Answer: The speed of the moon's rotation keeps the same side always facing Earth.
Explanation: Please mark me brainiest
Answer:
The speed of the Moon's rotation keeps the same side always facing Earth.
Explanation:
got it right on study island :)
runs into an at-rest freight car with a mass of 28,000 kg. The cars lock
together. What is their final velocity?
A.1.1 m/s
B. 2.2 m/s
C. 60,000 kg•m/s
D. 0.5 m/s
Answer:
a
Explanation:
you take 32,000kg ÷2.0m
2. When the low power (10X) objective is used the total magnification will be:________
3. When the high power (40X) objective is used the total magnification will be:________
4. When the oil immersion (100X) objective is used the total magnification will be:_________
Answer:
a) m_ttoal = 40x, b) m_total = 100X, c) m_total = 400X,
d) m_total = 1000 X
Explanation:
La magnificación o aumentos es el incremento de del tamaño de la imagen con respecto al tamaño original del objeto, en la mayoria del os sistema optico la magnificacion total es el producoto de la magnificación del objetivo por la magnificación del ocular
m_total = m_ objetivo * m=ocular
apliquemos esto a nuestro caso
1) m_total = 4 x * 10 x
m_ttoal = 40x
2) m_total = 10X * 10X
m_total = 100X
3)mtotal = 40X * 10X
m_total = 400X
4) m _totla = 100x * 10 X
m_total = 1000 X
en este ultimo caso para magnificación grandes es decalcificar el objeto
The total magnification produced by different combinations of eyepiece and objective lenses in a microscope.
1. When the scanning (4X) objective is used, the total magnification will be 40X because the eyepiece magnification is 10X and the objective magnification is 4X.
2. When the low power (10X) objective is used, the total magnification will be 100X because the eyepiece magnification is 10X and the objective magnification is 10X.
3. When the high power (40X) objective is used, the total magnification will be 400X because the eyepiece magnification is 10X and the objective magnification is 40X.
4. When the oil immersion (100X) objective is used, the total magnification will be 1000X because the eyepiece magnification is 10X and the objective magnification is 100X.
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Answer:
Answer:
ANSWER
A = 5 cm = 0.05 m
T = 0.2 s
ω=2π/T=2π/0.2=10πrad/s
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Answer:
67.5 cm
Explanation:
u = - 90 cm, v = 3 x u = 3 x 90 = 270 cm
let f be the focal length
Use lens equation
1 / f = 1 / v - 1 / u
1 / f = 1 / 270 + 1 / 90
1 / f = 4 / 270
f = 67.5 cm
To determine the focal length of the lens, we use the lens formula and set up an equation based on the given information. Solving for the image distance, we find that it is zero, indicating the image is formed at infinity. Therefore, the focal length of the lens is 90 cm.
To determine the focal length of the lens, we can use the lens formula:
1/f = 1/v - 1/u
Where f is the focal length, v is the image distance, and u is the object distance.
Given that the image distance triples when the object is moved from infinity to 90 cm in front of the lens, we can set up the following equation:
1/f = 1/(3v) - 1/(90)
Multiplying through by 90*3v, we get:
90*3v/f = 270v - 90*3v
90*3v/f = 270v - 270v
90*3v/f = 0
Simplifying further, we find that: v = 0
When the image distance is zero, it means the image is formed at infinity, so the lens is focused at the focal point. Therefore, the focal length of the lens is 90 cm.