Answer:
Astronaut in spacecraft while orbiting earth experience weightlessness because there is no gravity of earth or moon is acting on the body of an astronaut.
while on earth, we experience weight because the gravity of earth is acting on our body which is pulling us downward.
Both spacecraft and the astronauts both are in a free-fall condition.
Answer:
its 45 over 6
Explanation:the answer is in the question
Answer: Only the melted cube's shape changed.
Explanation:
The beat frequency heard when the two strings are played together is 2.95 Hz.
Given data:
The tuning frequency of the violin is, f = 294 Hz.
Decrement in the tension is, 2 %.
Since, tension is reduced at the rate of 2%. Then the new magnitude of tension on the string is,
T = (100 - 2 )/100
T = 0.98
Then the expression for the beat frequency heard when the two strings are played together is given as,
Solving as,
Thus, we can conclude that the beat frequency heard when the two strings are played together is 2.95 Hz.
Learn more about the beat frequency here:
Answer:
Beat frequency together = 2.95 Hz (Approx)
Explanation:
Given:
Frequency (F) = 294 H
Decrease in tension = 2%
Find:
Beat frequency together
Computation:
Tension = (100 - 2) / 100
Tension (T) = 0.98
Beat frequency together = Frequency (F) - (√T × F)
Beat frequency together = 294 - (√0.98 × 294)
Beat frequency together = 2.95 Hz (Approx)
Answer:
Uses of concave mirror:
Shaving mirrors.
Head mirrors.
Ophthalmoscope.
Astronomical telescopes.
Headlights.
Solar furnaces.
Uses of convex mirror:
Convex mirrors always form images that are upright, virtual, and smaller than the actual object. They are commonly used as rear and side view mirrors in cars and as security mirrors in public buildings because they allow you to see a wider view than flat or concave mirrors.
please give me full points.
Answer:
V = 1.69 * 10^6 V
Explanation:
Parameters given:
Electric field, E = 59V/m
Charge, q = 5.40C
We need to first find the distance between the electric charge and the point of consideration to be able to find the Electric potential difference.
Electric field is given as:
E = (kq/r^2)
k = Coulombs constant
=> r^2 = kq/E
=> r^2 = (9 * 10^9 * 5.4) / 59
r^2 = 8.2 * 10^8
r = 2.84 * 10^4 m
We can now find the Electric Potential by using:
V = kq/r
Hence,
V = (9 * 10^9 * 5.4) / (2.84 * 10^4)
V = 1.69 * 10^6 V
B.) perception.
C.) similarity.
D.) continuity.
Answer:
C
Explanation:
Similarity