Answer:
The gravity at Equator is 9.780 m/s2 and the gravity at poles is 9.832 m/s2. The gravity at poles are bigger than at equator, principally because the Earth is not totally round. The gravity is inversely proportional to the square of the radius, that is the reason for the difference of gravity (The radius at Poles are smaller than at Equator).
If Earths would have a net charge Q. The Electric field of Earth would be inversely proportional to the square of the radius of Earth (Electric field definition for a charge), the same case as for gravity. So there would be a difference between the electric field at poles and equator, too.
Answer:
6000 joules
Explanation:
I jus learned dis
Answer:6000j
Explanation:
Hope that helps
Answer:
Explanation:
To solve the problem it is necessary to take into account the concepts related to arc length and the radius that make up the measurements of an angle.
An angle is given by the length of arc displaced as a function of the radius, that is
360° is equal to do rad, therefore:
Answer:
0.002
Explanation:
The half-life of the radioactive nucleus is related to its quantity, by the following equation:
Where:
N(t): is the quantity of the radioactive nucleus at time t
N₀: is the initial quantity of the radioactive nucleus
t: is the time = 4.5x10⁹ years
t(1/2): is the half-life of the radioactive nucleus = 5x10⁸ years
Therefore, the fraction of the radioactive element in the rock today is 0.002.
I hope it helps you!
Answer:
0.97566 m/s
Explanation:
= Mass of cannon = 2260 kg
= Velocity of cannon
= Mass of ball = 21 kg
= Velocity of ball = 105 m/s
As the momentum of the system is conserved we have
The velocity of the cannon is 0.97566 m/s
Answer:
The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.
Explanation:
Given that,
Velocity = 270 m/s
Acceleration = 9.0g s
We need to calculate the altitude
Using formula of centripetal acceleration
Where, v = velocity
r = altitude
a = acceleration
Put the value into the formula
Hence, The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.
The Columb's law is the same as Gravitational law
As we see the formula of both Coulomb and Gravitational Law,
(1)
(2)
The masses (M) in formula (1) experiencing the force of gravitational pull with each other which varies with changing the distance. In the formula (2), the charges also are felling the forces on each other which varies with distance. The charges and masses are just like the objects which are experiencing the forces which have a common factor as distance. The gravitational force is also called the mutual forces.