Calculate the de Broglie wavelength of an electron and a one-ton car, both moving with speed of 100 km/hour. Based on your calculation could you predict which will behave like a "quantum particle" and why. Please explain each step in words and detail.

Answers

Answer 1
Answer:

Answer :

(a). The wavelength of electron is 26.22 μm.

(b).The wavelength of car is 2.38*10^(-38)\ m

Explanation :

Given that,

Speed = 100 km/hr

Mass of car = 1 ton

(a). We need to calculate the wavelength of electron

Using formula of wavelength

\lambda_(e)=(h)/(p)

\lambda_(e)=(h)/(mv)

Put the value into the formula

\lambda_(e)=(6.63*10^(-34))/(9.1*10^(-31)*100*(5)/(18))

\lambda=0.00002622

\lambda=26.22*10^(-6)\ m

\lambda=26.22\ \mu m

(II).  We need to calculate the wavelength of car

Using formula of wavelength again

\lambda_(e)=(6.63*10^(-34))/(1000*100*(5)/(18))

\lambda=2.38*10^(-38)\ m

The wavelength of the electron is greater than the dimension of electron and the wavelength of car is less than the dimension of car.

Therefore, electron is quantum particle and car is classical.

Hence, (a). The wavelength of electron is 26.22 μm.

(b).The wavelength of car is 2.38*10^(-38)\ m.


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Write down the DE of motion of a particle moving under the influence of gravity and experiencing a resistive force. .

Answers

Answer:

The DE will be (d^2x)/(dt^2)-(k)/(m)(dx)/(dt)-g=0

Explanation:

We have to find differential equation under the influence of gravity and experiencing a resistive force

Let an object of mass m falling under the influence of gravity

So the force experience under gravity =mg

Le the a resistive force of magnitude kv opposes this gravity force, here k is constant and v is velocity.

So net force F_(NET)=mg-kv-----eqn 1

F_(NET)=ma

So ma=mg-kv

We know that velocity is rate of change of position so v=(dx)/(dt), and acceleration is rate of change of velocity so a=(d^2x)/(dt^2)

Putting all these value in eqn 1

m(d^2x)/(dt^2)=mg-k(dx)/(dt)

(d^2x)/(dt^2)-(k)/(m)(dx)/(dt)-g=0

A toy airplane is flying at a speed of 6 m/s with an acceleration of 0.3 m/s2How fast is it flying after 4 seconds?
A. 5.7 m/s
B. 2.6 m/s
C. 13.9 m/s
D. 7.2 m/s
SUBMIT

Answers

Answer:

D

Explanation:

0.3=v-6/4

make v the subject

v=7.2ms^2

The word acid comes from the Latin word

Answers

Hi :)

The word acid comes from the Latin word acere, which means sour

Hope this helps!
It is acere but for future reference you can search of definition press more and google tells you its origin

Let A be the last two digits, and let B be the last three digits, and the C be the sum of the last 4 digits of your 8-digit student ID. (Example: For 20245347, A = 47, B = 347, and C = 19) A train moves at an average speed of (23.0 + A) m/s for (250.0 + B) seconds and then at an average speed of (45.0 + C) m/s for (800.0 + B) seconds. Determine the average speed for the entire time in meters per second (m/s). Round your final answer to 3 significant figures.

Answers

Answer:

66.053m/s

Explanation:

A = 47

B = 347

C = 19

Train moves at

(23 + A)m/s

= 23 + 47 = 60m/s

At (250.0+B) seconds

250.0+347 =

547 seconds

Distance d,

= 70 x 597

= 41790

It also moves at

(45.0 + c)

= 45 + 19

= 64m/s

Time = 800 + B

= 800 + 347

= 1147

Distance,

= 64 x 1147

= 73408m

Total distance,

= 73408 + 41790

= 115,198

Total time,

= 597 + 1147

= 1744

Average speed,

= Total distance / total time

= 115198/1174

= 66.053m/s

Final answer:

The average speed over the entire time can be calculated by first finding the distances the train travels over both periods, then finding the total distance and the total time, and finally dividing the total distance by the total time. The value must be rounded to three significant figures.

Explanation:

You can find the average speed of the train over the full-time interval by dividing the total distance travelled by the total time. To begin with, you would have to find the distances the train covered during both periods.

  1. The distance (D1) it travelled during the first period can be found by multiplying the average speed (23.0 + A) by the time (250.0 + B).
  2. The distance (D2) it travelled during the second period can be calculated by multiplying the average speed (45.0 + C) by the time (800.0 + B).

Then you add D1 and D2 to get the total distance (TD). This will be (D1 + D2). The total time (TT) will be found by adding both time intervals, which means it equals (250.0 + B) + (800.0 + B). You then divide the total distance by the total time to get the average speed, i.e., TD/TT. Lastly, round the average speed to 3 significant figures.

Learn more about Average Speed here:

brainly.com/question/17661499

#SPJ3

Consider three drinking glasses. All three have the same area base, and all three are filled to the same depth with water. Glass A is cylindrical. Glass B is wider at the top than at the bottom, and so holds more water than A. Glass C is narrower at the top than at the bottom, and so holds less water than A. In which glass is the pressure on the base greatest liquid pressure at the bottom?a. Glass Ab. Glass B
c. Glass C
d. All three have equal non-zero pressure at the bottom.
e. All three have zero pressure at the bottom.

Answers

Answer:

d

Explanation:

Pressure of the fluid in any container is a function of density of the fluid in the container, and depth of the fluid.

The static pressure of fluid in a container with depth h is given by:

P = p * g* h

Where p : density of fluid

g: gravitational constant 9.81 m/s^2

h : depth of the fluid

Since, all the glasses filled have same Area base, same depth and same density of fluid and g is constant. The pressure at the bottom of each drinking glass is equal for all cases. As supported by the relationship given above.  

A construction foreman exerts 1300 Newtons of force trying to move a 1200-kg block of concrete. How many Joules of work does he perform?

Answers

He does no work until the block starts to move ... an unlikely event.

If it ever does move, then the work he does is

                   (1300) x (the distance the block moves, in meters) .

The unit is 'joules.