 10^8) / (1.8 * 10^8)
n = 1.67
When the speed is 1.92 * 10^8 m/s, the refractive index is:
n = (3 * 10^8) / (1.92 * 10^8)
n = 1.56
Therefore, the range of values of the refractive index of the optical medium is 1.56 - 1.67.
Answers
Answer:
It can apply a greater output force over a greater distance compared to the input force and distance.
Explanation:
A machine helps to multiply force input and makes it easier to do work. Simple and complex machines are need to make work easier.
- Most machines are designed to increase the input force by a system of mechanics.
- Machines allow force to be applied over great distances and this allows for the input work done to be duly compensated for.
The statement describes how a machine can help make work easier, (c) It can apply a greater output force over a greater distance compared to the input force and distance is correct option.
A machine is a device designed to perform a specific task or work by using mechanical, electrical, or other forms of energy. Machines are created to make tasks easier, more efficient, or possible to accomplish that would be difficult or impossible to achieve using human effort alone.
They can range from simple tools like levers and pulleys to complex systems like engines and computers. Machines typically involve the conversion of input energy (such as human effort or electricity) into some form of output energy (such as mechanical motion or computation) to achieve a desired result.
To know more about machine
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Answers
Answer:
-847.2J
Explanation:
First find the acceleration from v^2= u^2 + 2as
v= 2.5 m/s
u= 1.3 m/s
a???
s=6.00
a= v^2-u^2/2s
a= (2.5)^2-(1.3)^2/2× 6
a= 0.38ms^-2
From Newtons second law:
(Force applied cos Θ) - (Frictional force) = ma
Frictional force = ma- (Force applied cos Θ)
Frictional force= (18.8×0.38) - (165 cos 26°)
Frictional force= 7.144- 148.3= -141.2N
Therefore,
Work done by friction = Frictional force × distance covered
= -141.2N × 6= -847.2J
Answer:
W = –847J
Explanation:
Given m = 18.8kg, F = 165N, θ = -26° (below the horizontal, s = 6.0m, u = 1.30m/s and v = 2.50m/s
In this problem, two forces act on the chair; the forward force F and the frictional force f. We would apply newton's second law to find the frictional force f after which we can calculate the workdone by the frictional force f×s.
But for us to apply newton's second law, we need to know the acceleration of the chair cause by the net force.
From constant acceleration motion equations
v² = u² + 2as
2.5² = 1.30² + 2a×6
6.25 = 1.69 +12a
12a = 6.25 – 1.69
12a = 4.56a
a = 4.56/12
a = 0.38m/s
By newton's second law the net sum of forces equals m×a
The force F has horizontal and vertical and components. It is the horizontal component of this force that pushes the chair against friction.
Fx and f are oppositely directed.
So
Fx – f =ma
165cos(-26) – f = 18.8×0.38
148.3 – f = 7.14
f = 148.3 – 7.14
f = 141.2N
Workdone = -fs = –141.2×6.00 = –847J
W = –847J
Work is negative because it is done by a force acting on the chair in a direction opposite (antiparallel) to that of the intended motion.
Answers
Answer:
14.7 psi is equal to 19051.2 pounds per square yard.
Explanation:
Dimensionally speaking, a square yard equals 1296 square inches. Therefore, we need to multiply the atmospheric pressure by 1296 to obtain its equivalent in pounds per square yard. That is:
14.7 psi is equal to 19051.2 pounds per square yard.