Answer:
Explanation:
Frequency( ν ) 4667 x 10³ Hz = 4.667 x 10⁶ Hz
Energy of one photon = hν [ h is plank's constant ]
= 6.6 x 10⁻³⁴ x 4.667 x 10⁶ = 30.8 x 10⁻²⁸ J
Power = 84 x 10³ J/s
No of photons emitted = Power / energy of one photon
= 84 x 10³ / 30.8 x 10⁻²⁸ =2.727 x 10³¹ per second .
Answer:
The ball land at 3.00 m.
Explanation:
Given that,
Speed = 40 m/s
Angle = 35°
Height h = 1 m
Height of fence h'= 12 m
We need to calculate the horizontal velocity
Using formula of horizontal velocity
We need to calculate the time
Using formula of time
We need to calculate the vertical velocity
We need to calculate the vertical position
Using formula of distance
Put the value into the formula
We need to calculate the distance
Hence, The ball land at 3.00 m.
Answer:
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 1300 × 1.07
We have the final answer as
Hope this helps you
Answer:
R = 8.94 10⁻² Ω/m, R_sp / R_total = 44.8
Explanation:
The resistance of a metal cable is
R = ρ L / A
The area of a circle is
A = π R²
The resistivity of copper is
ρ = 1.71 10⁻⁸ ohm / m
Let's calculate
R = 1.71 10⁻⁸ 4.27 / (π (0.51 10⁻³)²)
R = 8.94 10⁻² Ω/m
Each bugle needs two wire, phase and ground
The total wire resistance is
R_total = 2 R
R_total = 17.87 10⁻² Ω
Let's look for the relationship between the resistance of the bugle and the wire
R_sp / R_total = 8 / 17.87 10⁻²
R_sp / R_total = 44.8
The resistance of the speaker wire can be calculated using the formula for the resistance of a wire, taking into account the resistivity of copper, the length and thickness of the wire, and whether a single or pair of wires is used.
The question is asking you to find the minimum resistance of a copper wire given its diameter and length, plus the resistance of the speaker it's connected to. Resistance of a wire is calculated using the formula R=ρL/A, where R is the resistance, ρ (rho) is the resistivity of the material (in this case, copper), L is the length of the wire, and A is the cross-sectional area of the wire.
First, you need to find the area of the 0.51 mm diameter wire. The area (A) of a wire is given by the formula π(d/2)^2 where d is the diameter of the wire. After calculating the area, use the formula R=ρL/A to calculate the resistance. For copper wire at 20°C, ρ is approximately 1.68 × 10^-8 Ω·m. Substituting these values into the formula will give you the resistance of the wire in ohms.
Note: you may need to consider whether you have just a single wire or a pair, since two wires are typically required to connect a speaker. If a pair is used, each wire will carry half the current, which affects the total resistance.
#SPJ12
Answer:
Explanation:
In this case, power is the rate of transferring heat per unit time:
The heat is given by the formula of the latent heat of fusion, since the ice is melting.
Here m is the ice's mass and is the heat of fusion of ice. Recall that one day has 86400 seconds. Replacing (2) in (1) and solving:
To solve this problem it is necessary to apply to the concepts related to energy conservation. For this purpose we will consider potential energy and kinetic energy as the energies linked to the body. The final kinetic energy is null since everything is converted into potential energy, therefore
Potential Energy can be defined as,
Kinetic Energy can be defined as,
Now for Conservation of Energy,
Therefore the highets position the car reaches above the bottom of the hill is 40.02m
Answer:
f = 113 Hz
Explanation:
In order to have maximum power transferred from the driving source, as the RMS voltage doesn´t depends on frequency, the current I must be maximum.
This condition is met when the circuit behaves a purely resistive, as the impedance is at a minimum.
Such condition is known as resonance, and it satisfies the following equation:
XL = XC ⇒ ω₀ * L = 1 / ω₀*C, where ω₀, is the angular frequency at resonance.
Solving for ω₀, we have:
ω₀ = 1/√LC = 1/√200*10⁻3 H* 10⁻6F = 707 rad/sec
As we need to find the frequency (in cycles/sec), we need to convert from angular frequency to frequency, as follows:
ω₀ = 2*π*f₀ ⇒ f₀ = ω₀ / 2*π = 707 rad/sec / 2*π rad = 113 Hz